Velocity & Acceleration (AQA Level 3 Mathematical Studies (Core Maths)): Revision Note

Exam code: 1350

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Updated on

Distance-time Graphs

How do I use a distance-time graph?

  • Distance-time graphs show the distance travelled at different times

    • Distance is on the vertical axis

    • Time is on the horizontal axis 

  • The gradient of the graph is the speed

    • speed space equals space fraction numerator distance space travelled over denominator time end fraction space equals space rise over run

    • The units for speed are usually metres per second

      • Or m/s or ms-1

  • The steeper the line or curve, the faster the object is moving

    • Lines or curves with positive gradients represent objects moving away from the start point

    • Lines or curves with negative gradients represent objects moving towards the start point

    • Lines that are horizontal represent rest

      • The object is stationary (not moving)

Two straight lines, one with gradient steeper than the other. Steeper slope means larger speed, shallower slope means smaller speed.
  • Remember that the gradient of a distance-time graph is equal to the speed

    • If the gradient decreases (becomes less steep) the speed is decreasing

    • If the gradient increase (becomes more steep) the speed is increasing

Decreasing slope means decreasing speed, increasing slope means increasing speed.

How do I work out the overall average speed?

  • The overall average speed for the whole journey is fraction numerator total space distance space travelled over denominator total space time end fraction

  • The total time includes any rests

  • This can be applied to journeys with multiple parts

How do I work with curved distance-time graphs?

  • The gradient of a linear distance-time graph is constant

    • This means the speed is constant throughout

    • It is equal to the average speed for the journey

  • A curved distance-time graph has a gradient which is constantly changing

    • This means the speed is constantly changing

  • The gradient can be estimated at a point to find the speed at that point in time

    • This is done by drawing a tangent at that point and finding its gradient

  • The gradient can also be estimated between two points (using a chord) to find the average speed between those two points

  • See Gradients & Rates of Change for how to do this

A curve with a tangent drawn on it, and calculating the gradient of the tangent using rise over run
  • If a curve has a point where the tangent is horizontal (a stationary point) it may be referred to as "instantaneously at rest"

    • At a stationary point, the object will be changing direction

    • This is because the gradient (speed) will be changing from positive to negative, or vice-versa

Worked Example

The distance-time graph below shows the distance of a particle from its starting point during three different stages of motion.

distance time graph for a journey in three stages. A curved section, a negative gradient linear section, and a constant (gradient=0) section

(a) Describe the motion of the particle for each of the three stages. You do not need to perform any calculations.

Between A and B, the gradient of the graph is decreasing, therefore the speed is decreasing

Between A and B, the particle is moving away from its starting point, and its speed is decreasing

Between B and C the gradient is negative, so it is moving back towards its starting point
The line is linear, so the gradient, and therefore speed, is constant

Between B and C the object is moving back towards its starting point at a constant speed

Between C and D the distance from the starting point does not change

Between C and D the object is at rest

(b) Estimate the speed of the particle at 3 seconds.

Draw a tangent to the graph at time 3 seconds
A tangent should touch the curve, not intersect it

distance time graph with tangent drawn

Select two points on the tangent line and find the gradient of the tangent

tangent to distance time graph, with two coordinates on the tangent; (0, 2.4) and (6, 14)

gradient space equals fraction numerator 14 minus 2.4 over denominator 6 minus 0 end fraction equals fraction numerator 11.6 over denominator 6 end fraction equals 1.9333...

The gradient of the tangent is equal to the speed at that point in time

Round the answer to 3 significant figures, and add the units

At 3 seconds, the speed is 1.93 ms-1 (to 3.s.f)

(c) Find the average speed between point B and point D.

Average speed is found by: fraction numerator Total space distance space travelled over denominator Total space time end fraction

Apply this between points B and D

The distance at point B is 12 m from the start, and at point D the distance is 6 m from the start.

The time elapsed between B and D is 7 seconds (14 - 7)

Average space speed space equals space fraction numerator 12 minus 6 over denominator 7 end fraction equals 0.8571428571...

Round to 3 significant figures and write the units

The average speed between B and D is 0.857 ms-1

Velocity-time Graphs

What is a velocity-time graph?

  • Velocity describes the speed and direction of an object

    • E.g. A velocity of -3 ms-1 is equivalent to a speed of 3 ms-1

  • You may see speed-time graphs or velocity-time graphs

    • The direction that an object is travelling in does not matter for a speed-time graph

    • Speed-time graphs and velocity-time graphs follow the same principles

  • Velocity-time graphs show the velocity of an object at different times

    • Velocity is on the vertical axis

    • Time is on the horizontal axis 

  • The gradient of the graph is the acceleration

    • acceleration space equals space fraction numerator change space in space velocity over denominator time end fraction space equals space rise over run

    • The units for acceleration are usually metres per second squared

      • Or m/s2 or ms-2

  • The steeper the line or curve, the faster the object is accelerating

    • Lines or curves with positive gradients above the x-axis, represent objects increasing their velocity (accelerating)

    • Lines or curves with negative gradients above the x-axis, represent objects decreasing their velocity (decelerating)

Two lines with different gradients, one positive, one negative. Positive gradient has increasing velocity, negative gradient has decreasing velocity.
  • Lines that are horizontal represent constant speed

  • The object is at rest at points on the horizontal axis (where speed is zero)

A velocity time graph with a positive gradient meaning constant acceleration, horizontal line showing constant velocity, and negative gradient showing constant deceleration

How do I work with curved velocity-time graphs?

  • The gradient of a linear velocity-time graph is constant

    • This means the acceleration is constant throughout

    • It is equal to the average acceleration for the journey

  • A curved velocity-time graph has a gradient which is constantly changing

    • This means the acceleration is constantly changing

Graphs showing constant velocity (horizontal), increasing velocity (positive gradient, linear), increasing acceleration (positive quadratic), and decreasing acceleration (negative quadratic)
  • The gradient can be estimated at a point to find the acceleration at that point in time

    • This is done by drawing a tangent at that point and finding its gradient

  • The gradient can also be estimated between two points (using a chord) to find the average acceleration between those two points

  • See Gradients & Rates of Change for how to do this

Worked Example

A skydiver jumps from a plane and their velocity is tracked for 10 seconds.

A graph of her motion is shown below.

2-3-properties-of-motion-graphs-we-qn_edexcel-al-physics-rn

(a) Use the graph to estimate her acceleration at 2.5 seconds.

Draw a tangent to the graph at time 2.5 seconds
A tangent should touch the curve, not intersect it

velocity time graph (curve) with a tangent drawn at t=2.5

Select two points on the tangent line and find the gradient of the tangent

tangent to velocity time graph, with marked coordinates (0,8) and (7.5,60)

gradient space equals fraction numerator 60 minus 8 over denominator 7.5 minus 0 end fraction equals fraction numerator 52 over denominator 7.5 end fraction equals 6.9333...

The gradient of the tangent is equal to the acceleration at that point in time

Round the answer to 3 significant figures and add the units

At 2.5 seconds, the acceleration is 6.93 ms-2 (to 3.s.f)

(b) Use the graph to estimate her average acceleration between 0 and 10 seconds.

The average acceleration is given by fraction numerator total space change space in space speed over denominator total space time end fraction between the two points

At 0 seconds, the velocity is zero, and the time is zero
At 10 seconds, the velocity is 50 ms-1 and the time elapsed is 10 seconds

Average space acceleration space equals fraction numerator 50 minus 0 space over denominator 10 end fraction equals 5

The average acceleration between 0 and 10 seconds is 5 ms-2

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Jamie Wood

Author: Jamie Wood

Expertise: Maths Content Creator

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.