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Structural Analysis of Molecules (HL) (HL IB Chemistry)

Revision Note

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Philippa

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Philippa

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Chemistry

Structural Analysis of Molecules

  • The chemists' toolkit includes a range of analytical techniques that enable the structure of compounds to be deduced

Summary table of analytical techniques

Technique Information provided
Mass spectrometry

Relative atomic mass

Isotopes

Relative molecular mass

Fragments in organic compounds

Structure of organic compounds

Nuclear magnetic spectroscopy Structure of organic compounds
Infrared spectroscopy

Types of covalent bonds

Functional groups

  • These techniques are rarely used in isolation, but together provide corroborating evidence for elucidating chemical information on newly discovered or synthetic compounds
  • Problem solving typically involves taking multiple pieces of spectroscopic data about the same unknown compound and coming up with a likely structure

Worked example

An unknown compound, X, of molecular formula,C4H8O, has the following MS, IR and 1H NMR spectra.

Mass spectrum of X

Mass spectrum of X

 

IR spectrum of X

IR spectrum of X

 

1H NMR spectrum of X

1H NMR spectrum of X

Deduce the structure of X using the information given and any other additional information in the Data booklet. For each spectrum assign as much spectroscopic information as possible.

Answer

Mass Spectrum (Section 22 of the data booklet)

  • The molecular ion peak is at m / z = 72, which corresponds to the relative molecular mass of C4H8O
    • Mr = (12 × 4) + (8 × 1) +(16) = 72
  • The large peak at  m / z = 43 could correspond to CH3CH2CH2+ or CH3CO+ indicating the loss of CH4O or C2H5 from X, that is (Mr - 43)
  • The peak at  m / z = 29 could correspond to CH3CH2+  indicating the loss of C2H3O from X, that is (Mr - 29)

IR Spectrum (Section 20 of the data booklet)

  • There is a strong absorption in the range 1700 - 1750 cm-1 which corresponds to C=O
  • This suggests an aldehyde or ketone is present
    • It cannot be an ester or a carboxylic acid as there is only one oxygen in the formula

1H NMR Spectrum (Section 21 of the data booklet)

  • The 1H NMR spectrum shows three protons environments
    • The peak around chemical shift 1.0 ppm could correspond to methyl protons on the end of a chain, -CH3
    • The peaks around chemical shift 2.2 - 2.7 ppm could correspond to a proton next to a carbonyl group, R-CH2-CO-
  • The peak splitting is a quartet, singlet and triplet
    • A quartet and triplet in the same spectrum usually corresponds to an ethyl group, CH3CH2, following the n+1 rule
    • The singlet indicates an isolated proton environment

Overall structure

butanone-displayed-formula

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Philippa

Author: Philippa

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener.