Redox (SQA National 5 Chemistry): Revision Note
Exam code: X813 75
Reduction & oxidation
Oxidation is a reaction in which an element, ion or compound loses electrons
This can be shown in an ion-electron equation, e.g. when silver reacts with chlorine, silver is oxidised to silver ions:
Ag → Ag+ + e-
Reduction is a reaction in which an element, ion or compound gains electrons
This can be shown in an ion-electron equation, e.g. when oxygen reacts with magnesium, oxygen is reduced to oxide ions:
O2 + 4e- → 2O2-
A good way to remember these definitions is the mnemonic OILRIG
Oxidation Is Loss (of electrons)
Reduction Is Gain (of electrons)
What is a redox reaction?
In any reaction, where one substance loses electrons (is oxidised), another substance must gain them (is reduced)
Therefore, oxidation and reduction always happen at the same time
This is why they are called redox reactions
Example redox reaction
The displacement reaction that occurs when a piece of magnesium ribbon is placed into a solution of blue copper(II) sulfate is:
Mg (s) + CuSO4 (aq) → MgSO4 (aq) + Cu (s)
To understand what is happening with the electrons, we can split the reaction into two parts:
The magnesium
The copper
What happens to magnesium?
A neutral magnesium atom (Mg) turns into a magnesium ion (Mg2+) which is part of the magnesium sulfate.
To go from a neutral atom (Mg) to a 2+ ion (Mg2+), the atom must lose 2 electrons
Loss of electrons is oxidation (OILRIG)
Oxidation ion electron equation:
Mg (s) → Mg2+ (aq) + 2e-
What happens to copper?
A copper(II) ion (Cu2+) from the copper(II) sulfate solution turns into a neutral copper atom (Cu), which is seen as a brown solid
To go from a 2+ ion (Cu2+) to a neutral atom (Cu), the ion must gain 2 electrons
Gain of electrons is reduction (OILRIG)
Reduction ion electron equation:
Cu2+ (aq) + 2e- → Cu (s)
Since magnesium is losing electrons (oxidation) and the copper ions are gaining electrons (reduction) in the same reaction, it is a redox reaction
The 2 electrons lost by each magnesium atom are the same 2 electrons gained by each copper(II) ion
Redox ion-electron equations
A redox reaction can be shown as one overall equation
This equation is created by combining the two separate ion-electron equations for the oxidation and reduction processes
The final, overall redox equation shows all the species that react but must not include electrons
Combining ion-electron equations
Identify the oxidised and reduced substances, using the Electrochemical Series (page 10 of the SQA Data Booklet)
The substance that is higher up in the series is the one that is oxidised (loses electrons)
Its ion-electron equation must be reversed
The substance that is lower down in the series is the one that is reduced (gains electrons)
Its ion-electron equation is used as written
Write the two ion-electron equations
Make sure to reverse the one for the substance higher up in the series
Balance the electrons
The number of electrons lost must equal the number of electrons gained
If needed, multiply one or both entire equations to make the electron numbers the same
Combine the equations
Add everything on the reactant (left) side together and everything on the product (right) side together
Cancel out the electrons
Cancel the electrons from both sides to get the final, overall redox equation
Worked Example
Write the overall redox equation for the reaction between magnesium metal and iron(II) ions.
[2]
Identify the oxidised and reduced substances
Magnesium is higher than iron, so it is oxidised (reversed equation)
Iron is lower, so it is reduced (equation as written)
Write the two ion-electron equations
Mg → Mg2+ + 2e-
Fe2+ + 2e- → Fe
Balance the electrons
Mg loses 2e- and Fe2+ gains 2e- [1 mark]
Combine the equations
Mg + Fe2+ + 2e- → Mg2+ + Fe + 2e-
Cancel out the electrons
Mg (s) + Fe2+ (aq) → Mg2+ (aq) + Fe (s) [1 mark]
Worked Example
Write the overall redox equation for the reaction between aluminium metal and nickel(II) ions.
[2]
Answer:
Identify the oxidised and reduced substances
Aluminium is higher than nickel, so it is oxidised (reversed equation)
Nickel is lower, so it is reduced (equation as written)
Write the two ion-electron equations
Al → Al3+ + 3e-
Ni2+ + 2e- → Ni
Balance the electrons
Al loses 3e- and Ni2+ gains 2e-
The numbers are not balanced
The lowest common multiple of 3 and 2 is 6
Multiply the aluminium equation by 2:
2Al → 2Al3+ + 6e-
Multiply the nickel equation by 3:
3Ni2+ + 6e- → 3Ni
Now, 6 electrons are lost and 6 electrons are gained [1 mark]
Combine the equations
2Al + 3Ni2+ + 6e- → 2Al3+ + 3Ni + 6e-
Cancel out the electrons
2Al (s) + 3Ni2+ (aq) → 2Al3+ (aq) + 3Ni (s) [1 mark]
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