Compounds, Formulae & Equations (OCR A Level Chemistry A): Revision Note

Exam code: H432

Richard Boole

Written by: Richard Boole

Reviewed by: Philippa Platt

Updated on

Chemical formulae

  • Ionic compounds are formed from a metal and a non-metal bonded together

  • Ionic compounds are electrically neutral

    • This means that the positive charges equal the negative charges

Positive ions

  • Some non-metal ions can have a positive charge, e.g.:

    • Hydrogen, H+

  • All metals form positive ions

  • Group 1 metals:

    • Lose 1 electron

    • Have a 1+ charge, eg. K+

  • Group 2 metals:

    • Lose 2 electrons

    • Have a 2+ charge, eg. Ca2+

  • Group 3 metals:

    • Lose 3 electrons

    • Have a 3+ charge, eg. Al3+

  • The charge on the ions of the transition elements can vary

    • Roman numerals are used to indicate their charge

      • Mn(II) represents the Mn2+ ion

      • Mn(VII) represents the Mn7+ ion

  • Roman numerals are used in some compounds formed from transition elements to show the charge (or oxidation state) of metal ions

    • In copper(II) oxide, CuO, the copper ion has a 2+ charge

    • In copper(I) oxide, Cu2O, the copper ion has a 1+ charge

Negative ions

  • The non-metals in group 15 to 17 have:

    • A negative charge

    • The ‘ide’ suffix, e.g. nitride, sulfide, chloride

  • Group 17 elements:

    • Gain 1 electron

    • Have a 1- charge, eg. bromide, Br-

  • Group 16 elements:

    • Gain 2 electrons

    • Have a 2- charge, eg. oxide, O2-

  • Group 15 elements:

    • Gain 3 electrons

    • Have a 3- charge, eg. nitride, N3-

Simplified ionic table with groups 1, 2, 13-18. Blue for positive ions (e.g., Li⁺, Ca²⁺), red for negative ions (e.g., F⁻, I⁻), and transition elements.
The charges of simple ions depend on their position in the Periodic Table

Polyatomic ions

  • Polyatomic ions are ions that are made of more than one type of atom

  • For A-level Chemistry:

    • The most common positive polyatomic ion is:

      • Ammonium, NH4+

    • There are several polyatomic negative ions:

      • Hydroxide, OH-

      • Nitrate, NO3-

      • Sulfate, SO42-

Ion formulae table

Ion

Formula and charge

Silver(I)

Ag+

Ammonium

NH4+

Zinc(II)

Zn2+

Hydroxide

OH-

Nitrate

NO3-

Sulfate

SO42-

Carbonate

CO32-

Hydrogen carbonate

HCO3-

Phosphate

PO43-

Worked Example

Formulae

Determine the formulae of the following ionic compounds

  1. Magnesium chloride

  2. Iron(III) oxide

  3. Aluminium nitrate

Answers:

  1. Magnesium chloride = MgCl2

    • Magnesium is in Group 2 so has a charge of 2+

    • Chlorine is in group 17 so has a charge of 1-

    • Magnesium needs two chloride ions for each magnesium ion to be balanced

    • Therefore, the formula is MgCl2

  2. Iron (III) oxide = Fe2O3

    • The Roman numeral states that iron has a charge of 3+

    • Oxygen is in group 16 so has a charge of 2-

    • The charges need to be equal so 2 iron ions to 3 oxide ions will balance electrically

    • Therefore, the formula is Fe2O3

  3. Aluminum nitrate = Al(NO3)3

    • Aluminium is in group 13 so has a charge of 3+

    • Nitrate is a polyatomic ion and has a charge of 1-

    • The polyatomic ion needs to be placed in a bracket if more than 1 is needed

    • Therefore, the formula of aluminium nitrate is Al(NO3)3

Balancing chemical equations

  • A symbol equation is a shorthand way of describing a chemical reaction using chemical symbols to show the number and type of atoms involved

  • A word equation uses only words to describe the reactants and products of a chemical reaction

Balancing equations

  • Atoms are not created or destroyed in chemical reactions

  • Therefore, the number of atoms of each element must be the same on both sides of the equation

  • To balance equations:

    • Do not change any chemical formulae

    • Add numbers in front of formulae to balance atoms

    • In combustion reactions, balance carbon first, then hydrogen, and finally oxygen

Step-by-step method

  1. Write the correct formulas for the reactants and products

  2. Count the number of each type of atom on both sides

  3. Add numbers in front of formulas to balance the atoms one at a time

  4. Add appropriate state symbols:

    • (s) = solid

    • (l) = liquid

    • (g) = gas

    • (aq) = aqueous (dissolved in water)

Worked Example

Write the balanced symbol equation for the following reaction:

magnesium + oxygen → magnesium oxide

Answer:

Step 1: Write out the symbol equation showing reactants and products

Mg + O2 → MgO

Step 2: Count the numbers of atoms in each reactant and product

Mg

O

Reactants

1

2

Products

1

1

Step 3: Balance the atoms one at a time until all the atoms are balanced

2Mg + O2 → 2MgO

This is now showing that 2 moles of magnesium react with 1 mole of oxygen to form 2 moles of magnesium oxide

Step 4: Use appropriate state symbols in the fully balanced equation

2Mg (s) + O2 (g) → 2MgO (s)

Ionic equations

  • In aqueous solutions, ionic compounds dissociate into their ions

  • However, not all ions in the solution actually take part in the chemical reaction

    • The ions that do not react are called spectator ions

  • An ionic equation shows only the species that are involved in the chemical change

    • It leaves out the spectator ions

Worked Example

1. Write the balanced symbol equation for the following reaction:

zinc + copper(II) sulfate → zinc sulfate + copper

2. Write the ionic equation for the above reaction.

Answer 1:

Step 1: To balance the equation, write out the symbol equation showing reactants and products

Zn  + CuSO4  → ZnSO4 + Cu

Step 2: Count the numbers of atoms in each reactant and product.

Zn

Cu

S

O

Reactants

1

1

1

4

Products

1

1

1

4

The equation is already balanced

Step 3: Use appropriate state symbols in the equation

Zn (s)  + CuSO4 (aq)  → ZnSO4 (aq) + Cu (s)

Answer 2:

Step 1:  The full chemical equation for the reaction is

Zn (s)  + CuSO4 (aq)  → ZnSO4 (aq) + Cu (s)

Step 2:  Break down reactants into their respective ions

Zn (s)  + Cu2+ +  SO42- (aq)  → Zn2++ SO42- (aq) + Cu (s) 

Step 3:  Cancel the spectator ions on both sides to give the ionic equation

Zn (s)  + Cu2+ + SO42- (aq)  → Zn2++ SO42- (aq) + Cu (s)

So, the final ionic equation is:

Zn (s)  + Cu2+(aq)  → Zn2+ (aq) + Cu (s)

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Richard Boole

Author: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener