Ionisation Energy Trends (Cambridge (CIE) AS Chemistry): Revision Note
Exam code: 9701
Trends in Ionisation Energy
Ionisation energies show periodicity, a recurring trend across each period of the Periodic Table
As you move left to right across a period, first ionisation energy generally increases
This trend is linked to the electronic configuration of elements:
Group 1 metals (e.g. Na) have low first ionisation energies because they have a single outer electron that is easy to remove
Noble gases (e.g. Ne, Ar) have very high ionisation energies due to their full outer shells and strong nuclear attraction
There are four factors that affect ionisation energy
Nuclear charge
Distance from the nucleus
Electron shielding
Spin-pair repulsion
Nuclear charge (number of protons)
As atomic number increases, so does the positive charge of the nucleus
A higher nuclear charge creates a stronger electrostatic attraction between the nucleus and outer electrons
Therefore more energy is required to remove the electron means a higher ionisation energy
Distance from the nucleus (atomic radius)
Outer electrons that are further from the nucleus experience weaker attraction
The greater the distance, the easier it is to remove the electron
Ionisation energy decreases with increased distance from the nucleus
Electron shielding (inner shell repulsion)
Electrons in inner shells repel electrons in outer shells and partially block the attraction of the nucleus
This is known as the shielding effect
More inner electron shells means greater shielding and therefore a lower ionisation energy
Spin-pair repulsion (electron–electron repulsion)
In orbitals that contain two electrons, the electrons experience repulsion due to their like charges
This repulsion slightly reduces the energy needed to remove one of the electrons
This explains small drops in ionisation energy across a period, such as:
Oxygen vs nitrogen (O’s paired 2p electrons are easier to remove)
Aluminium vs magnesium (Al’s 3p¹ electron is higher in energy than Mg’s 3s²)
Ionisation Energy & the Periodic Table
Across a period:
first ionisation energy increases due to higher nuclear charge and same shielding
Down a group:
first ionisation energy decreases due to greater atomic radius and more shielding
Graph of first ionisation energies from H to Na

Ionisation energy across a period
Across a period, ionisation energy increases because:
Nuclear charge increases, pulling electrons closer
Atomic radius decreases, reducing the distance to outer electrons
Shielding stays roughly constant, since electrons are added to the same shell
Outer electrons are held more tightly, so more energy is needed to remove them
Dips in the trend
There is a slight decrease in IE1 between beryllium and boron as the fifth electron in boron is in the 2p subshell, which is further away from the nucleus than the 2s subshell of beryllium
Beryllium has a first ionisation energy of 900 kJ mol-1 as its electron configuration is 1s2 2s2
Boron has a first ionisation energy of 800 kJ mol-1 as its electron configuration is 1s2 2s2 2px1
There is a slight decrease in IE1 between nitrogen and oxygen due to spin-pair repulsion in the 2px orbital of oxygen
Nitrogen has a first ionisation energy of 1400 kJ mol-1 as its electron configuration is 1s2 2s2 2px1 2py1 2pz1
Oxygen has a first ionisation energy of 1310 kJ mol-1 as its electron configuration is 1s2 2s2 2px2 2py1 2pz1
In oxygen, there are 2 electrons in the 2px orbital, so the repulsion between those electrons makes it slightly easier for one of those electrons to be removed
Ionisation energy down a group
The ionisation energy down a group decreases due to the following factors:
The number of protons in the atom is increased, so the nuclear charge increases
But, the atomic radius of the atoms increases as you add more shells of electrons, making the atoms bigger
So, the distance between the nucleus and outer electron increases as you descend the group
The shielding by inner shell electrons increases as there are more shells of electrons
These factors outweigh the increased nuclear charge, meaning it becomes easier to remove the outer electron as you descend a group
So, the ionisation energy decreases
Table summarising ionisation energy trends across a period & down a group
Across a period: Ionisation energy increases | Down a group: Ionisation energy decreases |
---|---|
Increase in nuclear charge | Increase in nuclear charge |
The same number of shells | Increased number of shells |
Distance from the outer electron to the nucleus decreases | Distance from the outer electron to the nucleus increases |
Shielding remains relatively constant | Shielding increases |
Decreased atomic / ionic radius | Increased atomic / ionic radius |
The attraction between the outer electron and the nucleus gets stronger so the outer electron is harder to remove | The attraction between the outer electron and the nucleus gets weaker so the outer electron is easier to remove |
Successive Ionisation Energies of an Element
Successive ionisation energies of an element increase
This is because once the outer electron is removed, the atom becomes a positive ion, making further electron removal more difficult
As more electrons are removed:
Shielding decreases
The proton-to-electron ratio increases
Attraction between nucleus and remaining electrons increases
The increase is not constant, it depends on the electronic configuration
Taking calcium as an example:
Table showing the successive ionisation energies of calcium table
Electronic Configuration | 1s2 2s2 2p6 3s2 3p6 4s1 | 1s2 2s2 2p6 3s2 3p6 | 1s2 2s2 2p6 3s2 3p5 | 1s2 2s2 2p6 3s2 3p4 |
IE | First | Second | Third | Fourth |
IE (kJ mol-1) | 590 | 1150 | 4940 | 6480 |
Successive ionisation energies of calcium

The first ionisation energy is relatively low due to spin-pair repulsion in the 4s orbital
The second electron is harder to remove because this repulsion is no longer present
The third ionisation energy increases sharply as the electron is removed from the 3p subshell, which is closer to the nucleus
The fourth electron is also more difficult to remove due to reduced spin-pair repulsion within the 3p orbital
Successive ionisation energies always increase because electrons are being removed from an increasingly positive ion
A large jump in ionisation energy indicates a change in shell, while smaller jumps reflect changes within the same shell or subshell
Using successive ionisation data
Helps predict or confirm electronic configuration.
Identifies the number of outer-shell electrons.
Indicates the group number by locating the position of a significant jump in ionisation energy.
Commonly applied to elements like sodium (Na), magnesium (Mg), and aluminium (Al) to deduce their place in the Periodic Table.
Successive ionisation energies table
Element | Atomic Number | Ionisation Energy (kJ mol-1) | |||
---|---|---|---|---|---|
First | Second | Third | Fourth | ||
Na | 11 | 494 | 4560 | 6940 | 9540 |
Mg | 12 | 736 | 1450 | 7740 | 10500 |
Al | 13 | 577 | 1820 | 2740 | 11600 |
Sodium
A large increase between the first and second ionisation energies shows it is much easier to remove the first electron
This means the first electron removed is from the valence shell, so Na is in Group 1
The jump corresponds to removing an electron from the 3s to the full 2p subshell
Na: 1s2 2s2 2p6 3s1
Magnesium
A large increase between the second and third ionisation energies suggests the first two electrons are easier to remove
Therefore, Mg has two valence electrons, placing it in Group 2
The jump corresponds to removing an electron from the 3s to the full 2p subshell:
Mg: 1s2 2s2 2p6 3s2
Aluminium
A large increase between the third and fourth ionisation energies shows the first three electrons are easier to remove
These are the 3p and 3s electrons, which are farther from the nucleus and experience less nuclear charge than 2p electrons
This suggests Al has three valence electrons, so it belongs to Group 13 (Group III)
The jump corresponds to removing an electron from the third shell to the second shell:
Al: 1s2 2s2 2p6 3s2 3p1
Examiner Tips and Tricks
It is easy to remove electrons from a full subshell as they undergo spin-pair repulsion.
It gets more difficult to remove electrons from principal quantum shells that get closer to the nucleus as there is less shielding and an increase in attractive forces between the electrons and nuclear charge.
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