Tree Diagrams with Conditional Probability (OCR A Level Maths A): Revision Note

Exam code: H240

Tree diagrams with conditional probability

How do I find conditional probabilities problems from tree diagrams?

  • Interpreting questions in terms of AND (begin mathsize 16px style intersection end style), OR (union) and complement ( ‘ )

  • Condition probability may now be involved too - “given that” ( | )

  • This makes it harder to know where to start and how to complete the probabilities on a tree diagram

    • e.g. If given, possibly in words, P left parenthesis B vertical line A right parenthesis then event A has already occurred so start by looking for the branch event A in the 1st experiment, and then  would be the branch for event  in the 2nd experiment

  • Similarly, begin mathsize 16px style straight P left parenthesis B vertical line A right parenthesis end style would require starting with event “bold italic n bold italic o bold italic t bold space bold italic A  in the 1st experiment and event B in the 2nd experiment

UclzomJM_3-2-3-fig1-tree-setup

 

  • The diagram above gives rise to some probability formulae you will see in the next revision note

  • bold P bold left parenthesis bold italic B bold vertical line bold italic A bold right parenthesis (“given that”) is the probability on the branch of the 2nd experiment

  • However, the “given that” statement bold P bold left parenthesis bold italic A bold vertical line bold italic B bold right parenthesis is more complicated and a matter of working backwards

    • from Conditional Probability,  straight P left parenthesis A vertical line B right parenthesis equals fraction numerator straight P left parenthesis A intersection B right parenthesis over denominator straight P left parenthesis B right parenthesis end fraction

    • from the diagram above, P left parenthesis B right parenthesis equals P left parenthesis A intersection B right parenthesis plus P left parenthesis A apostrophe intersection B right parenthesis

    • leading to  bold P bold left parenthesis bold italic A bold vertical line bold italic B bold right parenthesis bold equals fraction numerator bold P bold left parenthesis bold A bold intersection bold B bold right parenthesis over denominator bold P bold left parenthesis bold A bold intersection bold B bold right parenthesis bold plus bold P bold left parenthesis bold A bold apostrophe bold intersection bold B bold right parenthesis end fraction

    • This is quite a complicated looking formula to try to remember so use the logical steps instead – and a clearly labelled tree diagram!

Worked Example

The event F has a 75% probability of occurring.

The event W follows event F, and if event F has occurred, event W has an 80% chance of occurring.

It is also known that straight P left parenthesis F apostrophe intersection W right parenthesis space equals space 0.15 .

Find

(i) straight P left parenthesis W vertical line F apostrophe right parenthesis

(ii) straight P left parenthesis F vertical line W apostrophe right parenthesis

(iii) the probability that event F didn’t occur, given that event Wdidn’t occur.

3-2-3-fig2-we-solution-part-1
2ACeFam__3-2-3-fig2-we-solution-part-2

Examiner Tips and Tricks

  • It can be tricky to get a tree diagram looking neat and clear first attempt – it can be worth drawing a rough one first, especially if there are more than two outcomes or more than two events; do keep an eye on the exam clock though!

  • Always worth another mention – tree diagrams make particularly frequent use of the result begin mathsize 16px style straight P left parenthesis not space A right parenthesis equals 1 minus straight P left parenthesis A right parenthesis end style

  • Tree diagrams have built-in checks

    • the probabilities for each pair of branches should add up to 1

    • the probabilities for each outcome of combined events should add up to 1

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