Ideal Gases (Cambridge (CIE) A Level Physics): Revision Note

Exam code: 9702

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

Ideal gases

  • An ideal gas is one which obeys the relation:

pV T

  • Where:

    • p = pressure of the gas (Pa)

    • V = volume of the gas (m3)

    • T = thermodynamic temperature (K)

  • According to the relation:

    • temperature is directly proportional to pressure, for a constant volume

    • temperature is directly proportional to volume, for a constant pressure

    • pressure and volume are inversely proportional to each other, for a constant temperature

Temperature and pressure

  • For a constant volume

  • When the temperature of a gas is increased

  • Then the pressure is also increased

    • the molecules have a higher kinetic energy

    • so move about more and collide more with the walls of their container

    • creating more pressure

Temperature and volume

  • For a constant pressure

  • When the temperature of a gas is increased

  • The volume is also increased

    • the molecules have a higher kinetic energy

    • so move about more and move further apart from each other

    • expanding to create a bigger volume

Pressure and volume

  • For a constant temperature

  • An increase in pressure comes from a decrease in volume

  • The smaller container creates a smaller surface area

  • There are more collisions which creates more pressure

Worked Example

An ideal gas is in a container of volume 4.5 × 10−3 m3. The gas is at a temperature of 30°C and a pressure of 6.2 × 105 Pa.

Calculate the pressure of the ideal gas in the same container when it is heated to 40 °C.

Answer:

Step 1: State the known values

  • Volume, V = 4.5 × 10−3 m3

  • Initial pressure, p1 = 6.2 × 105 Pa

  • Initial temperature, T1 = 30°C = 303 K

  • Initial temperature, T2 = 40°C = 313 K

Step 2: Since volume is constant, state the pressure law

p1p2=T1T2

Step 3: Rearrange to make p2 the subject

p2=p1×T2T1

Step 4: Substitute in known values and calculate p2

p2=6.2×105×313303= 6.4×105 Pa

Examiner Tips and Tricks

Make sure to always have the temperature, T in kelvins for all equations in this topic!

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.