Conversion between Forms of Complex Numbers (DP IB Applications & Interpretation (AI)): Revision Note

Conversion of forms

How do I convert out of Cartesian form?

  • To convert z equals x plus straight i y from Cartesian form to modulus-argument (polar) form or exponential (Euler) form, you first need to find

    • the modulus 

      • r equals open vertical bar z close vertical bar equals square root of x squared plus y squared end root

    • and  the argument

      • theta equals arg invisible function application z

    • then use

      • z equals r open parentheses cos space theta plus isin space theta close parentheses equals r straight e to the power of straight i theta end exponent equals r space cis space theta

Examiner Tips and Tricks

The relationship z equals r open parentheses cos space theta plus isin space theta close parentheses equals r straight e to the power of straight i theta end exponent equals r space cis space theta is given in the formula booklet.

How do I convert into Cartesian form?

  • To convert from modulus-argument (polar) form or exponential (Euler) form to Cartesian form

    • you need to work out the values of

      • cos space theta

      • sin space theta

      • which may be exact

    • then expand z equals r open parentheses cos space theta plus isin space theta close parentheses into the components z equals x plus straight i y

Examiner Tips and Tricks

It is not possible to go directly from exponential (Euler) to Cartesian form without having to first convert to modulus-argument (polar) form.

Examiner Tips and Tricks

Your GDC may be able to convert between complex number forms, as some have the option to 'convert to polar' or 'convert to rectangular' (Cartesian).

Worked Example

Two complex numbers are given by z subscript 1 equals 2 plus 2 straight i and z subscript 2 equals 3 straight e to the power of fraction numerator 2 pi over denominator 3 end fraction straight i end exponent.

(a) Write z subscript 1 in the form r straight e to the power of straight i theta end exponent where r greater than 0 and 0 less or equal than theta less than 2 pi.

1-9-2-ib-aa-hl-forms-of-cn-we-solution-3-a

(b) Write z subscript 2 in Cartesian form.

1-9-2-ib-aa-hl-forms-of-cn-we-solution-3-b

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