Ionic Compounds (SQA National 5 Chemistry): Revision Note

Exam code: X813 75

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Forming ions

  • Atoms are most stable when they have a full outer shell of electrons, like the Noble Gases in Group 0 (8)

  • To achieve this stable electron arrangement, atoms will either lose or gain electrons

  • When an atom loses or gains electrons, it becomes a charged particle called an ion

Metals form positive ions

  • Metal atoms (from the left of the Periodic Table) have 1, 2 or 3 electrons in their outer shell

  • They achieve a stable electron arrangement by losing these outer electrons

  • When a neutral atom loses negative electrons, it is left with more positive protons.

    • This results in a positive ion

Example: Magnesium (Mg)

  • A magnesium atom has the electron arrangement 2,8,2

  • It loses its 2 outer electrons to achieve the stable arrangement 2,8

  • It now has 12 protons but only 10 electrons

    • So, it forms the Mg2+ ion

Non-metals form negative ions

  • Non-metal atoms (from the right of the Periodic Table) have 5, 6 or 7 outer electrons

  • They achieve a stable electron arrangement by gaining electrons to complete their outer shell

  • When a neutral atom gains extra negative electrons, it is left with more negatove electrons

    • This results in a negative ion

Example: Oxygen (O)

  • An oxygen atom has the electron arrangement 2,6

  • It gains 2 electrons to achieve the stable arrangement 2,8

  • It now has 8 protons but 10 electrons

    • So, it forms the O2- ion

Writing ion-electron equations

  • We can show the process of an atom losing or gaining electrons by writing an ion-electron equation

    • The symbol for an electron is e-

Losing electrons (metals)

  • When an atom loses electrons, the electrons are shown on the product (right) side of the equation

  • For example, magnesium:

Mg → Mg2+ + 2e-
(A magnesium atom forms a magnesium ion and two electrons)

Gaining electrons (non-metals)

  • When an atom gains electrons, the electrons are shown on the reactant (left) side of the equation

  • For example, oxygen

O + 2e- → O2-
(An oxygen atom and two electrons form an oxide ion)

Examiner Tips and Tricks

The total charge on both sides of an ion-electron equation must be balanced

  • For Mg → Mg2+ + 2e-:

    • The charge on the reactant (left) side is 0

    • The charge on the product (right) side is (+2) + (-2) = 0

  • For O + 2e- → O2-:

    • The charge on the reactant (left) side is 0 + (-2) = -2

    • The charge on the product (right) side is -2

Worked Example

An atom of aluminium has the electron arrangement 2,8,3.

a) State the charge on the ion formed by an aluminium atom.

[1]

b) Write the ion-electron equation for the formation of this ion

[1]

Answer:

a) Charge on the ion:

  • Aluminium is a metal, so it loses electrons.

  • When a neutral atom loses 3 negative electrons, it is left with 13 protons (+) and 10 electrons (-).

  • The resulting charge is 3+ [1 mark]

b) Ion-electron equation:

  • The reactant is the neutral aluminium atom, Al

  • The product is the ion that is formed, Al3+

  • Because the atom lost 3 electrons, the electrons (3e-) are shown on the product (right) side of the equation

Al → Al3++ 3e-

[1 mark]

Worked Example

An atom of fluorine has the electron arrangement 2,7.

a) State the charge on the ion formed by a fluorine atom.

[1]

b) Write the ion-electron equation for the formation of this ion.

[1]

Answer:

a) Charge on the ion:

  • Fluorine is a non-metal, so it gains electrons

  • When a neutral atom gains 1 negative electron, it has 9 protons (+) and 10 electrons (-)

  • The resulting charge is 1- [1 mark]

b) Ion-electron equation:

  • The reactant is the neutral fluorine atom, F

  • The product is the ion that is formed, F-

  • To form the ion, the atom must gain 1 electron

  • The electron (e-) is therefore a reactant and is written on the left side of the equation

F + e- → F-

[1 mark]

Ionic bonding & lattices

Ionic bonding

  • Ionic bonding occurs between metal and non-metal atoms

  • It involves the transfer of electrons from the metal atom to the non-metal atom

    • The metal atom loses its outer electrons to form a positive ion

    • The non-metal atom gains these electrons to form a negative ion

Diagram showing ionic bonding in sodium chloride, illustrating electron transfer from a sodium ion to a chloride ion, forming Na⁺ and Cl⁻.
Ionic bonding in sodium chloride: a strong electrostatic attraction exists between the positive sodium ions and the negative chloride ions.

Ionic lattices

  • Ionic bonds are very strong and act in all directions

  • This means that a single positive ion doesn't just attract one negative ion; it attracts all the oppositely charged ions around it

  • As a result, ionic compounds do not form small, separate molecules

    • Instead, they build up into a giant, repeating, three-dimensional (3D) pattern called an ionic lattice

  • An ionic lattice is a regular, crystal structure

    • Each positive ion is surrounded by negative ions

    • Each negative ion is surrounded by positive ions

  • This arrangement ensures the electrostatic attraction is maximised, creating a very strong and stable structure

Giant ionic lattice of sodium chloride

Diagram of sodium chloride crystal structure, showing Na+ ions and Cl- ions.
Ionic solids are arranged in lattice structures with alternating positive and negative ions

Examiner Tips and Tricks

The chemical formula for an ionic compound, like NaCl, does not represent a single molecule. There are no "NaCl molecules"

The formula simply shows the simplest whole-number ratio of ions present in the giant lattice structure

In sodium chloride, for every one Na+ ion, there is one Cl- ion

For magnesium chloride (MgCl2), for every one Mg2+ ion, there are two Cl- ions

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.