Applying General Mathematics in Chemistry (DP IB Chemistry: SL): Revision Note

Richard Boole

Written by: Richard Boole

Reviewed by: Philippa Platt

Updated on

Applying general mathematics in Chemistry

Using arithmetic and algebraic calculations in chemistry

  • Chemistry often requires the use of calculations, which can include:

  • Decimals

    • Most chemical calculations use decimals, e.g. the concentration of a chemical

  • Fractions

    • These are most commonly used in uncertainty calculations

    • Most scientific calculators will initially give answers as fractions

      • Make sure you know where the S⇔D button is so that you convert the fraction into a decimal

  • Percentages

    • There are many percentage calculations, including percentage yield, percentage atom economy, percentage change, percentage difference, percentage error and percentage uncertainty

  • Ratios

    • These are commonly used in moles calculations where the stoichiometry of the balanced chemical equation is not 1 : 1, e.g.

H2SO4 + 2NaOH → Na2SO4 + 2H2O

  • Reciprocals

    • These are most obvious in gas laws, using 1 / V, and concentration versus rate graphs, using 1 / T

  • Logarithmic functions

    • These are most obvious in pH and Arrhenius calculations

  • Exponential functions (Additional Higher level)

    • This is most obvious in Arrhenius calculations

  • Section 1 of the Data Booklet contains a list of the mathematical equations that you are expected to be able to manipulate and work with

    • Careful: This is not an exhaustive list - there are other equations that you will be expected to know that are not given in Section 1 of the Data Booklet, e.g. percentage yield

Examiner Tips and Tricks

  • Make sure your final answers are written as proper numbers, not left as fractions

    • Leaving them as fractions will typically lose you a mark

What is the mean average?

  • The mean average is often just called the “average”

  • It is the total of all the values divided by the number of values, i.e. add all the numbers together and divide by how many there are

  • For example, two common isotopes of chlorine are chlorine-35 and chlorine-37, which exist in a 3 : 1 ratio

    • The information shows that there are three chlorine-35 atoms for every one chlorine-37 atom

    • Overall, there is a total of four atoms to be considered in the calculation

    • So, the mean average = 35+35+35+374 = 35.5

  • Problems with the mean average occur when there are anomalous results 

    • These should not be included in a mean average calculation

What mean average calculations are in chemistry?

  • Two main calculations in chemistry that involve mean average calculations are:

    • Calculating relative atomic mass from isotopic abundance data

      • For more information, see our revision note on Isotopes

    • Calculating average titres as part of a titration calculation

      • These calculations will typically have values that should not be considered because they are not concordant

Worked Example

Calculate the average titre for the following experimental results.

Rough titre
/ cm3

Titre 1 
/ cm3

Titre 2
/ cm3

Titre 3
/ cm3

Titre 4
/ cm3

15.50

14.90

15.15

14.95

14.95

Answer:

  • The three values that are used for the mean average calculation are:

    • 14.90

    • 14.95

    • 14.95

  • The rough titre should never be used in the mean average calculation

  • Any results that are not concordant are considered to be outlying / anomalous results and should not be included in the mean average calculation

  • So, the average titre = 14.90+14.95+14.953 = 14.93 cm3 

Range

  • The range can only be applied to numerical data

  • It is a measure of how spread out the data is, which means that it is the difference between the highest and lowest values

    • You can remember this as "Hi - Lo"

  • It can be expressed as:

    • A range of values

      • e.g. 9.2 - 8.4 

    • A single value

      • e.g. 9.2 - 8.4 = 0.8

  • The range can be affected when the highest and / or lowest data are anomalous results themselves

What is scientific notation?

  • Scientific notation is also known as standard form

  • It is a system of writing and working with very large or very small numbers

    • For example, Avogadro's number 602 000 000 000 000 000 000 000 is 6.02 x 1023 in scientific notation

  • Numbers in scientific notation are written as:

a × 10n

  • They follow these rules:

    • a is a number above 1 and below 10

    • For large numbers, n is an integer that is greater than 0 

      • i.e It shows how many times a is multiplied by 10

    • For small numbers, n is an integer that is less than 0 

      • i.e It shows how many times a is divided by 10

    • n < 0 for small numbers i.e how many times a is divided by 10

Applying scientific notation to numbers

Diagram showing how to convert large and small numbers into scientific notation
The scientific notation for numbers greater than 1 has the x 10 raised to a positive power while the scientific notation for numbers less than 1 has the x 10 raised to a negative power 
  • When rounding a number in standard form to a certain number of significant figures, only the value of a is rounded (the × 10n value will not be significant)

    • For example, 4.37 × 106 to 2 significant figures is 4.4 × 106

Orders of magnitude

  • When a number is expressed to an order of 10, this is an order of magnitude

    • Example: If a number is described as 3 × 108 then that number is actually 3 × 100 000 000

    • The order of magnitude of 3 × 108 is just 108

  • Orders of magnitude follow rules for rounding

    • The order of magnitude of 6 × 108 is 109 as the magnitude is rounded up

  • A quantity is one order of magnitude larger than another quantity if it is about ten times larger

    • Similarly, two orders of magnitude would be 100 times larger, or 102

  • In chemistry, orders of magnitude can be very large or very small

Approximation and estimation

  • Approximation and estimation are both methods used to obtain values that are close to the true or accurate values

    • While they share some similarities, they have distinct characteristics and are used in different contexts

  • An approximation is a value that is close to the actual value but not exact.

  • Used when:

    • A precise calculation is unnecessary

    • A quick answer is sufficient

    • The exact value is hard or time-consuming to obtain

  • Approximations are typically easy and fast to work out

  • For example, the pH of a strong acid is generally between pH 1.0 and 3.0

    • A useful approximation is to say pH = 1.0.

    • This is not exact, but it is widely accepted and practical for many uses

  • Estimationis making a reasoned guess based on available data.

  • Used when the true value is unknown or can't be directly measured.

  • For example, estimating percentage yield

    • Start with a known amount of reactant.

    • Calculate the theoretical mass of product.

    • Perform the reaction and measure actual product mass

Percentage yield = actual yieldtheoretical yield×100

Appreciate when some effects can be ignored and why this is useful

  • During calculations using acid and base dissociation constants the assumption made is that the value of [H+] = [HA] 

    • Or the concentration of hydrogen ions is the same as the concentration of the acid

  • This is because

    • The weak acid has a low degree of dissociation so you can assume the concentration of the acid is the same value at equilibrium and use it in the expression for Ka

      • CH3COOH  CH3COO + H+

      • A point to remember is that Ka values are different depending on the acid, so the degree of dissociation also varies. Therefore the error using this assumption for some acids will be larger than others 

    • All the H+ ions are assumed to come from the acid as water will contribute a very small number of H+ ions

  • So the Ka expression:

Ka[H+][A][HA]

can be simplified to 

Ka = [H+]2[HA]

  • Remember to give the full expression in an exam when asked

Percentage change and percentage difference

  • Percentage change and percentage difference are commonly used to express the relative change between two values

    • They are useful for comparing experimental results, determining reaction yields and analysing other chemical data

Percentage change

  • Percentage change is used to express the relative change between an initial value and a final value

  • It is calculated using the following formula:

Percentage Change = (Final ValueInitial Value)Initial value×100

Worked Example

During the course of a chemical reaction, the initial of chemical species A increases from 0.05 mol dm–3 to 0.08 mol dm–3.

Calculate the percentage change in concentration.

Answer:

  • Percentage change =(Final ValueInitial Value)Initial value×100

  • Percentage change = (0.080.05)0.05×100 = 60%

  • So, the concentration of the chemical species increased by 60% during the reaction

Percentage difference

  • Percentage difference is used to compare two values to determine how much they differ from each other as a percentage

  • It is calculated using the following formula:

Percentage Difference = (value 1  value2)(average of value1 and value 2)×100

Worked Example

The melting points of different samples B and C are measured:

  • B = 75°C

  • C = 81°C

Calculate the percentage difference in melting points. 

Answer:

  • Percentage difference = (value 1value2)(average of value1 and value 2)×100

  • Percentage difference = (7581)((75+81)2)×100

  • Percentage difference = 678×100 = –7.69%

  • When calculating percentage difference, you can ignore the minus sign in front of the calculation

  • So, the melting points of B and C differ by 7.69%

Percentage Error

  • Percentage error is used to express the difference between a final calculated answer and an accepted or literature value

  • It is calculated using the following formula

Percentage error = accepted valueexperimental valueaccepted value×100

  • You should be able to comment on any differences between the experimental and literature values

Worked Example

Experimental results showed the enthalpy of combustion of propan-1-ol to be –1.5 x 103 kJ mol–1.

The literature value for this enthalpy change is -2021 kJ mol-1.

Calculate the percentage error.

