Differentiating Powers of x (DP IB Applications & Interpretation (AI)): Revision Note

Differentiating Powers of x

What is differentiation?

  • Differentiation is the process of finding an expression for the derivative (gradient function) of a function from an expression for the function

How do I differentiate powers of x?

  • Powers of x are differentiated according to the following formula:

    • Ifspace f left parenthesis x right parenthesis equals x to the power of n thenspace f to the power of apostrophe left parenthesis x right parenthesis equals n x to the power of n minus 1 end exponent where n element of straight integer numbers

    • This is given in the formula booklet

Examiner Tips and Tricks

It is possible to differentiate x to the power of n for any power of x. For your AI SL course, however, you only need to be able to find derivatives for integer powers of x. I.e., x to the power of n where n equals 0 comma space plus-or-minus 1 comma space plus-or-minus 2 comma space plus-or-minus 3 comma space...

  • If the power of x term is multiplied by a constant then the derivative is also multiplied by that constant

    • Ifspace f left parenthesis x right parenthesis equals a x to the power of n thenspace f to the power of apostrophe left parenthesis x right parenthesis equals a n x to the power of n minus 1 end exponent where n element of straight integer numbers and a is a constant

  • The alternative notation (tospace f to the power of apostrophe left parenthesis x right parenthesis) is to use fraction numerator straight d y over denominator straight d x end fraction

    • If y equals a x to the power of n then fraction numerator straight d y over denominator straight d x end fraction equals a n x to the power of n minus 1 end exponent

      • e.g.  If y equals negative 4 x to the power of 5 then fraction numerator straight d y over denominator straight d x end fraction equals negative 4 cross times 5 cross times x to the power of 5 minus 1 end exponent equals negative 20 x to the power of 4

  • Don't forget these two special cases:

    • Ifspace f left parenthesis x right parenthesis equals a x thenspace f to the power of apostrophe left parenthesis x right parenthesis equals a

      • e.g.  If y equals 6 x then fraction numerator straight d y over denominator straight d x end fraction equals 6

    • Ifspace f left parenthesis x right parenthesis equals a thenspace f to the power of apostrophe left parenthesis x right parenthesis equals 0

      • e.g.  If y equals 5 then fraction numerator straight d y over denominator straight d x end fraction equals 0

  • Functions involving fractions with denominators in terms of x will need to be rewritten as negative powers of x first

    • e.g.  Ifspace f left parenthesis x right parenthesis equals 4 over x then rewrite asspace f left parenthesis x right parenthesis equals 4 x to the power of negative 1 end exponent before differentiating

How do I differentiate sums and differences of powers of x?

  •  For an expression that is a sum or difference of powers of x, just differentiate term by term

    • e.g.  Ifspace f left parenthesis x right parenthesis equals 5 x to the power of 4 plus 2 x cubed minus 3 x plus 4 then
      space f to the power of apostrophe left parenthesis x right parenthesis equals 5 cross times 4 x to the power of 4 minus 1 end exponent plus 2 cross times 3 x to the power of 3 minus 1 end exponent minus 3 plus 0
      space f to the power of apostrophe left parenthesis x right parenthesis equals 20 x cubed plus 6 x squared minus 3

  • Products and quotients cannot be differentiated in this way so would need to be expanded/simplified first

    • e.g.  Ifspace f left parenthesis x right parenthesis equals left parenthesis 2 x minus 3 right parenthesis left parenthesis x squared minus 4 right parenthesis then expand tospace f left parenthesis x right parenthesis equals 2 x cubed minus 3 x squared minus 8 x plus 12 which is a sum/difference of powers of x and can be differentiated

Examiner Tips and Tricks

A common mistake is not simplifying expressions before differentiating.

For example, the derivative of open parentheses x squared plus 3 close parentheses open parentheses x cubed minus 2 x plus 1 close parentheses can not be found by multiplying the derivatives of open parentheses x squared plus 3 close parentheses and open parentheses x cubed minus 2 x plus 1 close parentheses.

Worked Example

The functionspace f left parenthesis x right parenthesis is given by

space f left parenthesis x right parenthesis equals x cubed minus 2 x squared plus 3 minus 4 over x cubed,  where x greater than 0

Find the derivative ofspace f left parenthesis x right parenthesis

5-1-1-ib-sl-ai-aa-extra-we2-soltn-a

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