Definite Integrals (DP IB Applications & Interpretation (AI)): Revision Note

Did this video help you?

Definite Integrals

What is a definite integral?

  • A definite integral is written in the form integral subscript a superscript b f left parenthesis x right parenthesis space straight d x, where

    • space f left parenthesis x right parenthesis is the integrand (function to be integrated)

    • a and b are the integration limits

      • a is the lower limit, and b is the upper limit

      • These correspond to the lines x equals a and x equals b in the area under a curve

  • According to the Fundamental Theorem of Calculus, if F left parenthesis x right parenthesis is an antiderivative ofspace f left parenthesis x right parenthesis, then

integral subscript a superscript b f left parenthesis x right parenthesis space straight d x equals F left parenthesis b right parenthesis minus F left parenthesis a right parenthesis

  • The constant of integration (“plus c”) is not needed in definite integration

    • "plus c” would appear alongside both F(a) and F(b)

    • Then subtracting means the “plus c”’s would cancel

How do I find definite integrals analytically (manually)?

  • STEP 1

    Give the integral a name to save having to rewrite the whole integral every time

    If need be, rewrite the integral into an integrable form

    • E.g.space space I equals integral subscript 1 superscript 2 3 x squared space straight d x

  • STEP 2

    Integrate without applying the limits; you will not need “+c
    Notation: use square brackets [ ] with limits placed at the end bracket

    • E.g.space space I equals open square brackets x cubed close square brackets subscript 1 superscript 2 

  •  STEP 3

    Substitute the limits into the function and evaluate

    • E.g.space space I equals open parentheses 2 close parentheses cubed minus open parentheses 1 close parentheses cubed equals 8 minus 1 equals 7 

Examiner Tips and Tricks

Even if you evaluate a definite integral manually, it is always good practice to check your answer by using your GDC.

Worked Example

a) Show that

integral subscript 2 superscript 4 3 x left parenthesis x squared minus 2 right parenthesis space straight d x equals 144

 

5-4-3-ib-sl-aa-only-we1-soltn-a

b) Use your GDC to evaluate

space integral subscript 0 superscript 1 3 straight e to the power of x squared sin space x end exponent space straight d x

giving your answer to three significant figures.

5-4-3-ib-sl-aa-only-we1-soltn-b

You've read 0 of your 5 free revision notes this week

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Paul

Author: Paul

Expertise: Maths Content Creator

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.