Structural Analysis of Molecules (HL) (DP IB Chemistry): Revision Note

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Structural Analysis of Molecules

  • The chemists' toolkit includes a range of analytical techniques that enable the structure of compounds to be deduced

Summary of analytical techniques

  • Mass spectrometry provides:

    • Relative atomic mass

    • Isotopic composition

    • Relative molecular mass (Mr)

    • Fragmentation patterns in organic compounds

    • Support for determining structure

  • Nuclear magnetic resonance (NMR) spectroscopy provides:

  • Infrared (IR) spectroscopy provides:

    • Identification of specific covalent bonds

    • Evidence for functional groups present in the molecule

  • These techniques are rarely used in isolation

    • They are typically combined to provide evidence when analysing new or synthetic compounds

    • Using multiple techniques helps confirm the identity and structure of the compound with greater confidence

  • Structural problems often require interpreting multiple spectra for the same unknown compound

    • Each technique offers a different piece of information

    • The goal is to combine the evidence and propose the most likely structure

Worked Example

Compound X has the molecular formula C4H8O and produces the following mass spectrum, IR spectrum and ¹H NMR spectrum.

Mass spectrum of X
Mass spectrum of X
IR spectrum of X
Infrared spectrum of X
1H NMR spectrum of X
1H NMR spectrum of X

Deduce the structure of the compound using the data provided.

Support your answer with evidence from each spectrum and appropriate references to the IB Chemistry data booklet.

Answer

Mass Spectrum - IB Chemistry data booklet (Section 22)

  • Molecular ion peak, m / z = 72

    • This corresponds to the relative molecular mass of C4H8O

      • Mr = (12.01 × 4) + (8 × 101) + (16.00) = 72.12

  • Large peak at  m / z = 43

    • This could correspond to CH3CH2CH2+ or CH3CO+ 

      • Mr of CH3CH2CH2+ = (12.01 x 3) + (7 × 1.01) = 43.10

      • Mr of CH3CO+ = (12.01 × 2) + (3 × 1.01) + (16.00) = 43.05

    • This indicates the loss of CH4O or C2H5 from X

  • Peak at  m / z = 29

    • This could correspond to CH3CH2+ 

      • Mr of CH3CH2+ =  (12.01 x 2) + (5 × 1.01) = 29.07

    • This indicates the loss of C2H3O from X

IR Spectrum - IB Chemistry data booklet (Section 20)

  • There is a strong absorption in the range 1700 - 1750 cm-1

    • This corresponds to C=O and suggests an aldehyde or ketone

    • It cannot be an ester or a carboxylic acid because there is only one oxygen in the molecular formula

1H NMR Spectrum - IB Chemistry data booklet (Section 21)

  • The spectrum shows three distinct proton environments:

    • A triplet at around 1.0 ppm

      • This suggests a –CH3 group next to a –CH2– group

    • A quartet at around 2.4 ppm

      • This suggests a –CH2 group between a –CH3 group and a carbonyl group

    • A singlet at around 2.1 ppm

      • This suggests a –CH3 group attached directly to a carbonyl group, with no adjacent protons

  • The peak splitting pattern of a quartet and triplet together suggests an ethyl group (CH3CH2–)

  • The singlet indicates an isolated proton environment

  • Integration data (3H : 2H : 3H) further confirms the assignment of two methyl groups and one methylene

Overall structure:

  • The molecular formula is C4H8O

  • The compound contains a carbonyl group but is not an aldehyde or acid, suggesting it is a ketone

  • The NMR data support two CH3 groups and one CH2 group in different environments

  • Mass spectrum fragments match those expected for CH3COCH2CH3

  • Therefore, the structure of X is butan-2-one (CH3COCH2CH3 ):

butanone-displayed-formula

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

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