Reactions of Metals (SQA National 5 Chemistry): Revision Note

Exam code: X813 75

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Metal reactivity series

  • Some metals, like potassium, are extremely reactive, while others, like gold, are very unreactive

  • By comparing how vigorously different metals react, we can arrange them in order of their reactivity

    • This ordered list is called the reactivity series

  • For National 5 Chemistry, the official version of this is the Electrochemical Series

    • This can be found on page 10 of the SQA Data Booklet

    • Metals higher up the series are more reactive

Building a simple reactivity series

  • In the lab, a simple reactivity series can be built by comparing the the rate (speed) of reaction for different metals with the same substance, such as dilute acid

  • Method:

    • Add small, equal-sized pieces of different metals to separate test tubes containing the same dilute acid

  • The reaction produces hydrogen gas, which is observed as fizzing (effervescence)

  • Observation:

    • The speed of the fizzing indicates the reactivity

    • The faster the fizzing, the more reactive the metal

Metal

Observation with acid

Reactivity

Magnesium

Fizzes very vigorously

Very reactive

Zinc

Fizzes steadily

Reactive

Iron

Fizzes very slowly

Slightly reactive

Copper

No reaction (no fizzing)

Unreactive

  • From these observations, we can create a simple reactivity series for these four metals:

most reactive > least reactive

magnesium > zinc > iron > copper

  • This order matches their positions in the full Electrochemical Series

Examiner Tips and Tricks

When describing an experiment to compare reactivity, be specific about what you are observing

  • Poor answer: Magnesium was more reactive than zinc.

  • Good answer: Magnesium reacted faster with the acid than zinc did, as it produced bubbles of gas at a greater rate.

Metal reactions

  • Reactive metals take part in chemical reactions where the metal atoms lose electrons (are oxidised) to form compounds

  • For National 5 Chemistry, you need to know the general word equations for the reactions of metals with:

    1. Oxygen

    2. Water

    3. Dilute acids

Reaction with oxygen

  • This reaction happens when a metal is burned in air or oxygen.

  • The product is a metal oxide

  • The general word equation is:

metal + oxygen → metal oxide

Worked Example

Write the word and balanced symbol equation for the reaction between calcium and oxygen.

[2]

Answer:

Word equation:

  • The only product is a metal oxide, so it must be calcium oxide

calcium + oxygen → calcium oxide [1 mark]

Balanced formula equation:

  • For calcium oxide, Ca is in Group 2 (valency 2) and O is in Group 6 (valency 2)

  • This gives the formula CaO

Ca + O2 → CaO

  • The oxygen atoms don't balance (2 on the left, 1 on the right)

  • Put a 2 in front of CaO to fix this:

Ca + O22CaO

  • Now the calcium atoms don't balance (1 on the left, 2 on the right)

  • Put a 2 in front of Ca to fix this and add state symbols

2Ca (s) + O2 (g) → 2CaO (s) [1 mark]

Reaction with water

  • Only the most reactive metals will react with cold water

    • These include the alkali metals like lithium, sodium and potassium

  • The products are a metal hydroxide and hydrogen gas

  • The general word equation is:

metal + water → metal hydroxide + hydrogen

Worked Example

Write the word and balanced symbol equation for the reaction between lithium and water.

[2]

Answer:

Word equation:

  • The products are a metal hydroxide and hydrogen gas

  • The metal hydroxide must be lithium hydroxide

lithium + water → lithium hydroxide + hydrogen [1 mark]

Balanced formula equation:

  • For lithium hydroxide, Li is in Group 1 (valency 1). Hydroxide is a group ion, OH⁻ (valency 1)

  • The formula is LiOH

Li + H2O → LiOH + H2

  • The hydrogen atoms don't balance (2 on the left, 3 on the right).

  • A useful trick is to put a 2 in front of the term with the odd number of hydrogens,

Li + H2O → 2LiOH + H2

  • This gives 4 H on the right, so we need 4 on the left.

  • Put a 2 in front of H2O:

Li + 2H2O → 2LiOH + H2

  • Now balance the Li by putting a 2 in front of it and adding state symbols

2Li (s) + 2H2O (l) → 2LiOH (aq) + H2 (g) [1 mark]

Reaction with acid

  • Metals that are above hydrogen in the Electrochemical Series will react with dilute acids

  • The products are a salt and hydrogen gas

  • The general word equation is:

metal + acid → salt + hydrogen

Worked Example

Write the word and balanced symbol equation for the reaction between magnesium and nitric acid.

[2]

Answer:

Word equation:

  • As nitric acid is used a nitrate salt will be produced

  • The products are a magnesium nitrate and hydrogen gas

magnesium + nitric acid → magnesium nitrate + hydrogen [1 mark]

Balanced formula equation:

  • The formulas are:

    • Magnesium is Mg

    • Nitric acid is HNO3

    • Hydrogen is H2

    • For magnesium nitrate, Mg is in Group 2 (valency 2)

    • Nitrate is a group ion, NO3- (valency 1)

      • Swapping valencies and using brackets gives the formula Mg(NO3)2

Mg + HNO3 → Mg(NO3)2 + H2

  • The nitrate group is not balanced (1 on the left, 2 on the right)

  • Put a 2 in front of HNO3 to fix this:

Mg + 2HNO3 → Mg(NO3)2 + H₂

  • Now check all the atoms: 1 Mg, 2 H, 2 N, 6 O on both sides

Mg (s) + 2HNO3 (aq) → Mg(NO3)2 (aq) + H2 (g) [1 mark]

Examiner Tips and Tricks

Both the reaction with water and the reaction with acid produce hydrogen gas

The hydrogen gas produced can be detected using the "pop test"

A lit splint is placed at the mouth of the test tube and will go out with a squeaky 'pop' if hydrogen is present

Using metals to make soluble salts

  • This method is used to make a soluble salt from the reaction of a moderately reactive metal and a dilute acid

  • Suitable metals are:

    • Above hydrogen in the Electrochemical Series

    • But, not so reactive that the reaction is dangerous

    • For example, metals like magnesium, zinc or iron).

  • Unreactive metals like copper (below hydrogen) will not react

The "excess" method

  • This practical procedure is another example of the "excess method"

  • The principle is to add more solid reactant (the metal) than is needed

    • This ensures that all of the acid is completely used up

    • This also stops the final salt being impure because it is contaminated with unreacted acid

  • Any leftover solid can be easily removed by filtration

The method in brief

  1. React

    • Add the metal in excess to a warm dilute acid

    • The reaction is complete when the fizzing stops and there is unreacted metal left over

  2. Filter

    • Filter the mixture to remove the unreacted excess metal

    • The liquid that passes through is the pure salt solution (filtrate)

  3. Crystallise

    • Gently evaporate the water from the filtrate and allow pure salt crystals to form

Step-by-step diagram illustrating the preparation of salt crystals by heating, filtration, evaporation, and crystallisation using a Bunsen burner.
Preparing a soluble salt from a metal and acid using the excess method

Examiner Tips and Tricks

You must be able to explain the key steps:

  • Why add the metal in excess?

    • To ensure all of the acid is neutralised/reacted

  • Why filter the mixture?

    • To remove the unreacted/excess metal

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.