Molar Concentration (DP IB Chemistry): Revision Note

Alexandra Brennan

Written by: Alexandra Brennan

Reviewed by: Philippa Platt

Updated on

Molar concentration

Volumes & concentrations of solutions

  • Concentration tells us how much solute is dissolved in a solvent to make a solution:

    • It is usually measured as the amount of solute in 1 dm3 of solution

    • The solute is the substance being dissolved (e.g. salt or sugar)

    • The solvent is the liquid that does the dissolving (often water)

  • A concentrated solution contains a large amount of solute per unit volume

  • A dilute solution contains a small amount of solute per unit volume

Units of concentration

  • Concentration can be expressed in three common ways:

    • Moles per unit volume

      • Units: mol dm-3

      • Often written using square brackets, e.g. [NaCl] = 0.25 mol dm-3

    • Mass per unit volume

      • Units: g dm-3

    • Parts per million (ppm)

      • Used for very low concentrations, e.g. pollutants in water or air

Moles per unit volume

  • The formula for expressing concentration using moles is:

concentration (g dm-3) = Error converting from MathML to accessible text.

  • You must make sure you change cm3 to dm (by dividing by 1000)

  • The relationships can be expressed using this formula triangle

Concentration moles formula triangle diagram

Triangle diagram showing relationship between moles, concentration, and volume in dm³. Moles at top, divided by volume or concentration on bottom sides.
To use the concentration formula triangle cover the one you want to find out about with your finger and follow the instructions

Worked Example

Calculate the mass of sodium hydroxide, NaOH, required to prepare 250 cm3 of a 0.200 mol dm-3 solution.

Answer:

  • Step 1: Use the formula triangle to find the number of moles of NaOH needed

number of moles  = concentration (mol dm-3) x volume (dm3)  

moles = 0.200 mol dm-3 x 0.250 dm3

moles = 0.0500 mol

  • Step 2: Find the molar mass of NaOH

molar mass = 22.99 + 16.00 + 1.01 = 40.00 g mol-1

  • Step 3: Calculate the mass required

mass = moles x molar mass

mass = 0.0500 mol x 40.00 g mol-1 = 2.00 g

Mass per unit volume

  • Sometimes it is more convenient to express concentration in terms of mass per unit volume

  • The formula is:

concentration (g dm-3) = fraction numerator bold mass bold space bold of bold space bold solute bold space stretchy left parenthesis g stretchy right parenthesis over denominator bold volume bold space bold of bold space bold solution bold space stretchy left parenthesis dm cubed stretchy right parenthesis end fraction

  • To convert from mol dm-3 to g dm-3  :

    • Multiply the molar concentration by the molar mass

mass of solute (g) = number of moles (mol) x molar mass (g mol-1)

  • To convert from g dm-3 to mol dm-3:

    • Divide the mass concentration by the molar mass

concentration (mol dm-3) = fraction numerator bold concentration bold space bold left parenthesis bold g bold space bold dm to the power of bold minus bold 3 end exponent bold right parenthesis over denominator bold molar bold space bold mass bold space bold left parenthesis bold g bold space bold mol blank to the power of bold minus bold 1 end exponent bold right parenthesis end fraction

Parts per million

  • When expressing extremely low concentrations a unit that can be used is parts per million or ppm

  • This is useful when giving the concentration of a pollutant in water or the air when the absolute amount is tiny compared to the volume of water or air

  • 1 ppm is defined as

    • A mass of 1 mg dissolved in 1 dm3 of water

  • Since 1 dm3 weighs 1 kg we can also say it is

    • A mass of 1 mg dissolved in 1 kg of water, or 10-3 g in 103 g which is the same as saying the concentration is 1 in 10or 1 in a million

Worked Example

The concentration of chlorine in a swimming pool should be between 1 and 3 ppm.

Calculate the maximum mass, in kg, of chlorine that should be present in an Olympic swimming pool of size 2.5 million litres.

Answer:

  • Step 1: calculate the total mass in mg assuming 3ppm (1 litre is the same as 1 dm3)

3 x 2.5 x 106 = 7.5 x 106 mg

  • Step 2: convert the mass into kilograms (1 mg = 10-6 kg)

7.5 x 106  x 10-6  kg = 7.5 kg

Examiner Tips and Tricks

Use the correct formula:

  • For mass:

moles (n) = fraction numerator mass space open parentheses straight g close parentheses over denominator molar space mass space open parentheses gmol to the power of negative 1 end exponent close parentheses end fraction

  • For concentration

n = concentration (mol dm-3) x volume (dm-3)

Always check the units of mass and volume before calculating moles:

  • g mol-1 for molar mass (M)

  • grams (g) for mass (m)

  • dm3 (not cm3) for volume in concentration calculations

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Alexandra Brennan

Author: Alexandra Brennan

Expertise: Chemistry Content Creator

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener