Interval Bisection (Edexcel International AS Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Updated on

Interval Bisection

What is interval bisection?

  • Interval Bisection means splitting an interval containing a root into two halves and using a sign change test to find out which half contains the root

  • For example, if straight f open parentheses 1 close parentheses less than 0 and straight f open parentheses 2 close parentheses greater than 0 and straight f open parentheses x close parentheses is continuous

    • Then a root must lie in open square brackets 1 comma space 2 close square brackets

    • Find the midpoint of the interval

      • x equals 1.5

    • Check the sign at the midpoint

      • For example, straight f open parentheses 1.5 close parentheses less than 0

    • Write down the half-interval that has the sign change

      • straight f open parentheses 1 close parentheses less than 0, straight f open parentheses 1.5 close parentheses less than 0 and straight f open parentheses 2 close parentheses greater than 0

      • So open square brackets 1.5 comma space 2 close square brackets has the sign change

  • The process can be repeated

    • For example, if straight f open parentheses 1.75 close parentheses greater than 0 then open square brackets 1.5 comma space 1.75 close square brackets contains the sign change

How do I use interval bisection to estimate a root?

  • If a root lies in the interval open square brackets 1 comma space 2 close square brackets, then the first approximation of the root, x subscript 1, is simply the midpoint

    • x subscript 1 equals 1.5

  • The second approximation, x subscript 2, requires using Interval Bisection once

    • For example, giving open square brackets 1.5 comma space 2 close square brackets

    • Then find the midpoint

      • x subscript 2 equals 1.75

    • And so on

Examiner Tips and Tricks

Read the question carefully to see if an approximation to the root is required, or the interval containing the root is required.

Worked Example

The equation x cubed plus x minus 16 equals 0 has a root in the interval open square brackets 2.1 comma space 2.9 close square brackets.

Use interval bisection to find an interval of width 0.2 that contains the root.

Find the width of the interval given in the question

2.9 minus 2.1 equals 0.8

Interval bisection halves the width
To get a width of 0.2, interval bisection is needed twice
Find the signs of the interval end-points

table row cell straight f open parentheses 2.1 close parentheses end cell equals cell negative 4.639 less than 0 end cell row cell straight f open parentheses 2.9 close parentheses end cell equals cell 11.289 greater than 0 end cell end table

Find the midpoint of the interval

x equals fraction numerator 2.1 plus 2.9 over denominator 2 end fraction equals 2.5

Find the sign of straight f open parentheses x close parentheses at x equals 2.5

straight f open parentheses 2.5 close parentheses equals 2.125 greater than 0

Find the new halved interval containing the sign change
Check the signs: straight f open parentheses 2.1 close parentheses less than 0, straight f open parentheses 2.5 close parentheses greater than 0 and straight f open parentheses 2.9 close parentheses greater than 0

open square brackets 2.1 comma space 2.5 close square brackets

Repeat the process
Find the midpoint of the interval

x equals fraction numerator 2.1 plus 2.5 over denominator 2 end fraction equals 2.3

Find the sign of straight f open parentheses x close parentheses at x equals 2.3

straight f open parentheses 2.3 close parentheses equals negative 1.533 less than 0

Find the new halved interval containing the sign change
Check the signs: straight f open parentheses 2.1 close parentheses less than 0, straight f open parentheses 2.3 close parentheses less than 0 and straight f open parentheses 2.5 close parentheses greater than 0

open square brackets 2.3 comma space 2.5 close square brackets

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.