Expansion of the Octet (HL) (DP IB Chemistry): Revision Note

Richard Boole

Written by: Richard Boole

Reviewed by: Philippa Platt

Updated on

Expansion of the octet

  • Some elements in period 3 or higher can form molecules where the central atom holds more than eight electrons

  • This is possible because these elements have vacant d-orbitals in their valence shell

  • These orbitals can accommodate extra bonding pairs of electrons

  • This phenomenon is called the expansion of the octet

    • It explains the existence of structures like:

      • PCl5 – with five bonding pairs

      • SF6 – with six bonding pairs

Expansion to five electron pairs

  • Molecules with five electron domains around the central atom adopt a trigonal bipyramidal electron domain geometry

  • Molecular geometry depends on:

    • How many domains are bonding pairs

    • How many domains are lone pairs

  • Examples of chemicals where an octet is expanded to five electron pairs include:

    • Phosphorus pentachloride, PCl5

    • Chlorine trifluoride, ClF3

    • The triiodide ion, l3-

    • Sulfur tetrafluoride, SF4

Phosphorus pentachloride, PCl5

  • The total number of valence electrons in PCl5,is:

P + (5 x Cl) = 5 + (5 x 7) = 40

  • There are 5 chlorine atoms bonded to a central phosphorus atom

    • So, there are 5 bonding pairs

  • The bonding pairs account for 10 electrons

    • This leaves 40 - 10 = 30 electrons

  • The remaining 30 electrons exist as 15 lone pairs

    • This means that each chlorine atom has 3 lone pairs

  • Phosphorus has expanded its octet, since it has 5 pairs of electrons

  • The Lewis formula for PCl5 is: 

Lewis structure of PCl5 showing an expanded octet for phosphorous containing 10 electrons

The octet of the central phosphorous atom has been expanded to hold 10 electrons

Sulfur tetrafluoride, SF4

  • The total number of valence electrons in SF4,is:

S + (4 x F) = 6 + (4 x 7) = 34

  • There are 4 fluorine atoms bonded to a central sulfur atom

    • So, there are 4 bonding pairs

  • The bonding pairs account for 8 electrons

    • This leaves 34 - 8 = 26 electrons

  • The remaining 30 electrons exist as 13 lone pairs

  • Fluorine cannot expand the octet

    • So, each fluorine would accommodate 3 lone pairs

    • This accounts for 24 electrons

  • This leaves 1 lone pair on the sulfur

    • Sulfur has expanded its octet, since it has 5 pairs of electrons

  • The Lewis formula for SF4 is:

Lewis structure of SF4 showing an expanded octet for sulfur containing 10 electrons

The octet of the central sulfur atom has been expanded to hold 10 electrons

Triiodide ion, l3-

  • The total number of valence electrons in I3-,is:

(3 x I) + 1 electron = (3 x 7) + 1 = 22

  • There are two iodine atoms bonded to a central iodine atom

    • So, there are 2 bonding pairs

  • The bonding pairs account for 4 electrons

    • This leaves 22 - 4 = 18 electrons

  • The remaining 18 electrons exist as 9 lone pairs

  • Each outer iodine accommodates 3 lone pairs

    • This accounts for 12 electrons

  • This leaves 3 lone pairs on the central iodine atom

    • The central iodine atom has expanded its octet, since it has 5 pairs of electrons

  • The Lewis formula for I3- is:

Lewis structure of I3 showing an expanded octet for iodine containing 10 electrons

The octet of the central iodine atom has been expanded to hold 10 electrons

Worked Example

Draw the Lewis formula for chlorine trifluoride, ClF3.

Answer:

  • The total number of valence electrons in ClF3,is:

Cl + (3 x F) = 7 + (3 x 7) = 28

  • 3 fluorine atoms bonded to a central chlorine atom = 3 bonding pairs

  • This leaves 22 electrons, existing as 11 lone pairs

  • Each fluorine accommodates 3 lone pairs, accounting for 18 electrons

  • This leaves 2 lone pairs on the chlorine

  • The Lewis formula for ClF3 is:

Lewis structure of ClF3 showing an expanded octet for chlorine containing 10 electrons

Expansion to six electron pairs

  • Molecules with six electron domains around the central atom adopt an octahedral electron domain geometry

  • Examples of chemicals where an octet is expanded to six electron pairs include:

    • Sulfur hexafluoride, SF6

    • Bromine pentafluoride, BrF5

    • Xenon tetrafluoride, XeF4

Sulfur hexafluoride, SF6

  • The total number of valence electrons in SF6,is:

S + (6 x F) = 6 + (6 x 7) = 48

  • There are 6 fluorine atoms bonded to a central sulfur atom

    • So, there are 6 bonding pairs

  • The bonding pairs account for 12 electrons

    • This leaves 48 - 12 = 36 electrons

  • The remaining 36 electrons exist as 18 lone pairs

    • This means that each fluorine atom has 3 lone pairs

  • Sulfur has expanded its octet, since it has 6 pairs of electrons

  • The Lewis formula for SF6 is: 

Lewis structure of SF6 showing an expanded octet for sulfur containing 12 electrons

The octet of the central sulfur atom has been expanded to hold 12 electrons

Bromine pentafluoride, BrF5

  • The total number of valence electrons in BrF5,is:

Br + (5 x F) = 7 + (5 x 7) = 42

  • There are 5 fluorine atoms bonded to a central bromine atom

    • So, there are 5 bonding pairs

  • The bonding pairs account for 10 electrons

    • This leaves 42 - 10 = 32 electrons

  • The remaining 32 electrons exist as 16 lone pairs

  • Fluorine cannot expand the octet

    • So, each fluorine would accommodate 3 lone pairs

    • This accounts for 30 electrons

  • This leaves 1 lone pair on the bromine

    • Bromine has expanded its octet, since it has 6 pairs of electrons

  • The Lewis formula for BrF5 is: 

Lewis structure of BrF5 showing an expanded octet for bromine containing 12 electrons

The octet of the central bromine atom has been expanded to hold 12 electrons

Worked Example

Draw the Lewis formula for xenon tetrafluoride, XeF4.

