Half-Life (Cambridge (CIE) A Level Physics): Revision Note

Exam code: 9702

Leander Oates

Written by: Leander Oates

Reviewed by: Caroline Carroll

Updated on

Half-life definition

  • Half-life is defined as:

The time taken for the initial number of nuclei to reduce by half

  • This means that when a time equal to the half-life has passed, the activity of the sample will also halve

  • This is because the activity is proportional to the number of undecayed nuclei, A ∝ N

Determining half-life from a graph

Half-Life Graph, downloadable AS & A Level Physics revision notes

When a time equal to the half-life passes, the activity falls by half, when two half-lives pass, the activity falls by another half (which is a quarter of the initial value)

Calculating half-life

  • The half-life of a radioactive sample can be calculated using the equation:

t1/2 = ln 2λ

  • Where:

    • t½ = half-life of the sample (s)

    • λ = decay constant of the sample (s-1)

  • This equation shows that:

    • the half-life and the decay constant of a sample are inversely proportional

    • the shorter the half-life, the larger the decay constant and the faster the rate of decay

Derivation of the half-life equation

  • To find an expression for half-life, start with the equation for exponential decay:

N = N0eλt

  • Where:

    • N = number of nuclei remaining in a sample

    • N0 = the initial number of undecayed nuclei (when t = 0)

    • λ = decay constant (s-1)

    • t = time interval (s)

  • When time t is equal to the half-life t½, the activity N of the sample will be half of its original value, so N = ½ N0

12N0 = N0eλt1/2

  • First, divide both sides by N0:

12 = eλt1/2

  • Then, take the natural log of both sides:

ln(12) = λt1/2

  • Finally, apply the properties of logarithms:

λt1/2 = ln 2

  • Therefore, half-life t½ can be calculated using the equation:

t1/2 = ln 2λ  0.693λ

Worked Example

Strontium-90 is a radioactive isotope with a half-life of 28.0 years. A sample of strontium-90 has an activity of 6.4 × 109 Bq.

Calculate the decay constant λ, in s–1, of strontium-90.

Answer: 

Step 1: Convert the half-life into seconds

28 years = 28 × 365 × 24 × 60 × 60 = 8.83 × 108 s

Step 2: Write the equation for half-life

t12 = ln 2λ

Step 3: Rearrange for λ and calculate

λ = ln 2t12 = ln 28.83×108 = 7.85×1010 s1

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.