Oxidation of Alcohols (DP IB Chemistry: SL): Revision Note

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Oxidation of alcohols

Classification of alcohols

  • Alcohols are compounds that contain at least one hydroxy (-OH) group

  • The general formula of alcohols is CnH2n+1OH

  • They can be classed as primary, secondary and tertiary

Primary alcohols

  • A primary alcohol contains a carbon atom, bonded to the -OH group, which is attached to one other carbon atom (or alkyl group)

Displayed formula of propan-1-ol, CH3CH2CH2OH, a primary alcohol: the carbon bonded to the OH group is attached to only one other carbon.
In a primary alcohol, the O-H group is bonded to a carbon atom which is bonded to one other carbon atom in the chain

Secondary alcohols

  • A secondary alcohol contains a carbon atom, bonded to the -OH group, that is attached to two other carbon atoms (or alkyl groups)

A diagram to show a secondary alcohol
In a secondary alcohol, the O-H group is bonded to a carbon atom which is bonded to two other carbon atoms in the chain

Tertiary alcohols

  • A tertiary alcohol contains a carbon atom, bonded to the -OH group, that is attached to three other carbon atoms (or alkyl groups)

A diagram to show a tertiary alcohol
In a tertiary alcohol, the O-H group is bonded to a carbon atom that is bonded to three other carbon atoms

Oxidation of alcohols (general)

  • Primary alcohols can be oxidised to form aldehydes which can undergo further oxidation to form carboxylic acids

  • Secondary alcohols can be oxidised to form ketones only

  • Tertiary alcohols do not undergo oxidation

  • The oxidising agent of alcohols is acidified potassium dichromate(VI), K2Cr2O7 

  • The colour change is from orange to green

    • For potassium dichromate(VI) to act as an oxidising agent, it itself needs to be reduced

    • This reduction requires hydrogen (H+) ions which are provided by an acid, typically sulfuric acid

    • When alcohols are oxidised, the orange dichromate ions (Cr2O72-) are reduced to green Cr3+ ions

Three test tubes after warming with acidified potassium dichromate(VI): propan-1-ol (primary) and propan-2-ol (secondary) have turned green, while 2-methylpropan-2-ol (tertiary) stays orange.
This test can be used to distinguish tertiary alcohols, which do not oxidise, from primary and secondary alcohols that do

Oxidation of primary alcohols

  • The diagram below shows the two-step oxidation of a primary alcohol using [O] to represent the oxidising agent

    • The first oxidation step forms an aldehyde

    • The second oxidation step produces a carboxylic acid

Two-step oxidation using [O] (acidified K2Cr2O7): ethanol (primary alcohol) to ethanal (aldehyde) to ethanoic acid; and propanal (aldehyde) to propanoic acid.

Formation of a carboxylic acid (using ethanol)

  • This reaction is performed using reflux apparatus

  • A primary alcohol, such as ethanol, is added to the oxidising agent and warmed

CH3CH2OH (l) + 2[O] → CH3COOH (g) + H2O (l)

Reflux apparatus: a pear-shaped flask containing the mixture and anti-bumping granules, heated from below, with a vertical Liebig condenser above it (cold water in at the bottom, water out at the top) and an open top.
Ethanol and ethanal vapour condense and drip back into the reaction flask until it is all oxidised. Ethanoic acid can then be distilled off

Formation of an aldehyde (using ethanol)

  • This reaction is performed using distillation apparatus

  • A primary alcohol, such as ethanol, is added to the oxidising agent and warmed

  • The aldehyde product has a lower boiling point than the alcohol reactant so it can be distilled off as soon as it forms 

CH3CH2OH (l) + [O] → CH3CHO (g) + H2O (l)

Distillation with addition: alcohol is dripped from a tap funnel into a flask of oxidising mixture; the aldehyde distils over through a sloping condenser into a receiving flask.
If the aldehyde is not distilled off, further refluxing with excess oxidising agent will oxidise it to a carboxylic acid

Oxidation of secondary alcohols

Equation: propan-2-ol (secondary alcohol) + [O], with heat, gives propanone (ketone) + H2O, shown as displayed formulae.
  • Secondary alcohols, such as propan-2-ol, are oxidised to ketones

  • Since ketones cannot be further oxidised, the ketone product does not need to be distilled off straight away after it has been formed

CH3CH(OH)CH3 (l) + [O] → CH3COCH3 (g) + H2O (l)

Oxidation of tertiary alcohols

  • Tertiary alcohols do not undergo oxidation

    • This is because there must be a hydrogen on the functional group carbon, which breaks off to form water

    • There are no C-H bonds on the functional group carbon in a tertiary alcohol

Examiner Tips and Tricks

Make sure you can write equations using [O] to represent the oxidising agent in these reactions. The equation must still be balanced.

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Curriculum Expert

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.