Answer:

  • Percentage error = accepted valueexperimental valueaccepted value×100

  • Percentage error = 202115002021×100 = 26 %

Percentage uncertainty

  • Percentage uncertainties are a way to compare the significance of an absolute uncertainty on a measurement

    • This is not to be confused with percentage error, which is a comparison of a result to a literature value

  • It is calculated using the following formula

Percentage uncertainty = absolute uncertaintymeasured value×100 

Diagram with examples of percentage uncertainty calculations for common laboratory apparatus

Diagram comparing analogue and digital measurements using a burette and a digital scale, showing uncertainty calculations for precision in chemistry.
The absolute uncertainty for analogue measurements is ± half a division and for digital measurements is ± the last significant division

Examiner Tips and Tricks

  • Percentage uncertainty can be reduced by:

    • Using equipment with a smaller uncertainty

    • Increasing the measured value, e.g. using a sample with greater mass or volume

Mathematical skills linked to graphs and tables

  • There are several specification points linked to graphs and tables

    • For more information about working specifically with graphs, see our revision note on Graphing in Chemistry

  • These include, but are not limited to, being able to:

    • Distinguish between qualitative and quantitative data, incorporating continuous and discrete variables

    • Understand direct and inverse proportionality, as well as positive and negative correlations between variables

    • Determine rates of change from tabulated data

Qualitative and quantitative data

  • Qualitative data usually describes something in words, not numbers 

    • For example:

      • Copper sulfate solution is blue

      • A more dilute copper sulfate solution is pale blue, while a more concentrated copper sulfate solution is a darker blue

  • Quantitative data uses numbers to count / measure something

    • For example:

      • The neutralisation of 25.0 cm3 sodium hydroxide by 25.0 cm3 hydrochloric acid increases the temperature of the system by 2.5 oC

  • Discrete data is quantitative

    • It consists of separate, distinct and countable values

    • For example:

      • The stoichiometric coefficients representing the relative number of molecules or atoms involved in the reaction are discrete values and must be integers

      • Electrons can only occupy certain discrete energy levels, e.g. 1s, 2s, etc

  • Continuous data is also quantitative

    • It is based on measurements and can include decimal numbers or fractions

    • This allows for an infinite number of values 

    • For example:

      • The temperature of an exothermic reaction as time progresses

      • The volume of gas produced during the thermal decomposition of calcium carbonate

Direct and inverse proportionality

  • There are a number of terms that are commonly applied to trends, particularly in graphs

  • Directly proportional

    • This applies to a trend that has a clearly linear relationship

    • Mathematically, this can be described as y = kx, where k can be positive or negative

    • In most situations, it is clear that k is positive

    • This means that the relationship can be described as "when one variable increases, the other increases" or "if x doubles, then y doubles"

    • A directly proportional relationship is always a straight line through the origin with a fixed gradient 

  • Inversely proportional

    • This can be described as y = kx, where k can be positive or negative

    • This means that the relationship can be described as "when one variable increases, the other decreases" or "if x doubles, then y halves" 

    • When plotted, inverse proportionality is not a straight line and does not pass through the origin

  • Positive correlation

    • This term is best applied to the gradient of a graph

    • The gradient of the graph is positive / slopes or curves upwards

    • It describes a relationship where as x increases, y also increases

  • Negative correlation

    • This term is, also, best applied to the gradient of a graph

    • The gradient of the graph is negative / slopes or curves downwards

    • It describes a relationship where as x increases, y decreases

Examiner Tips and Tricks

  • Careful: A common mistake made by students is to describe any graph with a straight line going diagonally upwards as directly proportional

    • This is not correct because direct proportionality must go through the origin

    • A graph that does not go through the origin can correctly be described as proportional, but it is not directly proportional 

Determine rates of change from tabulated data

  • To determine rates of change from tabulated data, you can use the average rate of change or gradient, if the data has been plotted as a graph

  • The average rate of change between two points on a graph or in a table is:

Rate of change = the change in the dependent variable (yaxis)the change in the independent variable (xaxis)

Worked Example

An experiment is run to measure the amount of chemical Y produced as time progresses:

Time / seconds 

10

20

30

40

50

Amount of Y / cm3 

3.0

7.0

10.0

14.0

18.0

Calculate the rate of change for this reaction between 10 and 30 seconds.

Answer:

  • Rate of change = the change in the dependent variable (yaxis)the change in the independent variable (xaxis)

  • Rate of change = (10.03.0)(3010) = 0.35 cm3 s–1 

  • So, on average, the amount of Y increases by 3.5 cm3 every 10 seconds over the interval from t = 10 to t = 30 seconds

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Richard Boole

Author: Richard Boole

Expertise: Curriculum Expert

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener