Ionisation Energy Trends (Cambridge (CIE) AS Chemistry): Revision Note

Exam code: 9701

Last updated

  • Ionisation energies show periodicity, a recurring trend across each period of the Periodic Table

    • As you move left to right across a period, first ionisation energy generally increases

    • This trend is linked to the electronic configuration of elements:

      • Group 1 metals (e.g. Na) have low first ionisation energies because they have a single outer electron that is easy to remove

      • Noble gases (e.g. Ne, Ar) have very high ionisation energies due to their full outer shells and strong nuclear attraction

  • There are four factors that affect ionisation energy

    • Nuclear charge

    • Distance from the nucleus

    • Electron shielding

    • Spin-pair repulsion

Nuclear charge (number of protons)

  • As atomic number increases, so does the positive charge of the nucleus

  • A higher nuclear charge creates a stronger electrostatic attraction between the nucleus and outer electrons

  • Therefore more energy is required to remove the electron means a higher ionisation energy

Distance from the nucleus (atomic radius)

  • Outer electrons that are further from the nucleus experience weaker attraction

  • The greater the distance, the easier it is to remove the electron

  • Ionisation energy decreases with increased distance from the nucleus

Electron shielding (inner shell repulsion)

  • Electrons in inner shells repel electrons in outer shells and partially block the attraction of the nucleus

  • This is known as the shielding effect

  • More inner electron shells means greater shielding and therefore a lower ionisation energy

Spin-pair repulsion (electron–electron repulsion)

  • In orbitals that contain two electrons, the electrons experience repulsion due to their like charges

  • This repulsion slightly reduces the energy needed to remove one of the electrons

  • This explains small drops in ionisation energy across a period, such as:

    • Oxygen vs nitrogen (O’s paired 2p electrons are easier to remove)

    • Aluminium vs magnesium (Al’s 3p¹ electron is higher in energy than Mg’s 3s²)

Ionisation Energy & the Periodic Table

  • Across a period:

    • first ionisation energy increases due to higher nuclear charge and same shielding

  • Down a group:

    • first ionisation energy decreases due to greater atomic radius and more shielding

Graph of first ionisation energies from H to Na

Graph showing the first ionisation energy against atomic number for elements H to Ne, with peaks at He and Ne, and a dip at Li.
There are ionisation energy trends within periods and groups

Ionisation energy across a period

  • Across a period, ionisation energy increases because:

    • Nuclear charge increases, pulling electrons closer

    • Atomic radius decreases, reducing the distance to outer electrons

    • Shielding stays roughly constant, since electrons are added to the same shell

    • Outer electrons are held more tightly, so more energy is needed to remove them

Dips in the trend

  • There is a slight decrease in IE1 between beryllium and boron as the fifth electron in boron is in the 2p subshell, which is further away from the nucleus than the 2s subshell of beryllium

    • Beryllium has a first ionisation energy of 900 kJ mol-1 as its electron configuration is 1s2 2s2

    • Boron has a first ionisation energy of 800 kJ mol-1 as its electron configuration is 1s2 2s2 2px1

  • There is a slight decrease in IE1 between nitrogen and oxygen due to spin-pair repulsion in the 2px orbital of oxygen

    • Nitrogen has a first ionisation energy of 1400 kJ mol-1 as its electron configuration is 1s2 2s2 2px1 2py1 2pz1

    • Oxygen has a first ionisation energy of 1310 kJ mol-1 as its electron configuration is 1s2 2s2 2px2 2py1 2pz1

    • In oxygen, there are 2 electrons in the 2porbital, so the repulsion between those electrons makes it slightly easier for one of those electrons to be removed

Ionisation energy down a group

  • The ionisation energy down a group decreases due to the following factors:

    • The number of protons in the atom is increased, so the nuclear charge increases

    • But, the atomic radius of the atoms increases as you add more shells of electrons, making the atoms bigger

    • So, the distance between the nucleus and outer electron increases as you descend the group

    • The shielding by inner shell electrons increases as there are more shells of electrons

    • These factors outweigh the increased nuclear charge, meaning it becomes easier to remove the outer electron as you descend a group

    • So, the ionisation energy decreases

Across a period: Ionisation energy increases

Down a group: Ionisation energy decreases

Increase in nuclear charge

Increase in nuclear charge

The same number of shells

Increased number of shells

Distance from the outer electron to the nucleus decreases

Distance from the outer electron to the nucleus increases

Shielding remains relatively constant

Shielding increases

Decreased atomic / ionic radius

Increased atomic / ionic radius

The attraction between the outer electron and the nucleus gets stronger so the outer electron is harder to remove

The attraction between the outer electron and the nucleus gets weaker so the outer electron is easier to remove

Successive Ionisation Energies of an Element

  • Successive ionisation energies of an element increase

  • This is because once the outer electron is removed, the atom becomes a positive ion, making further electron removal more difficult

  • As more electrons are removed:

    • Shielding decreases

    • The proton-to-electron ratio increases

    • Attraction between nucleus and remaining electrons increases

  • The increase is not constant, it depends on the electronic configuration

  • Taking calcium as an example:

Table showing the successive ionisation energies of calcium table

Electronic Configuration

1s2 2s2 2p6 3s2 3p6 4s1

1s2 2s2 2p6 3s2 3p6 

1s2 2s2 2p6 3s2 3p5

 1s2 2s2 2p6 3s2 3p4

IE

First

Second

Third

Fourth

IE (kJ mol-1)

590

1150

4940

6480

Successive ionisation energies of calcium

Graph showing ionisation energy versus electrons removed. Labels indicate shell changes with big jumps and subshell changes with small jumps.
Graph to show the successive ionisation energies for the element calcium
  • The first ionisation energy is relatively low due to spin-pair repulsion in the 4s orbital

  • The second electron is harder to remove because this repulsion is no longer present

  • The third ionisation energy increases sharply as the electron is removed from the 3p subshell, which is closer to the nucleus

  • The fourth electron is also more difficult to remove due to reduced spin-pair repulsion within the 3p orbital

  • Successive ionisation energies always increase because electrons are being removed from an increasingly positive ion

  • A large jump in ionisation energy indicates a change in shell, while smaller jumps reflect changes within the same shell or subshell

Using successive ionisation data

  • Helps predict or confirm electronic configuration.

  • Identifies the number of outer-shell electrons.

  • Indicates the group number by locating the position of a significant jump in ionisation energy.

  • Commonly applied to elements like sodium (Na), magnesium (Mg), and aluminium (Al) to deduce their place in the Periodic Table.

Successive ionisation energies table

Element

Atomic Number

Ionisation Energy (kJ mol-1)

First

Second

Third

Fourth

Na

11

494

4560

6940

9540

Mg

12

736

1450

7740

10500

Al

13

577

1820

2740

11600

Sodium

  • A large increase between the first and second ionisation energies shows it is much easier to remove the first electron

  • This means the first electron removed is from the valence shell, so Na is in Group 1

  • The jump corresponds to removing an electron from the 3s to the full 2p subshell

    • Na: 1s2 2s2 2p6 3s1

Magnesium

  • A large increase between the second and third ionisation energies suggests the first two electrons are easier to remove

  • Therefore, Mg has two valence electrons, placing it in Group 2

  • The jump corresponds to removing an electron from the 3s to the full 2p subshell:

    • Mg: 1s2 2s2 2p6 3s2

Aluminium

  • A large increase between the third and fourth ionisation energies shows the first three electrons are easier to remove

  • These are the 3p and 3s electrons, which are farther from the nucleus and experience less nuclear charge than 2p electrons

  • This suggests Al has three valence electrons, so it belongs to Group 13 (Group III)

  • The jump corresponds to removing an electron from the third shell to the second shell:

    • Al: 1s2 2s2 2p6 3s2 3p1

Examiner Tips and Tricks

  • It is easy to remove electrons from a full subshell as they undergo spin-pair repulsion.

  • It gets more difficult to remove electrons from principal quantum shells that get closer to the nucleus as there is less shielding and an increase in attractive forces between the electrons and nuclear charge.

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