Redox (SQA National 5 Chemistry): Revision Note

Exam code: X813 75

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Reduction & oxidation

  • Oxidation is a reaction in which an element, ion or compound loses electrons

    • This can be shown in an ion-electron equation, e.g. when silver reacts with chlorine, silver is oxidised to silver ions:

Ag → Ag+ + e-

  • Reduction is a reaction in which an element, ion or compound gains electrons

    • This can be shown in an ion-electron equation, e.g. when oxygen reacts with magnesium, oxygen is reduced to oxide ions:

O2 + 4e- → 2O2-

  • A good way to remember these definitions is the mnemonic OILRIG

    • Oxidation Is Loss (of electrons)

    • Reduction Is Gain (of electrons)

What is a redox reaction?

  • In any reaction, where one substance loses electrons (is oxidised), another substance must gain them (is reduced)

    • Therefore, oxidation and reduction always happen at the same time

    • This is why they are called redox reactions

Example redox reaction

  • The displacement reaction that occurs when a piece of magnesium ribbon is placed into a solution of blue copper(II) sulfate is:

Mg (s) + CuSO4 (aq) → MgSO4 (aq) + Cu (s)

  • To understand what is happening with the electrons, we can split the reaction into two parts:

    1. The magnesium

    2. The copper

  1. What happens to magnesium?

    • A neutral magnesium atom (Mg) turns into a magnesium ion (Mg2+) which is part of the magnesium sulfate.

    • To go from a neutral atom (Mg) to a 2+ ion (Mg2+), the atom must lose 2 electrons

    • Loss of electrons is oxidation (OILRIG)

    • Oxidation ion electron equation:

Mg (s) → Mg2+ (aq) + 2e-

  1. What happens to copper?

    • A copper(II) ion (Cu2+) from the copper(II) sulfate solution turns into a neutral copper atom (Cu), which is seen as a brown solid

    • To go from a 2+ ion (Cu2+) to a neutral atom (Cu), the ion must gain 2 electrons

    • Gain of electrons is reduction (OILRIG)

    • Reduction ion electron equation:

Cu2+ (aq) + 2e- → Cu (s)

  • Since magnesium is losing electrons (oxidation) and the copper ions are gaining electrons (reduction) in the same reaction, it is a redox reaction

  • The 2 electrons lost by each magnesium atom are the same 2 electrons gained by each copper(II) ion

Redox ion-electron equations

  • A redox reaction can be shown as one overall equation

  • This equation is created by combining the two separate ion-electron equations for the oxidation and reduction processes

  • The final, overall redox equation shows all the species that react but must not include electrons

Combining ion-electron equations

  1. Identify the oxidised and reduced substances, using the Electrochemical Series (page 10 of the SQA Data Booklet)

    • The substance that is higher up in the series is the one that is oxidised (loses electrons)

      • Its ion-electron equation must be reversed

    • The substance that is lower down in the series is the one that is reduced (gains electrons)

      • Its ion-electron equation is used as written

  2. Write the two ion-electron equations

    • Make sure to reverse the one for the substance higher up in the series

  3. Balance the electrons

    • The number of electrons lost must equal the number of electrons gained

    • If needed, multiply one or both entire equations to make the electron numbers the same

  4. Combine the equations

    • Add everything on the reactant (left) side together and everything on the product (right) side together

  5. Cancel out the electrons

    • Cancel the electrons from both sides to get the final, overall redox equation

Worked Example

Write the overall redox equation for the reaction between magnesium metal and iron(II) ions.

[2]

  1. Identify the oxidised and reduced substances

    • Magnesium is higher than iron, so it is oxidised (reversed equation)

    • Iron is lower, so it is reduced (equation as written)

  2. Write the two ion-electron equations

Mg → Mg2+ + 2e-

Fe2+ + 2e- → Fe

  1. Balance the electrons

    • Mg loses 2e- and Fe2+ gains 2e- [1 mark]

  2. Combine the equations

Mg + Fe2+ + 2e- → Mg2+ + Fe + 2e-

  1. Cancel out the electrons

Mg (s) + Fe2+ (aq) → Mg2+ (aq) + Fe (s) [1 mark]

Worked Example

Write the overall redox equation for the reaction between aluminium metal and nickel(II) ions.

[2]

Answer:

  1. Identify the oxidised and reduced substances

    • Aluminium is higher than nickel, so it is oxidised (reversed equation)

    • Nickel is lower, so it is reduced (equation as written)

  2. Write the two ion-electron equations

Al → Al3+ + 3e-

Ni2+ + 2e- → Ni

  1. Balance the electrons

    • Al loses 3e- and Ni2+ gains 2e-

      • The numbers are not balanced

      • The lowest common multiple of 3 and 2 is 6

    • Multiply the aluminium equation by 2:

      • 2Al → 2Al3+ + 6e-

    • Multiply the nickel equation by 3:

      • 3Ni2+ + 6e- → 3Ni

    • Now, 6 electrons are lost and 6 electrons are gained [1 mark]

  2. Combine the equations

2Al + 3Ni2+ + 6e- → 2Al3+ + 3Ni + 6e-

  1. Cancel out the electrons

2Al (s) + 3Ni2+ (aq) → 2Al3+ (aq) + 3Ni (s) [1 mark]

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.