Comprehension (AS & A Level) (AQA A Level Biology): Exam Questions

Exam code: 7402

4 hours18 questions
1a2 marks

Read the following passage.

Plants take in carbon dioxide through pores in their leaves called stomata. When stomata are open to allow gas exchange, water vapour can diffuse out of the leaf, meaning that most plants need to compromise between gas exchange and water conservation.

In desert regions, some plants use a form of photosynthesis known as CAM (Crassulacean Acid Metabolism). CAM plants keep their stomata closed during the day and open them at night to take in carbon dioxide. This carbon dioxide is stored in the form of organic acids inside vacuoles. During the day, the stored carbon is released and used in the Calvin cycle.

In contrast, most crop plants use C3 photosynthesis, in which carbon dioxide is taken up through stomata during the day. In C3 plants the enzyme rubisco fixes carbon dioxide in the first step of the Calvin cycle. When environmental temperatures rise, rubisco can bind with oxygen instead of carbon dioxide in a process known as photorespiration; this reduces the efficiency of photosynthesis.

Scientists are investigating ways to introduce CAM photosynthesis into crop plants such as rice. One technique used for this is known as CRISPR-Cas9. This method uses a guide RNA molecule that binds to a specific DNA sequence in the genome. The Cas9 enzyme then cuts the DNA at that site. New genes can be inserted into the break, or existing sequences can be removed or altered.

Use the information in the passage and your own knowledge to answer the following questions.

Describe how carbon is fixed during the Calvin cycle in C3 photosynthesis (paragraph 3).

1b3 marks

Suggest why photorespiration is more likely to occur in C3 plants when environmental temperatures rise (paragraph 3).

1c2 marks

Explain why the Calvin cycle needs to occur during the day in CAM plants, rather than at night when stomata are open (paragraph 2).

1d2 marks

Suggest why CAM plants are less likely to carry out photorespiration than C3 plants (paragraphs 2-3).

1e3 marks

Compare gene editing using CRISPR-Cas9 with traditional genetic engineering techniques (paragraph 4).

1f3 marks

Evaluate the introduction of CAM photosynthesis into crop plants (paragraph 4).

2a2 marks

Read the following passage.

The BRCA1 gene helps to regulate the cell cycle and is active in many healthy mammalian tissues. It codes for a protein that is involved in detecting damaged DNA. BRCA1 is often described as a tumour suppressor gene.

In non-dividing cells the BRCA1 gene is usually inactive. It is activated during cell division by a transcription factor called E2F1, which enters the nucleus during specific phases of the cell cycle.

In some forms of breast and ovarian cancer, the BRCA1 gene is no longer transcribed. This can occur even if the DNA sequence of the gene is unchanged. Researchers have found that in some tumour cells, the DNA near the BRCA1 promoter region is highly methylated, and the associated histone proteins lack acetyl groups.

A drug called Vorinostat, which belongs to a class of compounds known as histone deacetylase (HDAC) inhibitors, is being tested as a treatment for cancers in which BRCA1 is inactive. In one clinical trial involving 120 patients with breast cancer, Vorinostat restored BRCA1 gene expression in 68% of tumour samples. In a smaller group of patients with ovarian cancer, 54% showed a partial reduction in tumour size after receiving the drug. However, delivering Vorinostat effectively to all tumour cells remains a challenge.

Use the information in the passage and your own knowledge to answer the following questions.

Outline how the protein product of BRCA1 expression could suppress tumour formation (paragraph 1).

2b3 marks

Explain how transcription factor E2F1 could activate expression of the BRCA1 gene (paragraph 2).

2c2 marks

Describe the effects of methylation on gene expression (paragraph 3).

2d3 marks

Suggest how Vorinostat may act to reduce tumour development (paragraph 4).

2e4 marks

Evaluate the effectiveness of Vorinostat as a cancer treatment using the information provided (paragraph 4).

2f1 mark

Suggest why delivering drugs to tumour cells is challenging (paragraph 4).

3a4 marks

Read the following passage.

Nitrogen is an essential element in all living organisms. In aquatic ecosystems, nitrogen availability often limits plant growth, particularly in freshwater environments where nitrate concentrations are naturally low.

Aquatic plants have evolved various strategies to obtain nitrogen from their environment. Some species, such as water hyacinth, possess specialised root structures that can absorb both nitrate and ammonium ions directly from the water.

