Electric Force between Two Charges (Edexcel A Level Physics): Revision Note

Exam code: 9PH0

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

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Electric Force between Two Charges

  • All charged particles produce an electric field around them

    • This field exerts a force on any other charged particle within range

  • The electrostatic force between two charges is defined by Coulomb’s Law

    • Recall that the charge of a uniform spherical conductor can be considered as a point charge at its centre

  • Coulomb’s Law states that:

    The electrostatic force between two point charges is proportional to the product of the charges and inversely proportional to the square of their separation

  • The force FE between two charges as expressed by Coulomb's Law is given by the equation:

Coulombs Law Equation _2
Coulombs Law diagram, downloadable AS & A Level Physics revision notes

The electrostatic force between two charges is defined by Coulomb’s Law

  • Where:

    • FE = electrostatic force between two charges (N)

    • Q1 and Q2 = two point charges (C)

    • ε0 = permittivity of free space

    • r = distance between the centre of the charges (m)

  • The 1/r2 relation is called the inverse square law

  • This means that when the separation of two charges doubles, the electrostatic force between them reduces to (½)2 = ¼ of its original size

  • ε0 is a physical constant used to show the capability of a vacuum to permit electric fields

  • If Q1 and Q2 are oppositely charged, then the electrostatic force FE is negative

    • This can be interpreted as an attractive force between Q1 and Q2

  • If Q1 and Q2 are the same charge, then the electrostatic force FE is positive

    • This can be interpreted as a repulsive force between Q1 and Q2

Worked Example

An alpha particle is situated 2.0 mm away from a gold nucleus in a vacuum. Assuming they are point charges, calculate the magnitude of the force acting on each of the charges.

Atomic number of helium = 2

Atomic number of gold = 79

Charge of an electron = 1.60 × 10-19 C

Answer:

Step 1: Write down the known quantities

  • Distance, r = 2.0 mm = 2.0 × 10-3 m

    The charge of one proton = +1.60 × 10-19 C

    An alpha particle (helium nucleus) has 2 protons

  • Charge of alpha particle, Q1 = 2 × 1.60 × 10-19 = +3.2 × 10-19 C

    The gold nucleus has 79 protons

  • Charge of gold nucleus, Q2 = 79 × 1.60 × 10-19 = +1.264 × 10-17 C

Step 2: The electrostatic force between two point charges is given by Coulomb’s Law

Coulombs Law Equation _2

Step 3: Substitute values into Coulomb's Law

Coulomb's Law Worked Example equation 2

Examiner Tips and Tricks

Remember to always square the distance, r between the charges! 

Always look out for unit prefixes when substituting values into an equation. Check whether the charge has been converted into C instead of nC or µC, or the distance in mm to m to get a force F of newtons, N.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.