Bond Polarity (DP IB Chemistry): Revision Note
Bond polarity
What is electronegativity?
Electronegativity is the ability of an atom to attract the shared pair of electrons in a covalent bond
Different atoms have different electronegativities, shown on the Pauling scale
Electronegativity values are listed in the IB Chemistry Data Booklet (Section 9)
The higher the value, the more electronegative the element
The Pauling Scale

In diatomic molecules, the electron density is shared equally between the two atoms
E.g. H2, O2 and Cl2
These atoms have the same electronegativity, so the bonding electrons are shared equally
This results in a nonpolar covalent bond
Diagram to show the electron distribution in a chlorine molecule

What is meant by a polar bond?
When two atoms in a covalent bond have different electronegativities, the bonding electrons are drawn closer to the more electronegative atom
This creates a polar covalent bond with an uneven distribution of electron density
As a result:
The centres of positive and negative charge no longer coincide
The electron distribution becomes asymmetric
The less electronegative atom gains a partial positive charge (δ+)
The more electronegative atom gains a partial negative charge (δ-)
The degree of polarity depends on the difference in electronegativity between the bonded atoms
A larger difference produces a more polar bond
Diagram to show the electron distribution in an HCl molecule

What is a dipole?
A dipole forms when there is a separation of charge across a covalent bond
The dipole moment is a measure of how polar a bond is
The greater the difference in electronegativity, the greater the dipole moment
The direction of the dipole is represented using a special arrow symbol:
The crossed tail is placed near the partially positive atom (δ⁺)
The arrowhead points toward the partially negative atom (δ⁻)

Worked Example
The electronegativity values of four elements are given.
C = 2.6 N = 3.0 O = 3.4 F = 4.0
What is the order of increasing polarity of the bonds in the following compounds?
A. CO < OF2 < NO < CF4
B. NO < OF2 < CO < CF4
C. CF4 < CO < OF2 < NO
D. CF4 < NO < OF2 < CO
Answer:
The correct option is B
Calculate the electronegativity difference for each bond:
NO → 3.4 – 3.0 = 0.4
OF2 → 4.0 – 3.4 = 0.6
CO → 3.4 – 2.6 = 0.8
CF4 → 4.0 – 2.6 = 1.4
Rank the bond polarities from smallest to largest:
NO < OF2 < CO < CF4
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