Buffers (OCR A Level Chemistry A): Revision Note

Exam code: H432

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Buffer solutions

  • A buffer solution is a solution which resists changes in pH when small amounts of acids or alkalis are added

  • A buffer solution is used to keep the pH almost constant by maintaining an almost constant concentration of hydrogen and hydroxide ions in a solution

Acidic buffers

  • Acidic buffers are made from a weak acid and a soluble salt of the acid

  • A common example is an aqueous mixture of ethanoic acid and sodium ethanoate

  • In solution, ethanoic acid partially ionises:

CH3COOH (aq) ⇌ H(aq) + CH3COO- (aq) 

ethanoic acid                       ethanoate

high conc                               low conc

  • Sodium ethanoate is a salt which fully dissociates in solution:

CH3COONa + aq → Na+ (aq) + CH3COO- (aq) 

sodium ethanoate                       ethanoate ion

low conc.                                    high conc.

  • This results in a buffer solution with high concentrations of CH3COOH and CH3COO-

    • The establishes the equilibrium with hydrogen and ethanoate ions:

CH3COOH (aq) ⇌ H(aq) + CH3COO- (aq) 

high conc.                               high conc.

When H+ ions (acid) are added:

  • The extra H⁺ ions react with CH3COO- to form CH3COOH

  • The equilibrium shifts left to reduce [H+]

    • This limits any drop in pH

  • Since there's a large supply of CH3COO-, its concentration doesn’t change much

  • So, the pH remains almost constant

Diagram explaining how ethanoate ions in buffer react with added H+ ions, preventing pH decrease; shows equilibrium equation for this reaction.
Ethanoate ions react with added H⁺ ions to prevent the pH from decreasing

When OH- ions (base) are added:

  • The OH- ions react with H+ to form water:

OH- (aq) + H(aq) → H2O (l)

  • The [H+] decreases, shifting the equilibrium right

CH3COOH (aq) → H+ (aq) + CH3COO- (aq)

  • More CH3COOH dissociates to replace H+ ions

  • So, the pH stays nearly constant due to the buffer action

  • The buffer works because it contains a reservoir of both the weak acid and its conjugate base, which can react with added H⁺ or OH⁻ to restore balance.

Le Chatelier's principle diagram shows acetic acid equilibrium shifting to replace removed hydrogen ions, reacting with hydroxide to form water.
Hydroxide ions remove H⁺ ions; equilibrium shifts to replace them

Calculating the pH of a buffer solution

  • The pH of a buffer solution can be calculated using:

    • The Ka of the weak acid

    • The equilibrium concentration of the weak acid and its conjugate base (salt)

  • To determine the pH, the concentration of hydrogen ions is needed which can be found using the equilibrium expression:

Ka = fraction numerator open square brackets salt close square brackets open square brackets straight H to the power of plus close square brackets over denominator open square brackets acid close square brackets end fraction

  • This can be rearranged to give:

[H+] = Ka x fraction numerator open square brackets acid close square brackets over denominator open square brackets salt close square brackets end fraction

  • To simplify the calculations, logarithms are used such that the expression becomes:

-log10[H+] = -log10Ka x -log10fraction numerator open square brackets acid close square brackets over denominator open square brackets salt close square brackets end fraction

  • Since -log10 [H+] = pH, the expression can also be rewritten as:

pH = pKa + log10fraction numerator open square brackets salt close square brackets over denominator open square brackets acid close square brackets end fraction

  • This is known as the Hendersen-Hasselbalch equation

Worked Example

Calculate the pH of a buffer solution containing 0.305 mol dm-3 of ethanoic acid and 0.520 mol dm-3 sodium ethanoate.

The Ka of ethanoic acid  = 1.74 × 10-5 mol dm-3

Answer:

Ethanoic acid is a weak acid that ionises as follows:

CH3COOH (aq) ⇌ H+ (aq) + CH3COO- (aq)

Step 1: Write down the equilibrium expression to find Ka

Ka = fraction numerator open square brackets CH subscript 3 COO to the power of minus close square brackets open square brackets straight H to the power of plus close square brackets over denominator open square brackets CH subscript 3 COOH close square brackets end fraction

Step 2: Rearrange the equation to find [H+]

[H+] = Ka x fraction numerator open square brackets CH subscript 3 COOH close square brackets over denominator open square brackets CH subscript 3 COO to the power of minus close square brackets end fraction

Step 3: Substitute the values into the expression

[H+] = 1.74 x fraction numerator open square brackets 0.305 close square brackets over denominator open square brackets 0.520 close square brackets end fraction

[H+] = 1.02 x 10-5 mol dm-3

Step 4: Calculate the pH

pH = - log [H+]

pH = -log 1.02 x 10-5

pH = 4.99

Uses of buffers

Controlling the pH of blood

  • In humans, HCO3- ions act as a buffer to keep the blood pH between 7.35 and 7.45

  • Body cells produce CO2 during aerobic respiration

  • This CO2 will combine with water in blood to form a solution containing H+ ions

CO2 (g) + H2O (l) ⇌ H+ (aq) + HCO3- (aq)

  • This equilibrium between CO2 and HCO3- is extremely important

  • If the concentration of H+ ions is not regulated, the blood pH would drop and cause ‘acidosis

    • Acidosis refers to a condition in which there is too much acid in the body fluids such as blood

    • This could cause body malfunctioning and eventually lead to coma

  • If there is an increase in H+ ions

  • The equilibrium position shifts to the left until equilibrium is restored

CO2 (g) + H2O (l) ⇌ H+ (aq) + HCO3- (aq)

  • This reduces the concentration of H+ and keeps the pH of the blood constant

  • If there is a decrease in H+ ions

    • The equilibrium position shifts to the right until equilibrium is restored

CO2 (g) + H2O (l) ⇌ H+ (aq) + HCO3- (aq)

  • This increases the concentration of H+ and keeps the pH of the blood constant

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.