Half Equations & Ionic Equations (AQA GCSE Combined Science: Trilogy): Revision Note

Exam code: 8464

Stewart Hird

Written by: Stewart Hird

Reviewed by: Richard Boole

Updated on

Half equations & ionic equations

Higher tier only

What is a half equation?

  • A half equation shows what happens to one species during a redox reaction

  • Each half equation shows:

    • Atoms balanced

    • Charges balanced

    • The gain or loss of electrons

  • You need two half equations to make a full redox equation

How to write a half equation

Steps to write a half equation:

  1. Identify the species involved, e.g. a metal ion being reduced or a non-metal ion being oxidised

  2. Write the correct formula and charge for the species before and after the change

  3. Balance the atoms on both sides of the equation

  4. Add electrons (e⁻) to one side to balance the charges

  5. Check that both atoms and charges are balanced

Examples of half equations

  • Copper(II) ions gains electrons to form copper metal

  1. The species involved are:

    • Copper(II) ions as a reactant

    • Copper as a product

  2. The formulas and charges are:

    • Copper(II) ions = Cu2+

    • Copper = Cu

  3. Balancing the atoms on both sides of the equation gives:

    • Cu2+ → Cu

  4. Two electrons are required, on the reactant side, to balance the equation:

    • Cu2+ + 2e- → Cu

  5. Check that the atoms and charges are balanced:

    • Atoms

      • Each side has one Cu

    • Charges

      • A 2+ charge on the copper(II) ion

      • A 1- charge on each electron = 2- charge overall

      • The 2+ and 2- charges cancel

  • Bromide ions lose electrons to form bromine

  1. The species involved are:

    • Bromide ions as a reactant

    • Bromine as a product

  2. The formulas and charges are:

    • Bromide ions = Br-

    • Bromine = Br2

  3. Balancing the atoms on both sides of the equation gives:

    • 2Br- → Br2

  4. Two electrons are required to balance the equation:

    • 2Br- - 2e- → Br2

    • This is more commonly written as:

    • 2Br- → Br2 + 2e-

  5. Check that the atoms and charges are balanced:

    • Atoms

      • Each side has two Br

    • Charges

      • Bromide ions each have a 1− charge

        • So, two bromide ions give a total charge of 2−

      • Two electrons (1− each) are released to balance this

Examiner Tips and Tricks

For half equations:

  • Electrons on the right

    • The species is losing electrons (oxidation)

  • Electrons on the left

    • The species is gaining electrons (reduction)

This links to the mnemonic OIL RIG

  • Oxidation Is Loss

  • Reduction Is Gain

What is an ionic equation?

  • An ionic equation shows only the particles that change during a reaction

    • Two half equations can be combined to form an ionic equation

  • They are useful for reactions in solution such as:

    • Neutralisation

    • Precipitation

How to write an ionic equation

Steps to write an ionic equation:

  1. Write the full balanced chemical equation

  2. Split aqueous compounds into ions

    • Only aqueous substances are split into ions

    • Solids, liquids, and gases stay in their molecular form

  3. Write the ionic form of the equation

  4. Cancel the spectator ions

    • Spectator ions do not take part in the chemical change

  5. Write the final ionic equation

    • Ionic equations must be balanced for both atoms and charge

Examples of ionic equations

  • The neutralisation reaction of hydrochloric acid and sodium hydroxide

  1. The full balanced chemical equation is:

    • HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)

  2. The aqueous ions are:

    • HCl → H+ and Cl-

    • NaOH → Na+ and OH-

    • NaCl → Na+ and Cl-

    • H2O stays as a molecule

  3. The ionic form of the equation is:

    • H+ + Cl- + Na+ + OH- → Na+ + Cl- + H2O

  4. Cancelling out the spectator ions:

    • Na+ and Cl- are spectator ions because they appear unchanged on both sides

    • H+ + Cl- + Na+ + OH-Na+ + Cl- + H2O

  5. The final ionic equation is:

    • H+ (aq) + OH- (aq) → H2O (l)

Worked Example

The precipitation reaction of lead(II) nitrate and potassium iodide.

A student mixes aqueous solutions of lead(II) nitrate and potassium iodide. A yellow precipitate of lead(II) iodide forms.

Write the ionic equation for the formation of the yellow precipitate.

Answer:

  1. The full balanced chemical equation is:

    • Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)

  2. The aqueous ions are:

    • Pb(NO3)2 → Pb2+ and 2NO3-

    • KI → K+ and I-

    • KNO3 → K+ and NO3-

    • PbI2 is a solid, so it remains as PbI2 (s)

  3. The ionic form of the equation is:

    • Pb2+ + 2NO3- + 2K+ + 2I- → PbI2 + 2K+ + 2NO3-

  4. Cancelling out the spectator ions:

    • 2NO3- and 2K+ are unchanged on both sides

  5. The final ionic equation is:

    • Pb2+ + 2I- → PbI2 (s)

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.