Set B (AQA GCSE Biology): Exam Questions

Exam code: 8461

7 hours39 questions
1a3 marks

This question is about how plants defend themselves against pathogens. 

Complete the sentences by picking one of the words in bold in each set of [ ] brackets. 

  1. Plant cells have physical barriers to defend themselves against the entry of pathogens. An example is the cell wall made of [starch / chitin / cellulose]  that acts as a barrier.

  2. A physical barrier around the outside of the leaf is called the [waxy cuticle / guard cells / palisade mesophyll].

  3. The outside of trees have a thick protective layer of dead cells around the stems called [cork / xylem / bark].

1b1 mark

The passion flower (Passiflora) is a genus of plant that produces leaves with small yellow spots, as shown in Figure 3. 

Figure 3

passion-flower-leaf-1

The spots on the leaves have evolved to mimic the eggs of butterflies.

What category of adaptation does this feature fall into?

Pick one option:

  • Physical

    • Mechanical

    • Chemical

1c2 marks

Suggest why having a mimicry of butterfly eggs on the leaves might benefit the plant.

1d1 mark

Methods to avoid herbivory are widespread in many different species of plants. 

Whilst these adaptations help to protect plant tissues from damage, they also protect from the entry of pathogens.

Suggest why does a defence against herbivores also defend against pathogens?

2a1 mark

Figure 1 shows a cross section of a leaf.

Figure 1

plant-tissue

Which of the options below correctly describes the organisational structure of a leaf?

  • Cell

  • Tissue

  • Organ

  • Organ system

2b2 marks

Name structure X and Y in Figure 1.

2c2 marks

Describe how structure X (in Figure 1) helps control gas exchange in response to changing environmental conditions.

2d1 mark

Which feature of palisade mesophyll cells makes them adapted for efficient photosynthesis?

  • They are transparent to allow light to pass through.

  • They have a thick waxy coating.

  • Contain lots of mitochondria

  • Contain lots of chloroplasts

3a1 mark

Which of the following options is not a non-specific defence against pathogens?

  • Skin

  • White blood cell

  • Trachea

  • Stomach

3b2 marks

Figure 1 shows the process of phagocytosis. 

Figure 1

phagocytosis-1

Describe the stages of phagocytosis shown in the image. 

3c
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2 marks

Table 1 shows how the number of white blood cells in the blood changes before and during an infection with a pathogen. 

Table 1

 

Before infection

During infection

Number of white blood cells per dm3 of blood

9 x 109

7 x 1010

Calculate the difference in the number of white blood cells per dm3 of blood before and during an infection. 

3d2 marks

State two roles of white blood cells during an infection other than phagocytosis.

4a3 marks

Describe and explain the changes that occur in the body during exercise.

4b3 marks

A group of athletes carried out a 9-month training programme.

Figure 1 shows the effect of the same type and amount of exercise on one of the athlete’s heart rate before and after the training programme.

Figure 1

training-programmes-3b

Calculate the percentage change in the athletes heart rate 10 minutes after the start of exercise.

Show your working.

4c5 marks

The volume of blood pumped out of the left side of the heart in one beat is the stroke volume.

Figure 2 shows the relationship between the athlete's stroke volume and heart rate in beats per minute both before and after completing the training programme.

Figure 2

heart-rate-and-exercise-q3c

The cardiac output of the heart can be calculated by:

cardiac output = heart rate × stroke volume

Calculate the difference in cardiac output of the athlete 20 minutes after the start of exercise before and after the training programme. 

Show clearly how you calculated your answer.

4d2 marks

Figure 1 shows that the heart of the athlete after completing the training programme beats more slowly than before the training programme.

Use information from Figure 2 to explain why.

4e3 marks

Explain how an increased cardiac output helps the athlete to maximise their performance.

5a1 mark

A student set up an investigation into the limiting factors of photosynthesis.

His set up is shown in Figure 5 below:

Figure 5

photosynthesis-prac-1

Identify the limiting factor being investigated in this practical.

5b2 marks

The student carried out an investigation to find out the effect of light intensity on the rate of photosynthesis by moving the light source further and further away from the aquatic plant and counting the bubbles produced per minute at each distance.

The results can be seen in Table 1 below:

Table 1

Distance between the aquatic plant and lamp in cm

Number of bubbles counted in 1 minute

0

29

10

21

20

45

30

15

40

10

One of the results recorded was an anomaly.

Identify which result was anomalous and explain your choice.

5c1 mark

Describe the trend shown by the data in Table 1.

5d1 mark

The student evaluated his method and decided that counting bubbles is an inaccurate way of measuring the rate of photosynthesis for two reasons.

  1. It does not take into account the fact that there may be bubbles of different sizes

  2. Tiny bubbles may be hard to see and so may not be counted at all

Suggest a more accurate method which could be used to collect information about the amount of oxygen gas produced as the aquatic plant photosynthesizes.

6a1 mark

Both muscle and sperm cells are specialised animal cells. The nucleus of a muscle cell is different to the nucleus of a sperm cell.

Describe one way in which the nucleus is different between these two cells.

6b2 marks

All specialised cells are adapted to carry out their function. 

Explain two adaptations of a sperm cell that enables it to carry out its function. 

6c2 marks

Specialised cells develop from unspecialised cells by differentiation when an organism develops.

Describe what happens when a cell differentiates.

6d2 marks

Compare the process of differentiation in animals and plants.

7a3 marks

Listing the key structures, describe the path of air from the trachea to the lung capillaries.

7b4 marks

Explain the changes that occur in the thorax (chest cavity) when a person breathes in.

7c3 marks

During inhalation and exhalation, the intercostal muscles work as antagonistic pairs.

With reference to the intercostal muscles, explain what antagonistic pairs are and how they work.

7d2 marks

The internal intercostal muscles are predominantly active during strenuous activity.

Why is this?

8a6 marks

Between 2013 and 2016, the Ebola virus was responsible for around 12 000 deaths.

Almost all of the victims were in Western Africa.

There is currently no clinically approved medicine available to treat individuals infected with the Ebola virus. 

Drug companies have developed a new drug to treat Ebola.

Describe the stages of testing this new drug must go through before it can be used on patients. 

8b1 mark

How are new drug compounds discovered?

8c2 marks

A potential vaccine for Ebola began development in 2003.

In 2014, the World Health Organisation ruled that it would approve the vaccine for use on individuals recently infected with Ebola.

At that time the vaccine had not yet been tested on humans.

Suggest two reasons reason why the World Health Organisation deemed it ethical to use the vaccine on infected individuals despite it not having been tested on humans.

9a3 marks

Figure 4 shows two guard cells surrounding an open stoma and two guard cells surrounding a closed stoma.

Figure 4

EpsGK5Sz_4

When light intensity is low, the stoma closes.

Describe how the stoma close.

9b1 mark

Guard cells have cell walls with unevenly distributed cellulose.

Suggest why this is important.

9c1 mark

A student investigated the effect of varying concentrations of salt solution on the opening of stomata on the lower epidermis of a leaf.

Her results are shown in Table 2.

Table 2

Concentration of salt solution in mol /dm3

Number of stomata in field of view

Number of open stomata in field of view

Percentage (%) of open stomata in field of view

0.0

15

15

100

0.2

18

18

100

0.4

13

11

85

0.6

16

10

65

0.8

15

6

40

1.0

18

4

22

The student calculated one of the percentages for open stomata in the field of view incorrectly.

Identify for which solution the result was incorrect and give the correct value.

9d1 mark

Write a conclusion for the results of the experiment as shown in Table 2.

9e3 marks

The student measured the real diameter for the field of view to be 0.475 mm.

Calculate the total number of stomata per mm2 of the leaf epidermis placed in 0.8 mol / dm3 salt solution if the value of π (pi) is 3.14.

Show your working.

10a4 marks

The liver has many roles in the body.

As well as detoxifying a number of substances, the liver also produces bile, a yellowish-brown fluid that is stored in the gallbladder.

One of the main components of bile is bilirubin.

The liver produces this yellow-brown pigment when it breaks down haemoglobin released from broken down red blood cells.

Explain how red blood cells transport oxygen from the alveoli to other parts of the body.

10b2 marks

The liver is also responsible for producing much of the body’s cholesterol.

If levels of cholesterol in the body are too high, there is a risk that solid ‘gallstones’ may form in the liquid bile.

The gallbladder is connected to the small intestine by a narrow duct (tube) which can become blocked by these gallstones.

It is not uncommon for individuals with gallstones to form very pale faeces.

Suggest why.

10c3 marks

One form of cholesterol found in the blood is LDL.

Suggest the consequences of an individual having too high a level of LDL cholesterol in their blood.

11a1 mark

Figure 1 shows two plant cells.

Figure 1

plant-cells_hypertonic

Which of the plant cells above was placed in a solution with a lower solute concentration than the cell contents?

11b3 marks

Explain what has happened to the plant cell you identified in part (a).

11c3 marks

When placed in different solutions, animal cells will also change.

Figure 2 below shows a red blood cell.

Figure 2

red-blood-cell

Describe what would happen if a red blood cell was put into a solution with a lower solute concentration than the cell contents and explain why this would be different from what would happen to a plant cell.

11d3 marks

Hereditary spherocytosis is a rare inherited condition that produces red blood cells with an abnormal spherical shape, as shown in Figure 3.

Figure 3

red-blood-cell_spherocytosis

Suggest the possible impact of this condition on a sufferer.