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Colour in Transition Metal Complexes (HL) (HL IB Chemistry)

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Colour in Transition Metal Complexes

  • Transition elements form coloured complexes when they bond with ligands
  • Ligands are molecules, such as ammonia and water, or ions, such as ammonium or chloride ions that form a coordinate bond to a central metal ion

Crystal Field Theory (CFT)

  • The crystal field theory is a model based on electrostatic point charges and is used to explain colour in transition metal compounds
  • In a transition metal atom, the five orbitals that make up the d-subshell all have the same energy
    • The term for this is degenerate
  • However, when ligands are attached to a transition metal ion, the electric field formed by the lone pairs of electrons on the ligands repel the electrons in the d-subshell causing the d-orbitals to split in energy
  • The dative bonding from the ligands causes the five d orbitals to split into two sets
  • These two sets are not equal in energy and are described as being non-degenerate orbitals

The effect of ligands on the d-orbitals of a central transition metal ion

Diagram showing how ligands cause the d-orbitals to split into non-degenerate orbitals

Upon bonding to ligands, the d orbitals of the transition element ion split into two non-degenerate sets of orbitals

  • The central metal ion in a complex has five d-orbitals for the electrons

Diagram showing the shapes and orientation of the five d-orbitals

the-five-d-orbitals

The names of the different d-orbitals are based on their position in the x, y and z planes. The shapes are shown here for reference only. You are not required to know the shapes of d-orbitals in the exam

Perception of colour

  • Most transition metal compounds appear coloured
  • This is because the difference in energy between the non-degenerate orbitals allows electrons in the lower energy orbitals to be promoted into the higher energy orbitals
    • A larger splitting of the d-orbitals means that more energy is required to promote an electron
  • This happens when the complex absorbs light energy with a wavelength corresponding to the energy gap between the orbitals
    • With a larger splitting of d-orbitals, light of a shorter wavelength and higher frequency is absorbed
  • The amount of energy absorbed relates to certain parts of the visible electromagnetic spectrum
  • The colour that is seen is complementary to the colour that is absorbed, i.e. it is made up of the parts of the visible spectrum that aren’t absorbed
    • For example, a green compound will absorb all frequencies of the spectrum apart from green light, which is transmitted

The colour wheel

Diagram showing the colour wheel

The colour wheel shows complementary colours in the visible light region of the electromagnetic spectrum

  • Complementary colours are any two colours which are directly opposite each other in the colour wheel
    • For example, the complementary colour of red is green and the complementary colours of red-violet are yellow-green

Exam Tip

  • The colour wheel is given section 15 in the Data booklet, so there is no need to learn it
  • There are different splitting patterns possible but you are not required to know different splitting patterns or their relation to coordination number.

Absorption of light

  • When white light passes through a solution of aqueous nickel(II) sulfate, an electron in the lower energy d-orbitals is excited and jumps up into the higher energy d-orbitals
  •  A photon of red light is absorbed and light of the complementary colour (green) is transmitted
  • This is why nickel(II) sulfate solution appears green
  • The energy of the separation is Δcorresponding to a wavelength of about 647 - 700 nm

Illustration of the electron promotion process in Nickel(II)

electron-promotion-in-niii-complexDuring electron promotion of a Ni(II) complex, an electron jumps from a dx orbital to a dx2-y2 orbital when light is shone on the solution

Worked example

Titanium(III) sulfate forms a purple aqueous solution. Estimate the wavelength of light absorbed by this solution, using Section 15 of the data booklet.

 

Answer:

  • Titanium(III) sulfate appears purple
  • The complementary colour of yellow is absorbed 
  • The wavelength range of the complementary colour is 575 - 585 nm

Wavelength, frequency and energy

  • A greater splitting of the d-orbitals results in a larger energy gap, Δ
  • This means that more energy is needed to promote an electron from a lower to a higher energy orbital
  • Therefore, the light needs to have:
    • Shorter wavelength
    • Higher frequency
  • The equations relating wavelength, frequency and energy are:
speed of light
(3.00 x 108 m s-1)

=
frequency
(s-1)

x
wavelength
(m)
c   f   λ
         
energy
(J)

=
Planck's constant
(6.63 x 10-34 J s)

x
frequency
(s-1)
E   h   f

  • These are given in Section 1 of the Data Booklet, so there is no need to memorise them, although you do need to how to manipulate them and what the units are
  • The constants are listed in Section 2 of the data Booklet

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Richard

Author: Richard

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.