Recent research has investigated the growth of water hyacinth in nutrient-poor freshwater systems. Scientists compared the growth of plants in water with different nitrogen concentrations over a 28-day period. Plants grown in high-nitrogen conditions showed significantly greater biomass accumulation and darker green colouration in their leaves. Plants in low-nitrogen environments developed longer, more branched root systems compared to those in nitrogen-rich water. Analysis of gene expression revealed that genes coding for nitrogen transport proteins were expressed at higher levels in nitrogen-starved plants.

While water hyacinth can grow in nutrient poor environments, there are concerns about introducing the species into new freshwater systems, as this species can rapidly colonise water bodies and outcompete native plant species, potentially disrupting local ecosystems.

Nitrogen deficiency in aquatic plants can cause stunted growth and yellowing of leaves.

(i) Explain why nitrogen deficiency can reduce the growth of aquatic plants (paragraph 1).

(ii) Use your knowledge of transport across cell membranes to suggest how nitrate ions enter aquatic plant root cells (paragraph 2).

3b4 marks

The scientists found that genes coding for nitrogen transport proteins were more highly expressed in the roots of nitrogen-starved plants (paragraph 3).

Suggest how the expression of these genes in root cells could have been measured.

3c1 mark

Despite showing reduced biomass accumulation, the nitrogen-starved plants developed longer, more branched root systems than plants grown in nitrogen-rich water (paragraph 3).

Suggest one reasons for this.

3d3 marks

The scientists reported that the difference in biomass accumulation between the two groups was statistically significant (paragraph 3).

(i) Name an appropriate statistical test that the scientists could have used.

[1]

(ii) Explain why this test is appropriate.

[1]

(iii) When the scientists carried out the statistical test they found that the test value was higher than the critical value at a probability level of 0.05.

State what this means.

[1]

3e3 marks

Evaluate the potential benefits and risks of introducing water hyacinth into freshwater systems to improve nitrogen cycling (paragraph 4).

4a1 mark
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4b2 marks

Suggest the mechanism by which the defensive enzymes destroy bacterial pathogens (lines 9-10).

4c3 marks

A stimulus can result in the expression of genes.

Suggest how the signal proteins cause the expression of the defensive enzyme genes (lines 9-13).

4d3 marks

Pepper plants can transmit signal proteins both into the air and also through mycorrhizal networks (lines 10–14).

Suggest which method of signal protein transmission is more likely to be effective. Justify your answer.

4e2 marks

In pepper plants the largest increase in defensive enzyme secretion observed in response to the presence of the signal protein was 119.4 % (lines 19–20).

The rate of secretion of the defensive enzymes before the presence of signal protein was 500 µmol dm−3 g−1 hour−1.

Calculate the rate of secretion per minute after the response to the presence of signal protein.

4f4 marks

A journalist who read the text above concluded that farmers should not be allowed to use fertilisers to increase the yield of pepper plants.

Evaluate their conclusion.

5a2 marks
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5b2 marks

Suggest why more than one person was used for the creation of the reference sequences (lines 11 - 16).

5c3 marks

Describe how some base substitutions in the DNA sequence of a gene can be harmless while others can lead to disease through altered protein-protein interactions (lines 20 - 23).

5d2 marks

The cancer cells within a particular patient were found to be caused by the known overexpression of a specific gene.

Suggest and explain how a medical cancer treatment could be tailored to the individual (lines 29 - 33).

5e2 marks

The sequencing machines can sequence 80 000 bases in 1 second. (lines 9 -11)

If the human genome is 6 200 megabase pairs long, calculate the time it will take to sequence a whole human genome.

1 megabase = 1 000 000 base pairs. Give your answer in hours.

5f3 marks

Some of the patients with cancer exhibited zero differences or variation in their genomes from the reference genome. One of the researchers suggested that there could be important differences in their epigenomes.

Explain what an epigenome is and suggest how epigenetic changes could cause cells to become cancerous.

5g1 mark

Genome sequencing can be used to sequence the genomes of disease-causing viruses and bacteria.

Suggest how the genomic information obtained about these organisms could be applied in human medicine.

6a6 marks
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6b2 marks

Explain how genetic fingerprinting would allow scientists to identify the mother and father of an adolescent Amur leopard that had been released into the wild.

6c2 marks

Explain why genetic variation within a wild population is important. Suggest how DNA fingerprints could be used to help maintain genetic variation within the captive Amur leopard population.

6d3 marks

i) Suggest two different types of body cells from the Amur leopards that could have been present in their faeces samples. The named cells must contain DNA (lines 13 - 15).

ii) Explain the effect of PCR (lines 15 -17).

6e1 mark

Explain why the primers used bind solely to Amur leopard DNA, and not to the DNA from other organisms present in the faeces (lines 13 - 16).

6f1 mark

Blood or tissue samples can also be used to obtain DNA from Amur leopards.

Suggest a disadvantage of using a blood or tissue sample to obtain DNA from Amur leopards.

7a3 marks
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7b2 marks

12% of the population on the small island near New Zealand are affected by total colour blindness (lines 9–11) 

Use the information provided to calculate how many more times an individual on the island is likely to have total colour blindness compared to an individual living elsewhere. Show your working.

7c4 marks

Red-green colour blindness affects more men than women but blue-yellow colour blindness affects men and women equally (lines 12–13 and lines 16 -19). Explain why.

7d2 marks

People with red-green and blue-yellow colour blindness are unable to distinguish between other colours as well. (lines 12–19). Explain why.

7e2 marks

Some of the recent research into the treatment of red-green colour blindness involves the use of gene therapy (lines 20 - 25).

Suggest how gene therapy cells could correct red-green colour blindness.

7f2 marks

The use of induced pluripotent stem cells (iPS cells) could prove a more successful method than gene therapy for the correction of red-green colour blindness (lines 26–27).

Using the information provided, suggest and explain two reasons why.

8a3 marks
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8b4 marks

Two couples, couple X and couple Y, used a genetic screening service to find out if they were likely to pass on any harmful alleles to their potential children. The genomes of all four individuals were sequenced and any harmful mutations identified. None of the parents showed signs or symptoms of MD.

The results revealed the following:

  • Couple X had a 25 % probability of their children having MD

  • Couple Y had a 100 % probability of their children having MD

Using your knowledge of inheritance and the information in lines 6–10, explain the results from couple X and couple Y.

8c2 marks

A small amount of DNA was extracted from the couples mitochondrial and nuclear DNA. PCR was carried out before sequencing. 

i) Suggest why PCR was used.

ii) Explain how sequencing would allow for mutations to be identified.

8d3 marks

Suggest how altering the anticodon of a tRNA results in MD (lines 10–13).

8e3 marks

The post-exercise blood lactate concentration of an individual with MD is often much greater than the normal range (line 16). Suggest why.

9a4 marks

Read the following passage.

Iron is an essential mineral required for many processes in both animals and plants. In plants, iron is needed for the synthesis of chlorophyll and acts as a cofactor for enzymes involved in photosynthesis and respiration. However, in many soils, particularly those with alkaline conditions, iron is not readily available because it forms insoluble compounds.

To overcome this, some plants release organic compounds called phytosiderophores into the surrounding soil. These molecules bind with iron ions to form soluble complexes that can be absorbed by specific transport proteins located in the root cell membranes.

Scientists have genetically modified rice plants to overproduce phytosiderophores to improve their ability to grow in iron-poor soils. In a recent experiment, the growth of these genetically modified (GM) rice plants was compared with that of unmodified rice plants when grown in alkaline soil with low iron availability.

After 21 days, the GM plants had significantly greater shoot length and chlorophyll concentration. However, no significant differences in root length were observed between the two types of plants. Gene expression analysis also showed that genes involved in transporting iron from roots to shoots were more highly expressed in the GM plants than in the unmodified plants.

One concern about these GM plants is the potential that increased phytosiderophore production may enhance the availability and uptake of harmful heavy metals, such as cadmium, in soils that are contaminated. If absorbed, these metals could accumulate in the grain, which may pose a risk to human health.

Iron deficiency in plants can cause chlorosis, a condition where leaves turn pale or yellow.

(i) Explain how this condition can reduce the growth of a plant (paragraph 1)

(ii) Use your knowledge of transport across cell membranes to explain how iron enters the plant root cells.

9b2 marks

The scientists found higher activity of iron transport genes in the GM rice plants.

Suggest how they could have measured the activity of these genes.

9c2 marks

Despite showing increased shoot growth, the GM rice plants did not have longer roots than unmodified plants (paragraph 4)

Suggest two reasons for this.

9d2 marks

The scientists reported that the differences in shoot length and chlorophyll concentration were statistically significant (paragraph 4)

Describe how they could have tested for this and what result would show the difference is significant.

9e5 marks

Evaluate the potential benefits and risks of using GM rice plants that produce high levels of phytosiderophores (paragraph 5)

10a4 marks

Read the following passage.

Maintaining blood glucose levels within a narrow range is essential for proper cellular function in mammals. When blood glucose levels rise after a meal, the pancreas releases insulin, which promotes glucose uptake by cells and stimulates the conversion of glucose to glycogen in the liver and muscles.

Insulin binds to specific insulin receptors on target cell membranes, triggering a cascade of intracellular events. This binding causes conformational changes in the receptor, which then activates glucose transporter proteins (GLUT4) that are stored in vesicles within the cytoplasm. These transporters are rapidly moved to the cell membrane through exocytosis, allowing glucose to enter the cells more efficiently.

In type 2 diabetes, cells become resistant to insulin, meaning that they respond poorly to the hormone even when it is present in normal or elevated concentrations. Research has shown that this insulin resistance is often associated with reduced numbers of functional insulin receptors on cell membranes and impaired translocation of GLUT4 transporters to the membrane.

A recent study investigated the effectiveness of a new drug treatment for type 2 diabetes. The drug works by increasing the sensitivity of cells to insulin, thereby improving glucose uptake. Patients were divided into two groups: one receiving the new drug and a control group receiving a placebo (a treatment containing no active ingredients). After 12 weeks of treatment the drug group showed significantly lower fasting blood glucose levels and improved glucose tolerance compared to the control group. Some patients in the drug group experienced side effects, including hypoglycaemia, a condition in which they developed abnormally low blood glucose levels.

Glycogen is used as a storage molecule in liver and muscle cells (paragraph 1).

(i) Describe how glycogen is formed from glucose in liver and muscle cells.

[2]

(ii) Explain two features of glycogen that make it a suitable storage molecule.

[2]

10b2 marks

Explain why muscle cells are target cells for insulin (paragraph 2).

10c2 marks

Insulin resistance in type 2 diabetes (paragraph 3) can lead to hyperglycaemia, a condition where blood glucose levels remain persistently high.

(i) Explain how type 2 diabetes can affect cellular respiration in body cells.

[1]

(ii) State how glucose normally enters target cells in response to insulin.

[1]

10d1 mark

Despite showing improved glucose uptake, some patients in the drug group experienced hypoglycaemia as a side effect (paragraph 4).

Suggest why this occurred.

10e4 marks

Evaluate the potential benefits and risks of using this new drug treatment for type 2 diabetes patients (paragraph 4).

10f3 marks

Myocyte Enhancer Factor 2 (MEF2) is a transcription factor responsible for initiating the transcription of GLUT4. Exercise has been shown to stimulate expression of MEF2 in skeletal muscle cells.

Describe the mechanism by which exercise could reduce the risk of type II diabetes.

11a3 marks

Read the following passage.

Natural selection is a fundamental mechanism of evolution that shapes populations over time. When environmental pressures favour certain traits, individuals with advantageous characteristics are more likely to survive and reproduce, passing these beneficial alleles to their offspring.

In a population of peppered moths (Biston betularia), two main colour variants exist: light-coloured moths and dark-coloured (melanic) moths. The colour is controlled by a single gene, with the dark allele being dominant over the light allele. During the Industrial Revolution, pollution darkened tree bark in many areas, providing better camouflage for dark moths against predation by birds.

Research has shown that in polluted environments, dark moths have significantly higher survival rates compared to light moths. This selective advantage leads to an increase in the frequency of the dark allele in the population over successive generations. Conversely, in unpolluted areas with light-coloured tree bark, light moths have the survival advantage.

A recent study investigated changes in allele frequencies in a peppered moth population over a 50-year period following the Clean Air Act, which reduced industrial pollution. Researchers found that as pollution levels decreased and tree bark became lighter, the frequency of the dark allele declined from 90% to 30% in the study population.

However, the researchers noted that some dark moths persisted even in the cleanest environments, suggesting that factors other than camouflage alone may influence survival.

In heavily polluted environments, the frequency of the light allele in peppered moth populations can become very low due to strong selection pressure.

(i) State why different variations in moth colour existed in the population of peppered moths (paragraph 2).

[1]

(ii) Identify the selection pressure acting on the peppered moth population (paragraph 2).

[1]

(iii) Suggest one reason why some dark moths were still found in unpolluted environments, even though light-coloured moths had the selective advantage (paragraph 5).

[1]

11b
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5 marks

In a population of 800 moths, 560 moths showed the dark phenotype. The colour is controlled by a single gene with two alleles. The dark allele is dominant over the light allele.

(i) Calculate the phenotype frequency of the dark moths in this population.
Give your answer as a percentage.

(ii) Use the Hardy–Weinberg principle to calculate the allele frequency of the dark allele in this population.

11c2 marks

The researchers reported that the changes in allele frequencies over the 50-year period were statistically significant where the probability value was P< 0.05.

Identify the statistical test used to analyse the allele frequencies of the moth populations and explain the meaning of these results.

11d5 marks

Evaluate the use of peppered moths as a model system for studying natural selection and evolutionary change.

12a5 marks

Read the following passage.

Protein digestion is a multi-stage process that begins in the stomach and continues in the small intestine. In the stomach, the enzyme pepsin hydrolyses proteins into smaller polypeptides under acidic conditions. The majority of protein digestion then takes place in the small intestine, where pancreatic enzymes, such as trypsin and chymotrypsin, break down these polypeptides into shorter peptide chains. Much of the final stage of protein digestion occurs on the surface of the small intestine’s epithelial cells. These cells possess membrane-bound peptidases on their brush border, which hydrolyse dipeptides and tripeptides into single amino acids. These amino acids are then absorbed into the epithelial cells and enter the bloodstream for transport around the body.

Scientists investigated protein digestion in individuals with pancreatic insufficiency — a condition in which the pancreas does not produce enough digestive enzymes. Participants ate a protein-rich meal and had blood sampled two hours later. Compared with healthy individuals, those with pancreatic insufficiency showed markedly lower blood amino-acid concentrations. When affected participants were given enzyme supplements, amino-acid absorption improved, although in many cases it did not reach the levels seen in healthy controls, and some participants continued to report digestive symptoms.

Further analysis revealed elevated levels of undigested peptides in the faeces of those with pancreatic insufficiency, indicating incomplete protein breakdown. Despite enzyme supplementation, faecal peptide levels often remained higher than in healthy individuals. Together, these findings show that pancreatic enzymes are essential for nutrient absorption, and that while supplementation helps, it may not fully restore normal digestion in all patients.

One common genetic cause of pancreatic insufficiency is cystic fibrosis (CF), a hereditary disorder caused by mutations in the CFTR gene. This mutation results in the production of thick, sticky mucus that can block the pancreatic duct. Cystic fibrosis is inherited in an autosomal recessive pattern.

Pancreatic insufficiency can lead to protein malnutrition, a condition where the body cannot obtain adequate amino acids from dietary proteins.

(i) Explain how this condition may affect cellular processes.

[4]

(ii) Use your knowledge of transport across cell membranes to explain how amino acids enter the intestinal epithelial cells (paragraph 1).

[1]

12b2 marks

Explain how the epithelial cells of the small intestine are adapted for the rapid absorption of amino acids (paragraph 1).

12c2 marks

Despite showing improved amino acid absorption with enzyme supplements, some individuals with pancreatic insufficiency still experienced digestive problems (paragraphs 2 and 3).

Suggest two reasons for this.

12d3 marks

The scientists found higher concentrations of undigested peptides in faeces from individuals with pancreatic insufficiency (paragraph 3).

Suggest how they could have measured the concentration of these peptides.

12e
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3 marks

Cystic fibrosis is inherited in an autosomal recessive pattern (paragraph 4).

A faulty allele is represented by f and a healthy allele is represented by F.

Two heterozygous individuals decide to have children.

(i) Predict the possible genotypes of their children and state the probability that their child will be affected by CF.

[2]

(ii) State how an individual could be tested to determine whether or not they carry the allele for CF.

[1]

13a1 mark

Read the passage.

Researchers studying bacteria from Antarctic sea ice have discovered several enzymes that remain active at temperatures close to 0 °C. These cold-adapted enzymes allow the bacteria to carry out essential metabolic reactions even in extremely cold conditions.

One such enzyme, called lipase-A, helps the bacteria break down lipids for energy. Compared to similar enzymes from bacteria in warmer environments, lipase-A is made up of a slightly different strcuture, giving it a more flexible structure. This flexibility appears to allow it to function efficiently at lower temperatures.

Scientists sequenced the gene for lipase-A and compared it to the version found in a closely related species that lives in temperate waters. The coding region for lipase-A in the Antarctic bacteria contained several base substitutions. However, the amino acid sequence was still very similar between the two species, suggesting that many of the mutations were neutral.

To study how the enzyme is produced, researchers isolated the mRNA for lipase-A. They then inserted the gene into bacterial cells to produce large amounts of the lipase enzyme in the laboratory.

Name the monomer(s) that lipase-A will break down the bacterial lipid molecules into. (Paragraph 2)

13b3 marks

(i) Suggest one advantage to the Antarctic bacteria of having enzymes that can function at low temperatures. (Paragraph 2)

(ii) The amino acid sequence of lipase-A in cold-climate bacteria is very similar to that of the temperate bacteria, despite DNA differences. (Paragraph 3)

Explain how this is possible.

13c5 marks

Before the researchers isolated the mRNA for lipase-A, it was produced from a gene.

(i) Describe how this mRNA was made.(Paragraph 4)

(ii) Give two ways in which the structure of this mRNA differs from the DNA it was transcribed from.

13d1 mark

The researchers described some of the base substitutions as “neutral.” (Paragraph 3)

Describe what is meant by a neutral mutation.

14a2 marks

Read the following passage.

Ebola is a viral disease. A glycoprotein on the surface of the Ebola virus binds to a receptor protein found in the cell-surface membranes of human cells. The binding of the virus glycoprotein with the human cell receptor protein allows the virus to enter the cell. However, not all humans produce this receptor protein.

Those who don't have the receptor protein can still become infected with the virus, without actually developing the disease.

A blood test can be used to check whether a patient has the Ebola disease. The blood of patients with the disease contains large numbers of specific plasma cells and large numbers of a particular antibody. It has been suggested by researchers that patients with Ebola could be treated by giving them blood plasma transfusions from patients who have recently had the disease but have now recovered.

Researchers have also stated that the high mutation rate of the Ebola virus presents a challenge to the development of a vaccine.

Use the information provided above and your own knowledge to answer the following questions.

Explain how people who don't have the receptor protein in the surface membranes of their cells can still become infected with the virus, without actually developing the disease (lines 5-6).

14b2 marks

Researchers found that the blood of patients who have Ebola contains large numbers of specific plasma cells and large numbers of a particular antibody (lines 7-9). Explain why this was the case.

14c3 marks

The high mutation rates of viruses is problematic for developing vaccines against them (lines 13-14)

(i) Explain how a mutation could cause the antigen(s) on a virus to change.

(ii) Why is antigenic variation in a particular virus problematic for developing a vaccine?

14d3 marks

It has been suggested by researchers that patients with Ebola could be treated by giving them blood plasma transfusions from patients who have recently had the disease but have now recovered (lines 9-12).

(i) Explain how these blood transfusions could be an effective treatment

(ii) Give one reason why the blood plasma should be tested before being given to Ebola patients.

15a
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3 marks

Read the following passage.

The milk produced by mammals is nutrient-rich and contains the correct proportions of the different nutrients that offspring need to grow and develop. This milk is produced by milk-producing cells located in mammary glands.


Milk-producing cells synthesise lipids, carbohydrates and proteins by absorbing substances from the blood. These cells have a height to breadth ratio of 1.3: 1. They are approximately cube-shaped.

Lactose is a disaccharide and is the main carbohydrate in milk. The condensation of glucose and galactose (both monosaccharides) forms lactose. Galactose has the same chemical formula as glucose but has a slightly different structure.

Lactose-synthesis occurs in the Golgi apparatus and is then transported through the cytoplasm in vesicles. The lactose inside these vesicles cannot escape. The diameter of the vesicles increases as they move to the plasma membrane. When they get there, the vesicle membranes fuse with the plasma membrane and release their lactose out of the cell.

Use the information provided above and your own knowledge to answer the following questions.

(i) Milk-producing cells have a height to breadth ratio of 1.3: 1. (line 5). The breadth of a milk-producing cell is 37 um.

Calculate the height of this cell.

(ii) Milk-producing cells are approximately cube-shaped (line 6).

Describe and explain how the surface area to volume ratio of an epithelial cell from the inner lining of the small intestine might differ from the surface area to volume ratio of a milk-producing cell.

