Derivation of the Kinetic Theory of Gases Equation (Cambridge (CIE) A Level Physics): Revision Note
Exam code: 9702
Derivation of the kinetic theory of gases equation
The equation for the kinetic theory of ideal gases contains the mean square speed of the particles:
Where
= average speed of the gas particles
has the units m2 s-2
Since particles travel in all directions in 3D space and velocity is a vector, some particles will have a negative direction and others a positive direction
When there are a large number of particles, the total positive and negative velocity values will cancel out, giving a net zero value overall
To calculate the average speed of the particles in a gas, take the square root of the mean square speed:
cr.m.s is known as the root-mean-square speed and still has the units of m s-1
The mean square speed is not the same as the mean speed
Root-mean-square speed
Molecular movement causes the pressure exerted by a gas
When molecules rebound from their container wall, the change in momentum gives rise to a force exerted by the particles on the wall
Many molecules moving in random motion exert forces on the walls, which creates an average overall pressure (since pressure is the force per unit area)
Derivation of the kinetic theory of gases equation
Consider the model of a gas molecule in a container
Take a single molecule in a cube-shaped box with sides of equal length
The molecule has mass
and moves with speed
parallel to one side of the box
It collides at regular intervals with the sides of the box, exerting a force and contributing to the pressure of the gas
By calculating the pressure this one molecule exerts on one end of the box, the total pressure produced by a total of
molecules can be deduced
Modelling a gas molecule in a container

A single molecule in a box collides with the walls and exerts a pressure
Derivation of the equation for the pressure exerted by a gas
1. Find the change in momentum as a single molecule hits a wall perpendicularly
One assumption of the kinetic theory is that molecules rebound elastically
This means there is no kinetic energy lost in the collision
If a particle rebounds in the opposite direction to its initial velocity
, its final velocity will be
The change in momentum is therefore:
2. Calculate the number of collisions per second by the molecule on a wall
The time between collisions of the molecule travelling to one wall and back is calculated by travelling a distance of
with speed
:
Time between collisions =
Note:
is not taken as the speed of light in this scenario
3. Find the change in momentum per second
The average force the molecule exerts on one wall is found using Newton’s second law of motion:
The change in momentum is
since the force on the molecule from the wall is in the opposite direction to its change in momentum
4. Calculate the total pressure from N molecules
The area
of one wall is
The pressure
is defined as the force per unit area:
This is the pressure exerted on the container wall by one molecule
To account for the large number of N molecules, the pressure can now be written as:
Each molecule has a different velocity and they all contribute to the pressure
The mean square speed
is written with left and right-angled brackets
The pressure is now defined as:
5. Consider the effect of the molecule moving in 3D space
The pressure equation still assumes all the molecules are travelling in the same direction and colliding with the same pair of opposite faces of the cube
In reality, all molecules will be moving in three dimensions equally and randomly, with average velocity
:
Where
,
, and
are the components of the average velocity - this equation is a result of Pythagoras' theorem in 3D
Since pressure is due to the force exerted on one face of the cube, only the component of velocity perpendicular to that face (e.g. the
-direction) matters
For a gas with molecules moving randomly in all directions, the mean square speed is evenly distributed among all three directions:
Therefore, each squared
-component of velocity
accounts for a third of the average velocity squared
This is why only one-third of the total mean square speed contributes to the pressure on one wall
6. Re-write the pressure equation
The box is a cube, and all the sides are of length
This means the volume
of the cube is equal to
Substituting the new values for
and
back into the pressure equation obtains the final equation:
Where:
= pressure (Pa)
= volume (m3)
= number of molecules
= mass of one molecule (kg)
= mean square speed of the molecules (m s–1)
This can also be written using the density ρ of the gas:
Rearranging the pressure equation for
and substituting the density
:
Worked Example
An ideal gas has a density of 4.5 kg m-3 at a pressure of 9.3 × 105 Pa and a temperature of 504 K.
Determine the root-mean-square (r.m.s.) speed of the gas atoms at 504 K.
Answer:
Step 1: Write out the equation for the pressure of an ideal gas with density
Step 2: Rearrange for mean square speed
Step 3: Substitute in values
Step 4: To find the r.m.s value, take the square root of the mean square speed
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