Mutations (College Board AP® Biology): Exam Questions

54 mins23 questions
1a1 mark

Describe what is meant by the term gene mutation.

1b1 mark

The table shows the DNA base sequence of part of a gene, as well as the same part of the gene after an insertion mutation occurred.

Original gene:

T A T A G T C T T

Mutated gene:

T A T A G T C C T T

Describe what is meant by an insertion mutation.

1c1 mark

Draw a circle on the table in part b) to show where an insertion mutation has occurred.

1d1 mark

Explain why a point mutation, in which one base is substituted for another, is likely to have little or no impact on the protein that is produced.

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2a1 mark

Some mutations lead to the introduction of a stop codon early in the nucleotide base sequence. As a result, a protein will be synthesized incorrectly.

Identify one other possible outcome of a gene mutation.

2b1 mark

Antibiotic resistance develops as a result of mutations in bacterial DNA.

Explain why these mutations are maintained in the population over time.

2c1 mark

Describe how bacteria transfer mutations within the population.

2d1 mark

Justify why genetic diversity in a bacterial population would be reduced if it were exposed to an antibiotic.

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3a1 mark

Describe how a mutation in nucleotide bases may result in the formation of a non-functional protein.

3b1 mark

Identify a human disease that occurs as a result of a chromosome mutation.

3c1 mark

Explain why a chromosome mutation usually results in more significant phenotype changes than a gene mutation.

3d1 mark

Explain why triploidy results in sterility (inability to produce offspring).

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4a1 mark

In certain regions where malaria is widespread, individuals who carry one copy of the sickle cell allele (Hbᵗˢ) and one copy of the normal allele (Hbᴬ) are more likely to survive than individuals with either two normal alleles (Hbᴬ/Hbᴬ) or two sickle cell alleles (Hbᵗˢ/Hbᵗˢ). This is an example of heterozygote advantage.

A study of two populations showed the following genotype frequencies.

Table 1: Genotype frequencies in a population exposed to malaria compared to a population free of malaria.

Genotype

Population A (with malaria)

Population B (no malaria)

Hbᴬ/Hbᴬ

0.30

0.95

Hbᴬ/Hbᵗˢ

0.60

0.05

Hbᵗˢ/Hbᵗˢ

0.10

0.00

Describe what is meant by the term heterozygote advantage.

4b1 mark

Use the data to explain how natural selection is acting on the sickle cell allele in Population A.

4c1 mark

Predict what would happen to the frequency of the Hbᵗˢ allele in Population A if malaria were eliminated.

4d1 mark

Justify your prediction in part (c).

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1a3 marks

Information flow in cells can be regulated by various mechanisms.

Describe the role of THREE of the following in the regulation of protein synthesis:

  • RNA splicing

  • repressor proteins

  • methylation

  • siRNA 

1b4 marks

Information flow can be altered by mutation. Describe THREE different types of mutations and their effect on protein synthesis.

1c4 marks

Identify TWO environmental factors that increase the mutation rate in an organism, and discuss their effect on the genome of the organism.  

1d1 mark

Epigenetics is the study of heritable changes in the phenotype caused by mechanisms other than changes in the DNA sequence. Describe ONE example of epigenetic inheritance. 

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2a2 marks

The table below shows the amino acid sequence of the carboxyl-terminal segment of a conserved polypeptide from four different, but related, species. Each amino acid is represented by a three-letter abbreviation, and the amino acid residues in the polypeptide chains are numbered from the amino end to the carboxyl end. Empty cells indicate no amino acid is present. 

 

Relative Amino Acid Position

Species 

1

2

3

4

5

6

7

8

9

10

I

Val

His

Leu

Val

Glu

Glu

His

Val

Glu

His

II

Val

His

Leu

Lys

Glu

Glu

His

Val

Glu

His

III

Val

His

Leu

Val

Glu

Glu

His

Val

 

 

IV

Val

His

Leu

Val

Arg

Trp

Ala

Cys

Met

Asp

Assuming that species I is the ancestral species of the group, explain the most likely genetic change that produced the polypeptide in species II and the most likely genetic change that produced the polypeptide in species III. 

2b2 marks

Predict the effects of the mutation on the structure and function of the resulting protein in species IV. Justify your prediction.

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3a2 marks

Gibberellin is the primary plant hormone that promotes stem elongation. GA 3-beta-hydroxylase (GA3H) is the enzyme that catalyzes the reaction that converts a precursor of gibberellin to the active form of gibberellin. A mutation in the GA3H gene results in a short plant phenotype. When a pure-breeding tall plant is crossed with a pure-breeding short plant, all offspring in the F1 generation are tall. When the F1 plants are crossed with each other, 75 percent of the plants in the F2 generation are tall and 25 percent of the plants are short.

qp3-2017-frq-ap-biology

Figure 1. The universal genetic code

The wild-type allele encodes a GA3H enzyme with alanine (Ala), a nonpolar amino acid, at position 229. The mutant allele encodes a GA3H enzyme with threonine (Thr), a polar amino acid, at position 229. Describe the effect of the mutation on the enzyme and provide reasoning to support how this mutation results in a short plant phenotype in homozygous recessive plants.

3b1 mark

Using the codon chart provided, predict the change in the codon sequence that resulted in the substitution of alanine for threonine at amino acid position 229.

3c1 mark

Describe how individuals with one (heterozygous) or two (homozygous) copies of the wild-type GA3H allele can have the same phenotype.

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4a1 mark

Table 1. The data show the growth of haploid Saccharomyces cerevisiae yeast strains on media that differ in amino acid content. A plus sign (+) indicates that the yeast strains grow, and a minus sign (—) indicates that the strains do not grow.

 

 

STRAINS

 

MEDIUM

Wild Type

Mutant 1

Mutant 2

Treatment I

All amino acids present

+

+

+

Treatment II

No amino acids present

+

Treatment III

All amino acids present EXCEPT methionine

+

+

Treatment IV

All amino acids present EXCEPT leucine

+

+

The yeast Saccharomyces cerevisiae is a single-celled organism. Amino acid synthesis in yeast cells occurs through metabolic pathways, and enzymes in the synthesis pathways are encoded by different genes. The synthesis of a particular amino acid can be prevented by mutation of a gene encoding an enzyme in the required pathway.

A researcher conducted an experiment to determine the ability of yeast to grow on media that differ in amino acid content. Yeast can grow as both haploid and diploid cells. The researcher tested two different haploid yeast strains (Mutant I and Mutant 2), each of which has a single recessive mutation, and a haploid wild-type strain.

The resulting data are shown in Table 1.

Identify the role of treatment I in the experiment.

4b1 mark

Provide reasoning to explain how Mutant I can grow on treatment I medium but cannot grow on treatment III medium.

4c1 mark

Yeast mate by fusing two haploid cells to make a diploid cell. In a second experiment, the researcher mates the Mutant 1 and Mutant 2 haploid strains to produce diploid cells. Using the table provided, predict whether the diploid cells will grow on each of the four media. Use a plus sign (+) to indicate growth and a minus sign (−) to indicate no growth. 

 

 

STRAINS

 

MEDIUM

Wild Type

Mutant 1

Mutant 2

Diploid Cells
Produced by
Mating
Mutant 1 and
Mutant 2

Treatment I

All amino acids present

+

+

+

 

Treatment II

No amino acids present

+

 

Treatment III

All amino acids present EXCEPT methionine

+

+

 

Treatment IV

All amino acids present EXCEPT leucine

+

+

 

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