Set B (AQA GCSE Biology): Exam Questions

Exam code: 8461

7 hours39 questions
1a1 mark

Figure 1 shows a cross section of a leaf.

Figure 1

plant-tissue

Which of the options below correctly describes the organisational structure of a leaf?

  • Cell

  • Tissue

  • Organ

  • Organ system

1b2 marks

Name structure X and Y in Figure 1.

1c2 marks

Describe how structure X (in Figure 1) helps control gas exchange in response to changing environmental conditions.

1d1 mark

Which feature of palisade mesophyll cells makes them adapted for efficient photosynthesis?

  • They are transparent to allow light to pass through.

  • They have a thick waxy coating.

  • Contain lots of mitochondria

  • Contain lots of chloroplasts

2a1 mark

Which of the following options is not a non-specific defence against pathogens?

  • Skin

  • White blood cell

  • Trachea

  • Stomach

2b2 marks

Figure 1 shows the process of phagocytosis. 

Figure 1

phagocytosis-1

Describe the stages of phagocytosis shown in the image. 

2c
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2 marks

Table 1 shows how the number of white blood cells in the blood changes before and during an infection with a pathogen. 

Table 1

 

Before infection

During infection

Number of white blood cells per dm3 of blood

9 x 109

7 x 1010

Calculate the difference in the number of white blood cells per dm3 of blood before and during an infection. 

2d2 marks

State two roles of white blood cells during an infection other than phagocytosis.

3a1 mark

Higher Tier Only

Monoclonal antibodies can be used to determine blood hormone levels.

Pregnancy test strips use monoclonal antibodies.

The hormone HCG is produced in the placenta in pregnant women.

The kidneys excrete HCG.

Figure 1 shows three pregnancy test strips.

Figure 1

q1a_monoclonal-antibodies_infection-and-response_gcse_aqa_biology

Which test strip would belong to a woman who is not pregnant?

3b2 marks

Higher Tier Only

Pregnancy testing uses monoclonal antibodies.

Give two other uses of monoclonal antibodies. 

3c6 marks

Higher Tier Only

Figure 2 shows the parts of a pregnancy test strip.

Figure 2

q1c_monoclonal-antibodies_infection-and-response_gcse_aqa_biology

If there is no HCG in a woman's urine, she would see a negative test result.

Explain how the pregnancy test strip works to display a negative result. 

4a3 marks

Describe and explain the changes that occur in the body during exercise.

4b3 marks

A group of athletes carried out a 9-month training programme.

Figure 1 shows the effect of the same type and amount of exercise on one of the athlete’s heart rate before and after the training programme.

Figure 1

training-programmes-3b

Calculate the percentage change in the athletes heart rate 10 minutes after the start of exercise.

Show your working.

4c5 marks

The volume of blood pumped out of the left side of the heart in one beat is the stroke volume.

Figure 2 shows the relationship between the athlete's stroke volume and heart rate in beats per minute both before and after completing the training programme.

Figure 2

heart-rate-and-exercise-q3c

The cardiac output of the heart can be calculated by:

cardiac output = heart rate × stroke volume

Calculate the difference in cardiac output of the athlete 20 minutes after the start of exercise before and after the training programme. 

Show clearly how you calculated your answer.

4d2 marks

Figure 1 shows that the heart of the athlete after completing the training programme beats more slowly than before the training programme.

Use information from Figure 2 to explain why.

4e3 marks

Explain how an increased cardiac output helps the athlete to maximise their performance.

5a
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3 marks

Higher Tier Only

Complete Table 1 to show the correct size conversions. Record your answers as ordinary numbers.

Table 1

Measurement

Unit

Conversion

Unit

15.3

cm

 

µm

3 x 10-6

mm

 

µm

0.25

m

 

µm

5b
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2 marks

Higher Tier Only

The mass of bacterial cells was measured in femtograms (fg).

1 femtogram = 1 x 10-15g

Figure 5

bacterial-growth-2

Calculate the mass of bacteria, in grams, immediately after binary fission when the cell growth rate was 0.1 fg s-1.

Give your answer in standard form.

5c
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3 marks

The electron micrograph shows some cellular structure in a leaf. A student uses their ruler to measure the scale bar, which they find to be 1.5 cm.

Figure 6

0-I1t0DA_3

Calculate the magnification of the image.

6a1 mark

A group of scientists investigated the rates of absorption of different sugars using two pieces of the intestine.

One piece of the intestine was poisoned with cyanide which stops cellular respiration.

The results are shown in Table 3 below.

Table 3

Sugar

Absorption rate (arbitrary units)

Healthy intestine

Intestine poisoned with cyanide

A

108

56

B

31

30

C

33

32

D

84

23

Which of the sugars in Table 3 are absorbed by active transport?

6b3 marks

Explain why you chose these sugars, using evidence from Table 3.

6c2 marks

One of the scientists states ‘All four of the sugars we investigated can be absorbed by diffusion.

