Points of Intersection (AQA Level 3 Mathematical Studies (Core Maths)): Revision Note

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Updated on

Graphical Solutions

How do I use graphs to solve linear simultaneous equations?

  • The point of intersection of the two graphs is the solution to the pair of simultaneous equations

  • Plot both equations on the same set of axes using straight line graphs y equals m x plus c

  • Find where the lines intersect (cross)

    • The x and y solutions to the simultaneous equations are the x and y coordinates of the point of intersection

  • For example:

    • To solve 2 x minus y equals 3 and 3 x plus y equals 7 simultaneously, first plot them both on the same graph as shown below

    • Find the point of intersection: (2, 1)

    • The solution is therefore x equals 2 and y equals 1

Points of intersection of 2x-y=3 and 3x+y=7

How do I use graphs to solve simultaneous equations where one is a quadratic?

  • Plot both functions on the same graph, and find their points of intersection

  • For example:

    • To solve y equals x squared plus 4 x minus 12 and y equals 1 simultaneously, first plot them both on the same graph as shown below

      • Find the points of intersection: (-6.1, 1) and (2.1, 1) to 1 decimal place

        • Solutions using graphs will often only be approximate

      • The solutions are therefore approximately x equals negative 6.1, y equals 1 and x equals 2.1, y equals 1

        • There are two pairs of x, y solutions as there are two points of intersection

        • To find the exact solutions, you could use algebra instead

Points of intersection of y = x^2 + 4x - 12 and y=1

How do I use graphs to solve other equations?

  • The solution to a pair of equations is their point of intersection

  • Solutions of straight f open parentheses x close parentheses equals 0 are where the graph of y equals straight f open parentheses x close parentheses crosses the x-axis

  • If asked to use the graph of y equals straight f open parentheses x close parentheses to solve a different equation

    • Rearrange the equation to be solved into straight f open parentheses x close parentheses equals straight g open parentheses x close parentheses, where g open parentheses x close parentheses is a different equation and both straight f open parentheses x close parentheses and straight g open parentheses x close parentheses can be drawn

    • The solutions are the x-coordinates of where straight f open parentheses x close parentheses and straight g open parentheses x close parentheses intersect

  • For example:

    • If given the curve for y equals x cubed plus 2 x squared plus 1 and asked to solve x cubed plus 2 x squared minus x minus 1 equals 0 then:

      • Rearrange x cubed plus 2 x squared minus x minus 1 equals 0 to x cubed plus 2 x squared plus 1 equals x plus 2

      • Draw the line y equals x plus 2 on the curve x cubed plus 2 x squared plus 1

      • Read the x-values of where the line and the curve cross
        In this case there would be 3 solutions
        Approximately x equals negative 2.2, x equals negative 0.6 and x equals 0.8

Points of intersection of y=x^3 + 2x^2 + 1 and y=x+2

Examiner Tips and Tricks

  • When solving a pair of linear simultaneous equations, remember to give an x and a y value for your final answer

  • Questions may use other variables, e.g. h and t to model height and time

    • Make sure you are certain which variable is measured on which axis

Worked Example

Two electricians, Paul and Claire, charge an hourly rate and a call-out fee (the price to travel to a job) to their customers.

Paul charges £85 per hour, with a £10 call-out fee.

Claire charges £54 per hour, with a £50 call-out fee.

(a) Plot a line for each electrician showing the fee charged to customers for jobs lasting between 0 and 2 hours.

Show the number of hours on the x-axis, and the fee on the y-axis.

For Paul, the y-intercept will be 10, as £10 is charged before a job is started (call-out fee)
The gradient for Paul will be 85, as £85 is charged per hour
The easiest points to plot are (0,10) and (1,95), and then join these to form a straight line

For Claire, the y-intercept will be 50, and the gradient will be 54
Plot the points (0,50) and (1,104) and join them to form a straight line

Label the lines you plot

Two linear graphs; y=85x+10 and y=54x+50

(b) It is suggested that Paul is cheaper for a "short job" and Claire is cheaper for longer jobs.

Use your graph to find an approximate upper limit for the length of a "short job".

The point of intersection of the lines is where Paul and Claire charge the same amount in total, for the same length job

Read the point of intersection from the graph

Finding x coordinate of intersection of y=85x+10 and y=54x+50, approximately x=1.3

For smaller values of x than this, Paul's line is below Claire's, so Paul is cheaper

A short job is up to approximately 1.3 hours

The true value is 1.2903... hours that can be found using algebra
The question does not require you to find this however, it only asks you to approximate using the graph

Worked Example

Martina is using a graphical method to solve 2 x cubed minus 5 x squared minus 6 x plus 9 equals 0.

She draws the graph of y equals 2 x cubed minus 5 x squared and a straight line graph on the same grid.

Here is the graph of y equals 2 x cubed minus 5 x squared.

Graph of y = 2x^3 - 5x^2

Complete her method to solve 2 x cubed minus 5 x squared minus 6 x plus 9 equals 0.

Rearrange 2 x cubed minus 5 x squared minus 6 x plus 9 equals 0 so that one side of the equation features the graph that has been plotted, 2 x cubed minus 5 x squared

table row cell 2 x cubed minus 5 x squared minus 6 x plus 9 end cell equals 0 row cell 2 x cubed minus 5 x squared end cell equals cell 6 x minus 9 end cell end table

This shows that the solutions to 2 x cubed minus 5 x squared minus 6 x plus 9 equals 0 are the same as the solutions to table row cell 2 x cubed minus 5 x squared end cell equals cell 6 x minus 9 end cell end table

The solutions to table row cell 2 x cubed minus 5 x squared end cell equals cell 6 x minus 9 end cell end table can be found by plotting the cubic y equals 2 x cubed minus 5 x squared, which is already plotted, and the straight line, y equals 6 x minus 9, and then finding their points of intersection

As we are only solving an equation in terms of x, we only need the x-coordinates

intersection points of 2x^3 - 5x^2 and 6x-9 at x=-1.5, 1, and 3

bold italic x bold equals bold minus bold 1 bold. bold 5
bold italic x bold equals bold 1
bold italic x bold equals bold 3

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Jamie Wood

Author: Jamie Wood

Expertise: Maths Content Creator

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.