Answer:

  • The total number of valence electrons in XeF4,is:

Xe + (4 x F) = 8 + (4 x 7) = 36

  • 4 fluorine atoms bonded to a central xenon atom = 4 bonding pairs

  • This leaves 28 electrons, existing as 14 lone pairs

  • Each fluorine accommodates 3 lone pairs, accounting for 24 electrons

  • This leaves 2 lone pairs on the xenon

  • The Lewis formula for XeF4 is: 

Lewis structure of xenon tetrafluoride with a central Xe atom, surrounded by four F atoms, each with three lone pairs, forming a square planar shape.

Revisiting Valence Shell Electron Pair Repulsion Theory (VSEPR)

  • The shapes and bond angles of molecules can be predicted using VSEPR theory

  • This theory is based on three core rules:

    1. All bonding and lone pairs arrange themselves to be as far apart as possible

    2. Lone pairs repel more strongly than bonding pairs

    3. Multiple bonds behave like a single bonding region when predicting shape

  • These principles apply to molecules with both expanded and unexpanded octets

Molecular geometry versus electron domain geometry

  • In exam questions, it’s important to distinguish between:

    • Electron domain geometry

      • This is the arrangement of all electron pairs (bonding and lone) around the central atom

    • Molecular geometry

      • This is the arrangement of the atoms in space

  • Electron domain geometry and molecular geometry can be the same

    • However, if lone pairs are present the geometries often differ

Electron domain and molecular geometry of water

  • The Lewis formula for H2O shows two bonding pairs and two lone pairs around the oxygen atom

    • So, there are four electron pairs

    • This makes the electron domain geometry tetrahedral

  • Only the bonded atoms count for molecular shape

    • The molecular geometry is bent (also called angular, bent linear or V-shaped)

    • The bond angle is approximately 104.5°

Diagram showing the Lewis structure and molecular shape of water with an angle of approximately 104.5° between hydrogen atoms.
The Lewis formula of water shows four electron domains, giving a tetrahedral electron domain geometry. The molecular geometry is bent.

Molecular geometry with five electron domains

  • The molecular geometry of species with five electron domains depends on the number of lone and bonding pairs

  • 5 bonding pairs, 0 lone pairs:

    • Electron domain geometry = trigonal bipyramidal

    • Molecular geometry = trigonal bipyramidal

    • Example = PCl5

      • PCl5  is a symmetrical molecule

      • This makes it nonpolar as any dipoles cancel out

Diagram of phosphorus pentachloride showing bond angles: 90°, 120°, and 180°. Central phosphorus atom with five chlorine atoms bonded.
  • 4 bonding pairs, 1 lone pair

    • Electron domain geometry = trigonal bipyramidal

    • Molecular geometry = seesaw

    • Example = SF4

      • SF4 is an asymmetrical molecule

      • It has one lone pair on one side of the central axis making the overall molecule polar

sf4-shape-and-angles
  • 3 bonding pairs, 2 lone pairs

    • Electron domain geometry = trigonal bipyramidal

    • Molecular geometry = T-shaped

    • Example = ClF3

      • ClF3 is an asymmetrical molecule

      • It has two lone pairs on one side of the central axis making the overall molecule polar

clf3-shape-and-angles
  • 2 bonding pairs, 3 lone pairs

    • Electron domain geometry = trigonal bipyramidal

    • Molecular geometry = linear  

    • Example = I3-

i3-shape-

Molecular geometry with six electron domains

  • The molecular geometry of species with six electron domains depends on the number of lone and bonding pairs

  • 6 bonding pairs, 0 lone pairs:

    • Electron domain geometry = octahedral

    • Molecular geometry = octahedral

    • Example = SF6

      • SF6 is a symmetrical molecule

      • This makes it nonpolar as any dipoles cancel out

sf6-shape-
  • 5 bonding pairs, 1 lone pair

    • Electron domain geometry = octahedral

    • Molecular geometry = square pyramidal

    • Example = BrF5

      • BrF5 is an asymmetrical molecule

      • It has one lone pair at the base making the overall molecule polar

brf5-shape-
  • 4 bonding pairs, 2 lone pairs

    • Electron domain geometry = octahedral

    • Molecular geometry = square planar

    • Example = XeF4

      • XeF4 is non-polar despite having two lone pairs

      • The bonding pairs are at 90o to the plane

      • The lone pairs are at 180o

      • The lone pairs are arranged above and below the square plane

        • This results in an even distribution of electron cloud charge

Diagram of a XeF4 molecule showing a central xenon atom with four surrounding fluorine atoms and lone pairs, in a square planar shape.

Worked Example

What is the electron domain geometry, molecular geometry and F-Xe-F bond angle of xenon difluoride, XeF2?

Answer

  • Count the valence electrons = Xe + 2F = 8 + (2 x 7) = 22

    • 2 bonding pairs = 4 electrons

    • This leaves 18 electrons

  • Each fluorine gets 3 lone pairs

    • This accounts for 6 pairs or 12 electrons

    • This leaves 3 lone pairs on the central xenon atom

  • XeF2 has 2 bonding pairs and 3 lone pairs

  • This means that:

    • Electron domain geometry = trigonal bipyramid

    • Molecular geometry = linear

    • F-Xe-F bond angle = 180

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Richard Boole

Author: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Philippa Platt

Reviewer: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener