Calculations Using Born-Haber Cycles (OCR A Level Chemistry A): Revision Note
Exam code: H432
Born-Haber Cycles - Calculations
Once a Born-Haber cycle has been constructed, it is possible to calculate the lattice enthalpy (ΔHlattꝋ) by applying Hess’s law and rearranging:
ΔHfꝋ = ΔHatꝋ + ΔHatꝋ + IE + EA + ΔHlattꝋ
If we simplify this into three terms, this makes the equation easier to see:
ΔHlattꝋ
ΔHfꝋ
ΔH1ꝋ (the sum of all of the various enthalpy changes necessary to convert the elements in their standard states to gaseous ions)
The simplified equation becomes
ΔHfꝋ = ΔH1ꝋ + ΔHlattꝋ
So, if we rearrange to calculate the lattice enthalpy, the equation becomes
ΔHlattꝋ = ΔHfꝋ - ΔH1ꝋ
When calculating the ΔHlattꝋ, all other necessary values will be given in the question
A Born-Haber cycle could be used to calculate any stage in the cycle
For example, you could be given the lattice enthalpy and asked to calculate the enthalpy change of formation of the ionic compound
The principle would be exactly the same
Work out the direct and indirect route of the cycle (the two routes start and end at the same points, so their enthalpy changes are equal)
Write out the equation in terms of enthalpy changes and rearrange if necessary to calculate the required value
Remember: sometimes a value may need to be doubled or halved, depending on the ionic solid involved
For example, with MgCl2 the value for the first electron affinity of chlorine would need to be doubled in the calculation, because there are two moles of chlorine atoms
Therefore, you are adding 2 moles of electrons to 2 moles of chlorine atoms, to form 2 moles of Cl- ions
Worked Example
Given the data below, calculate the ΔHlattꝋ of potassium chloride (KCl)

ΔHatꝋ / kJ mol-1 | IE / EA / kJ mol-1 | |
|---|---|---|
K | +90 | +418 (first ionisation energy) |
Cl | +122 | -349 (first electron affinity) |
ΔHfꝋ [KCl] = -437 kJ mol-1
Answer
Step 1: The corresponding Born-Haber cycle is:

Step 2: Applying Hess’ law, the lattice enthalpy of KCl is:
ΔHlattꝋ = ΔHfꝋ - ΔH1ꝋ
ΔHlattꝋ = ΔHfꝋ - [(ΔHat K) + (ΔHat Cl) + (IE1 K) + (EA1 Cl)]
Step 3: Substitute in the numbers:
ΔHlattꝋ = (-437) - [(+90) + (+122) + (+418) + (-349)] = -718 kJ mol-1
Worked Example
Given the data below, calculate the ΔHlattꝋ of magnesium oxide (MgO)

ΔHatꝋ / kJ mol-1 | IE1 / EA1 / kJ mol-1 | IE2 / EA2 / kJ mol-1 | |
|---|---|---|---|
Mg | +148 | +736 | +1450 |
O | +248 | -142 | +770 |
ΔHfꝋ [MgO] = -602 kJ mol-1
Answer
Step 1: The corresponding Born-Haber cycle is:

Step 2: Applying Hess’ law, the lattice enthalpy of MgO is:
ΔHlattꝋ = ΔHfꝋ - ΔH1ꝋ
ΔHlattꝋ = ΔHfꝋ - [(ΔHatꝋ Mg) + (ΔHatꝋ O) + (IE1 Mg) + (IE2 Mg) + (EA1 O) + (EA2 O)]
Step 3: Substitute in the numbers:
ΔHlattꝋ = (-602) - [(+148) + (+248) + (+736) + (+1450) + (-142) + (+770)]
= -3812 kJ mol-1
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