Determine whether the statement is correct or incorrect. Justify your answer.

6d1 mark

One of the sugars absorbed by active transport is glucose.

Xylose is a sugar that is the same size as glucose, but it is not absorbed by active transport.

Suggest a reason why.

6e3 marks

The wall of the small intestine contains smooth muscle cells.

Muscle cells convert soluble glucose into glycogen which is insoluble in water.

Suggest an explanation as to why it is essential that muscle cells store glucose as glycogen.

7a
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2 marks

An investigation was carried out to test the effect of temperature on the rate of photosynthesis of pondweed.

The volume of oxygen produced per hour was measured. The results can be seen in Table 1.

Table 1

temp-and-photosynthesis

Calculate the mean rate of photosynthesis per hour when the temperature was 45 °C.

7b
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5 marks

Plot the results from Table 1 onto an appropriate graph using the graph paper in Figure 2.

Figure 2

graph-paper-1
7c4 marks

Describe and explain the results shown in the graph.

7d4 marks

Higher Tier Only

A farmer growing strawberries in his greenhouse used the results in Table 1 to decide on the best temperature for his greenhouse. He decided to heat the greenhouse to 30 °C.

When the farmer measured the rate of photosynthesis of his plants, he found the rate to be 11.5% slower than the data suggested.

Calculate the rate of photosynthesis that the farmer actually achieved at 30 °C.

7e2 marks

Higher Tier Only

Suggest why the farmer may not have achieved a rate of photosynthesis as high as the data in Figure 2 predicted.

8a3 marks

The Human Immunodeficiency Virus (HIV) is a virus which emerged during the 1980s and has since infected millions of people globally. 

Explain why HIV sufferers may have an increased chance of suffering from communicable diseases.

8b2 marks

Figure 3 shows the percentage of the population with type 2 diabetes and the mean body mass of the population, from 1990 to 2000.

Figure 3

MHg7VH0v_3

Explain why the study chose to focus on body mass index.

8c
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2 marks

Tuberculosis (TB) is a bacterial infection caused by Mycobacterium tuberculosis which can be spread through inhaling tiny droplets from the coughs or sneezes of an infected person.

Most infections can be latent and show no sign of disease, but around 10% of infections can progress to an active form of the disease which can be fatal if left untreated.

Table 1 shows the number of new cases of TB and the number of deaths in selected countries.

Table 1

Country

Number of new TB cases per 100 000 people

Number of deaths from TB per 100 000 people

Case fatality rate (%)

China

100

15

15

Ethiopia

385

92

 

India

192

38

19.8

United Kingdom

13

1

7.7

United States of America

7

0

0

Calculate the case fatality rate for Ethiopia.

8d3 marks

Suggest why the number of new cases of TB (as shown in Table 1) is higher in some countries than others.

9a6 marks

Multiple sclerosis (MS) is a condition which affects the central nervous system caused by the immune system mistakenly attacking the brain and nerves. MS can lead to symptoms which flare up periodically, such as fatigue, vision problems, muscle spasms, mobility problems, difficulty in thinking, learning or planning, amongst others.

There are several different treatments for MS; two are considered here.

  1. Stem cell treatments:  Healthy cells found in the patients bone marrow can be used to rebuild the immune system. Must be used in combination with chemotherapy to remove the harmful immune cells.

  2. Disease modifying therapies (DMT): Medicines that can reduce the number of relapses a patient suffers and reduce the symptoms of MS. An example of a DMT is a drug called Lemtrada.

Table 1 gives some extra information about these two treatments for MS.

Table 1

Treatment type

Side effects

Cost

Success rate

Stem Cells

Risk of developing infections, cancer or fertility issues

Chemotherapy may lead to fatigue and appetite loss, hair loss

1 in 330 people may die

$550 000 per treatment

94% success rate (condition stabilised) over 4 years

Can provide a cure for MS

Disease modifying therapies (e.g. Lemtrada)

Headaches, rashes, nausea, under or overactive thyroid, changes in blood pressure or kidney problems

$340 000 for 5 years of treatment

82% success rate (condition stabilised) over 4 years.

Does not provide a cure.

Evaluate the use of stem cells and disease modifying therapies to treat multiple sclerosis.

9b4 marks

Heart attacks may be caused if a coronary artery becomes blocked and the flow of oxygenated blood is restricted. This can result in damage to the heart muscle tissue.

Suggest how embryonic cells could be used to treat a patient after a heart attack.

9c2 marks

A patient who has suffered a heart attack was offered treatment using stem cells from an embryo, but refused due to the use of embryonic stem cells.

Suggest a reason for this decision.

9d4 marks

The patient mentioned in part (c) was offered treatment using their own healthy stem cells removed from their heart tissue.

Evaluate the decision to use these stem cells as an alternative to embryonic stem cells in the treatment of the damaged heart tissue.