Gradients & Rates of Change (AQA Level 3 Mathematical Studies (Core Maths)): Revision Note

Exam code: 1350

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Updated on

Gradient of a Straight Line

How do I find the gradient of a straight line?

  • The gradient of a straight line is given by

    • fraction numerator Change space in space y over denominator Change space in space x end fraction or fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction

      • Where two co-ordinates on the line are given by open parentheses x subscript 1 comma space y subscript 1 close parentheses and open parentheses x subscript 2 comma space y subscript 2 close parentheses

    • You may also see this phrased as "rise over run"

  • In the straight line equation, y equals m x plus c

    • m is the gradient of the line

  • If the equation of the line is written in a different format, rearrange into the form y equals m x plus c to find the gradient

Interpreting the gradient as a rate of change

  • The gradient is the rate of change of the line as x increases

  • When modelling, the variables will be real life quantities rather than x and y

  • For example, when modelling:

    • The volume of water in a cup as it is filled

      • Volume would be on the y-axis, and time would be on the x-axis

      • The gradient would be volume per unit of time

      • E.g. ml per second

    • Rate of pay per hour

      • Pay would be on the y-axis, and time would be on the x-axis

      • The gradient would be pay per unit of time

      • E.g. £ per hour

    • The extension of a spring as a force is applied

      • Extension of the spring would be on the y-axis and the applied force would be on the x-axis

      • The gradient would be the extension per unit of force

      • E.g. cm per N (centimetres per Newton)

Worked Example

Write the equation of the straight line which passes through (-20, 24) and (20, -6).

Find the gradient using fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
Be careful with negative numbers!

fraction numerator negative 6 space minus space 24 over denominator 20 space minus space minus space 20 end fraction equals fraction numerator negative 30 over denominator 40 end fraction equals negative 3 over 4

Write in the form y equals m x plus c

y equals negative 3 over 4 x plus c

Find c by substituting in one of the coordinates, and solving for c
Substituting in (20, -6):

table row cell negative 6 end cell equals cell negative 3 over 4 open parentheses 20 close parentheses plus c end cell row cell negative 6 end cell equals cell negative 15 plus c end cell row 9 equals c end table

Write the full equation

Equivalent answers would also be allowed, e.g.
y equals negative 0.75 x plus 9
4 y equals negative 3 x plus 36 etc.

Worked Example

The price of electricity is charged per kWh (kilowatt-hour) of electricity used, plus a fixed, daily standing charge, which does not depend on usage.

The graph below shows the total daily price for electricity (in pence), against kWh used.

linear graph showing the cost of electricity per kWh used

(a) Explain the meaning of the gradient of the graph in this context.

The gradient is given by fraction numerator change space in space y over denominator change space in space x end fraction

gradient equals fraction numerator change space in space daily space cost space in space pence over denominator change space in space kWh space used end fraction

It can help to consider the units used

Units space equals pence over kWh

Explain what the gradient means, in the context of the problem

The gradient represents the price in pence per kWh of electricity used

(b) Use the graph to estimate the price for electricity in pence per kWh. Round your answer to the nearest penny.

As described in part (a) the price for electricity in pence per kWh is given by the gradient

Pick two points to use to find the gradient, using fraction numerator change space in space y over denominator change space in space x end fraction

Select two points which are far away from one another, to give the most accurate value

Selecting points which are on, or close to, gridlines can help you to read the graph

Finding two coordinates on a linear graph

The two coordinates are

(2, 100) and (20, 540)

Find the gradient

fraction numerator 540 minus 100 over denominator 20 minus 2 end fraction equals 24.444...

Round to nearest penny

24 pence per kWh

(c) Explain the meaning of the y-intercept of the graph in this context.

The y intercept is when x equals 0, or when no electricity is used in this context

The y-intercept represents the daily standing charge

Gradient at a Point on a Curve

How do I find the gradient of a curve at a point?

  • The gradient of a graph at any point is equal to the gradient of the tangent to the curve at that point

  • Remember that a tangent is a line that just touches a curve (and doesn’t cross it)

A quadratic curve with two tangents drawn on it. The gradient of the curve at the point x = 1 will be equal to the gradient of the purple tangent. The gradient of the curve at the point x = 6 will be equal to the gradient of the green tangent.
  • To find an estimate for the gradient:

    • Draw a tangent to the curve

      • This will only be done by eye, so the gradient will be an estimate

    • Find the gradient of the tangent by finding fraction numerator change space in space y over denominator change space in space x end fraction or "rise over run"

Finding the gradient of a tangent drawn to a curve using "rise over run"
  • For the above diagram, the gradient would be fraction numerator negative 2.5 over denominator 4 end fraction equals negative 0.625

    • Always check if the gradient should be positive or negative

      • An upward slope has a positive gradient

      • A downward slope has a negative gradient

How do I interpret the gradient of a graph at a point?

  • As discussed above for linear graphs, when modelling a real-life scenario, consider the meaning and units of the x and y axes

    • The gradient will be the y-axis units, divided by the x-axis units

      • E.g. millilitres per minute, or kilometres per litre

  • On a curve, the gradient is constantly changing

    • It is important to understand that the gradient at a point is the gradient at that point only

      • Not the gradient for the whole graph

  • If the gradient is zero at a point on the graph

    • The tangent at that point will be horizontal

    • This point is either a local minimum or a local maximum

    • They are described as "local" because whilst they are a peak or a trough, they may not be the maximum or minimum point of the graph overall

      • An example of this is shown in the below image

Cubic curve showing a local minimum and local maximum, where there are horizontal tangents

How do I find an average rate of change?

  • An average rate of change can be found by:

    • Selecting a point on the curve at the start

    • Selecting a point on the curve at the end

    • Drawing a line between them (a chord)

    • Finding the gradient of the chord joining the two points

  • An example of this method is shown in part (b) of the worked example below

Worked Example

The temperature of a cup of coffee in degrees Celsius is tracked as it cools down.

A graph is plotted of the temperature of the coffee over time and is shown below.

a negative exponential graph showing the temperature of a cup of coffee cooling down

(a) Estimate the rate of change of the temperature of the coffee after 10 minutes.

Draw a tangent to the curve at point corresponding to 10 minutes

negative exponential graph with tangent drawn at t=10

Select two coordinates on the tangent to use to estimate the gradient

Two points on a tangent to a curve selected; (1,60) and (25, 10)

Find the gradient between these two points

fraction numerator 10 minus 60 over denominator 25 minus 1 end fraction equals fraction numerator negative 50 over denominator 24 end fraction equals negative 2.08333...

The gradient of the tangent at 10 minutes, is equal to the gradient of the curve at 10 minutes

The rate of change of the temperature of the coffee after 10 minutes is -2.08 degrees per minute

Rather than using a negative rate of change, you could describe a rate of cooling instead

After 10 minutes, the coffee is cooling at a rate of 2.08 degrees per minute

(b) Estimate the average rate of change between 5 minutes and 30 minutes.

Select a point on the curve at 5 minutes, and a point on the curve at 30 minutes

Join them with a line to form a chord

A chord between two points on a negative exponential graph. The two points are (5,56) and (30,24)

Find the gradient of the chord

fraction numerator 24 minus 56 over denominator 30 minus 5 end fraction equals fraction numerator negative 32 over denominator 25 end fraction equals negative 1.28

The average rate of change between 5 minutes and 30 minutes is -1.28 degrees per minute

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Jamie Wood

Author: Jamie Wood

Expertise: Maths Content Creator

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.