Volumes of Revolution (Cambridge (CIE) AS Maths): Revision Note
Exam code: 9709
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Volumes of revolution around the x-axis
What is a volume of revolution around the x-axis?
- A solid of revolution is formed when an area bounded by a function - (and other boundary equations) is rotated 360° around the x-axis 
- A volume of revolution is the volume of this solid formed 

Example of a solid of revolution that is formed by rotating the area bounded by the function  , the lines 
  and  
 and the 
-axis 
 about the 
-axis
How do I find the volume of revolution around the x-axis?
- To find the volume of revolution created when the area bounded by the function - , the lines - and - , and the x-axis is rotated 360° about the x-axis use the formula 
 
- The formula may look complicated or confusing at first due to the y and dx - remember that y is a function of x 
- once the expression for y is substituted in, everything will be in terms of x 
 
- π is a constant so you may see this written either inside or outside the integral 
- This is not given in the formulae booklet - The formulae booklet does list the volume formulae for some common 3D solids – it may be possible to use these depending on what information about the solid is available 
 
How do I solve problems involving volumes of revolution around the x-axis?
- Visualising the solid created is helpful - Try sketching some functions and their solids of revolution to help 
 
- STEP 1 Square y - Do this first without worrying about π or the integration and limits 
 
- STEP 2 Identify the limits a and b (which could come from a graph) 
- STEP 3 Use the formula by evaluating the integral and multiplying by π - The answer may be required in exact form (leave in terms of π) - If not, round to three significant figures (unless told otherwise) 
 
 
- Trickier questions may give you the volume and ask for the value of an unknown constant elsewhere in the problem 
Worked Example

Examiner Tips and Tricks
- To help remember the formula note that it is only - - volume is 3D so you may have expected a cubic expression - If rotating a single point around the x-axis a circle of radius would be formed - The area of that circle would then be 
- Integration then adds up the areas of all circles between a and b creating the third dimension and volume 
 (In 2D, integration creates area by adding up lots of 1D lines)
 
 
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Volumes of revolution around the y-axis
What is a volume of revolution around the y-axis?
- A solid of revolution is formed when an area bounded by a function - (and other boundary equations) is rotated 360° around the y-axis 
- A volume of revolution is the volume of this solid formed 

Example of a solid of revolution that is formed by rotating the area bounded by the function  , the lines 
 and  
and the 
-axis 
 about the 
-axis
How do I find the volume of revolution around the y-axis?
- To find the volume of revolution created when the area bounded by the function - , the lines - and - , and the y-axis is rotated 360° about the y-axis use the formula 
 
- Note that although the function may be given in the form - it will first need rewriting in the form 
- This is not given in the formulae booklet 
How do I solve problems involving volumes of revolution around the y-axis?
- Visualising the solid created is helpful - Try sketching some functions and their solids of revolution to help 
 
- STEP 1 Rearrange - into the form - (if necessary) - This is finding the inverse function 
 
- STEP 2 Square x - Do this first without worrying about π or the integration and limits 
 
- STEP 3 Identify the limits c and d (which could come from a graph) 
- STEP 4 Use the formula by evaluating the integral and multiplying by π - The answer may be required in exact form (leave in terms of π) - If not, round to three significant figures (unless told otherwise) 
 
 
- Trickier questions may give you the volume and ask for the value of an unknown constant elsewhere in the problem 
Worked Example


Examiner Tips and Tricks
- Double check questions to ensure you are clear about which axis the rotation is around 
- Separating the rearranging of - into - and the squaring of x is important for maintaining accuracy - In some cases it can seem as though x has been squared twice - in the worked example above, x has been squared twice 
- but it needed to be – once as part of the rearranging, once as part of the volume formula 
 
 
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