Differentiate
(i) 
(ii) 
(iii) 
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Exam code: 8MA0
Differentiate
(i) 
(ii) 
(iii) 
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Given that
 find an expression for .
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Given that
find  writing your answer in simplest form.
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Given that
find  writing your answer in simplest form.
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Given that
find  writing your answer in simplest form.
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A curve has the equation
Find an expression for .
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Given that
use differentiation from first principles to show that
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A curve has equation
Find  writing your answer in simplest form.
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The function  is given by
Show that  can be written in the form
where , 
, 
 and 
 are constants to be found.
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Hence find an expression for .
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Find the coordinates of any points on the curve
at which the gradient is zero.
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Find the -coordinate of the point on the curve with equation
 
at which the gradient is 4.
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A student uses differentiation from first principles to show that the derivative of  is 
.
Their working is shown below.
There is an error in their argument in step 6.
Write out the correct argument for step 6.
STEP 1
STEP 2
STEP 3
STEP 4
STEP 5
STEP 6
When  ,  
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Given that
Use differentiation from first principles to show that
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Given that
Use differentiation from first principles to show that
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Given that
find .
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Given that
 
 find .
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A curve has equation
Find  writing your answer in simplest form.
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A curve has equation
Find  writing your answer in simplest form.
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The function  is defined by 
Find  writing your answer in simplest form.
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Hence solve the equation
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A curve has the equation
Find .
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Find the coordinates of the point on the curve where the gradient is 2.
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The function  is defined by 
where  is a constant.
Find an expression for  in terms of 
 and 
.
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Given that the equation  has exactly one real solution, find the value of 
.
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A curve has equation
Write the equation of the curve in the form
where , 
, 
 and 
 are constants to be found.
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Hence find  writing your answer in simplest form.
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Find the coordinates of the point(s) on the curve where the gradient is .
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A curve has the equation
where , 
 and 
 are non-zero constants.
The gradient at the point  is 
The gradient at the point  is 
Show that
and
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Hence find  and 
.
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By considering the point , find 
.
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A curve has equation
Find  writing your answer in simplest form.
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A curve has equation
Find .
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Given that
Use differentiation from first principles to show that
where  is a constant.
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Given that
Use differentiation from first principles to show that
How did you do?
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A curve has equation
Show that
where , 
, 
 and 
 are constants to be found.
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A curve has equation
Find  writing your answer in simplest form.
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A curve has equation
Find .
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The function  is defined by 
Show that there are no solutions to the equation
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A curve has the equation
where  is a constant. 
There is only one point on the curve where the gradient of the tangent at that point is zero.
Find the possible values of .
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The function  is defined by
where  is a constant.
Find all the possible values of  for which the equation
has at least one real solution.
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A curve has the equation
Show that
where  and 
 are rational numbers to be found.
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Hence find the coordinates of the point on the curve where the gradient is 0.
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Given that
show that
where  is a constant to be found.
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A curve has equation
Find , writing your answer in the form
where
  , 
 and 
 are constants to be found
, 
 and 
 are terms of a descending arithmetic sequence to be found
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A curve has equation
Find , writing the terms in your answer in ascending powers of 
.
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A curve has the equation
where , 
 and 
 are non-zero constants.
The curve passes through the point 
The gradient at the point  is 
Find , 
 and 
.
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