15b2 marks

Using your knowledge of water potential, explain why the diameter of lactose-containing vesicles increases as they move through the cytoplasm towards the plasma membrane (lines 11-12).

15c2 marks

Why do milk-producing cells need to contain large numbers of mitochondria?

15d3 marks

Lactose is released from milk-producing cells via exocytosis (lines 12-14). However, some substances diffuse through the plasma membranes of milk-producing cells.

Explain how substances can pass through the membrane via diffusion.

16a3 marks

Read the following passage.

The human body contains over 200 unique cell types. Further still, numerous human body cell types can be split further into different varieties of cell, within the cell type. For example, we can split white blood cells into several distinct varieties including lymphocytes and macrophages (a type of phagocytes).

Despite many common features present across a range of human body cell types, 5 each type is also specialised (sometimes very highly) to carry out its specific function. Although the majority of cell types contain the same organelles, the number of certain organelles that each cell type contains can differ significantly. A notably large number of mitochondria are present in muscle cells, for example, and hormone-secreting cells in the pancreas have distinctly large amounts of rough endoplasmic reticulum.

Interestingly, the amount of a certain organelle is not always fixed during a cells 'life' and this was observed by scientists looking at the cells in the tails of tadpoles. As a tadpole develops into a frog, its tail is gradually reabsorbed into the main body of the tadpole. The scientists found that the number of lysosomes in the tail cells actually increased as the tadpole matured.

Use the information provided above and your own knowledge to answer the following questions.

A notably large number of mitochondria are present in muscle cells (lines 8-9. Explain why muscle cells are adapted this way.

16b2 marks
16c3 marks
16d2 marks
17a3 marks

Read the following passage.

Wheat stalks are mainly composed of three different organic materials. These are cellulose, hemicellulose and lignin. Molecules of cellulose are joined in chains, which then layer together to create cellulose fibres. Hemicellulose is mostly made up of pentose sugar monomers.

Hemicellulose is a small molecule and functions a bit like a glue in that it holds cellulose fibres together. The third organic material, 5 lignin, is also a polymer. Unlike the other two substances, however, it is not a carbohydrate. It provides extra strength by covering the cellulose in the cell wall.

After the harvesting of a wheat crop, the hollow wheat stalks are dried, then cut and formed into bales of straw. Straw has a very low moisture content.

The straw can be used to produce a variety of useful organic substances. For example, it can be used as an ingredient in biofuels, packaging materials and paper manufacturing. A key step in the process is converting the cellulose to glucose. Although enzymes can be used for this process, a complication with this is that the lignin covering the cellulose within the straw stops the cellulose from being broken down by such enzymes. The lignin must therefore be removed before this can occur.

Use the information provided above and your own knowledge to answer the following questions.

Compare and contrast the structure of a hemicellulose molecule and a cellulose molecule.

17b3 marks

Molecules of cellulose are joined in chains, which then layer together to create cellulose fibres (lines 2-3). Describe the structure of a cellulose molecule.

17c2 marks

The lignin covering the cellulose within the straw stops the cellulose from being broken down by cellulose-digesting enzymes (lines 14-15). Explain why these enzymes cannot simply break down the lignin.

17d1 mark

Hemicellulose is mostly made up of pentose sugar monomers (lines 3-4).

Give one named example of a pentose sugar.

18a1 mark

Read the following passage.

Pathogens enter the bodies of organisms, where they cause disease. Viruses are a type of pathogen. People infected with the human immunodeficiency virus, commonly referred to as HIV, develop something known as acquired immunodeficiency syndrome, commonly referred to as AIDS. This is a very serious condition as it stops the infected individual from producing an immune response in defence against other pathogens.

Researchers have been trying to create vaccines against HIV for a long time but it is proving very difficult, mainly due to three properties of HIV. Firstly, HIV has high antigenic variability. Secondly, the virus can enter human body cells within a very short time of an individual being infected. Thirdly, HIV destroys T-cells.

There are other methods used to help delay the onset of AIDS. Although not a long-term cure, a drug called azidothymidine (AZT) can be used to temporarily stop and slow down the development of AIDS. The drug does not destroy HIV in the body but inhibits the enzyme responsible for synthesising DNA from the RNA of the human immunodeficiency virus.

Use the information provided above and your own knowledge to answer the following questions.

Viruses are a type of pathogen (lines 1-2). Other than viruses, name one other type of pathogen.

18b2 marks
18c4 marks
18d3 marks