Centripetal Force (Edexcel A Level Physics): Revision Note

Exam code: 9PH0

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Centripetal Force

  •  Centripetal force can be calculated using any of the following equations:

F = mv2r= mrω2 = mvω

  • Where:

    • F = centripetal force (N)

    • v = linear velocity (m s-1)

    • ⍵ = angular speed (rad s-1)

    • r = radius of the orbit (m)

Centripetal force diagram, downloadable AS & A Level Physics revision notes

Centripetal force is always perpendicular to the direction of travel

  • The centripetal force is the resultant force on the object moving in a circle

    • This is particularly important if there are multiple forces on the object, such as weight

Vertical Circular Motion

  • An example of vertical circular motion is swinging a ball on a string in a vertical circle

  • The forces acting on the ball are:

    • The tension in the string

    • The weight of the ball, acting downwards

  • As the ball moves around the circle, the direction of the tension changes continuously, while the weight always acts downwards

  • By conservation of mechanical energy, the ball is:

    • fastest at the bottom (where its gravitational potential energy is lowest)

    • slowest at the top (where its potential energy is highest)

  • The magnitude of the tension, therefore, varies, reaching a maximum at the bottom and a minimum at the top

6-1-4-vertical-circular-motion_sl-physics-rn
  • At the bottom of the circle:

    • The centripetal force is directed upwards (towards the centre of the circle)

    • The tension acts upwards, and the weight acts downwards

  • So, the tension must support the weight and provide the centripetal force:

Tmax  mg = mvbottom2r

Tmax = mvbottom2r + mg

  • At the top of the circle:

    • The centripetal force is directed downwards (towards the centre of the circle)

    • The tension and the weight both act downwards

  • So, together the tension and the weight provide the centripetal force:

Tmin + mg = mvtop2r

Tmin = mvtop2r  mg

  • The tension is therefore greatest at the bottom for two reasons:

    • v2 is largest at the bottom (from conservation of energy)

    • At the bottom, weight is subtracted from the centripetal force requirement to give the tension; at the top, weight is added — so for the same speed, T at the bottom would already exceed T at the top

Worked Example

A bucket of mass 8.0 kg is filled with water and is attached to a string of length 0.5 m.

WE - Centripetal force question image, downloadable AS & A Level Physics revision notes

What is the minimum speed the bucket must have at the top of the circle so no water spills out?

Answer:

Step 1: Draw the forces on the bucket at the top

Step 2: Write an expression for the centripetal force

  • The weight of the bucket = mg

  • At the top of the circular path, the weight and tension act in the same direction, so the centripetal force is

mv2r = T + mg

  • The minimum speed v is when the string is taut but not stretched, so the tension here is zero (T = 0)

mv2r =  mg

Step 3: Rearrange for velocity v and calculate

  • m cancels from both sides

v = gr

v = 9.81×0.5 = 2.2 m s1

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.