Expansion of the Octet (HL) (DP IB Chemistry): Revision Note
Expansion of the octet
Some elements in period 3 or higher can form molecules where the central atom holds more than eight electrons
This is possible because these elements have vacant d-orbitals in their valence shell
These orbitals can accommodate extra bonding pairs of electrons
This phenomenon is called the expansion of the octet
It explains the existence of structures like:
PCl5 – with five bonding pairs
SF6 – with six bonding pairs
Expansion to five electron pairs
Molecules with five electron domains around the central atom adopt a trigonal bipyramidal electron domain geometry
Molecular geometry depends on:
How many domains are bonding pairs
How many domains are lone pairs
Examples of chemicals where an octet is expanded to five electron pairs include:
Phosphorus pentachloride, PCl5
Chlorine trifluoride, ClF3
The triiodide ion, l3-
Sulfur tetrafluoride, SF4
Phosphorus pentachloride, PCl5
The total number of valence electrons in PCl5,is:
P + (5 x Cl) = 5 + (5 x 7) = 40
There are 5 chlorine atoms bonded to a central phosphorus atom
So, there are 5 bonding pairs
The bonding pairs account for 10 electrons
This leaves 40 - 10 = 30 electrons
The remaining 30 electrons exist as 15 lone pairs
This means that each chlorine atom has 3 lone pairs
Phosphorus has expanded its octet, since it has 5 pairs of electrons
The Lewis formula for PCl5 is:

The octet of the central phosphorous atom has been expanded to hold 10 electrons
Sulfur tetrafluoride, SF4
The total number of valence electrons in SF4,is:
S + (4 x F) = 6 + (4 x 7) = 34
There are 4 fluorine atoms bonded to a central sulfur atom
So, there are 4 bonding pairs
The bonding pairs account for 8 electrons
This leaves 34 - 8 = 26 electrons
The remaining 30 electrons exist as 13 lone pairs
Fluorine cannot expand the octet
So, each fluorine would accommodate 3 lone pairs
This accounts for 24 electrons
This leaves 1 lone pair on the sulfur
Sulfur has expanded its octet, since it has 5 pairs of electrons
The Lewis formula for SF4 is:

The octet of the central sulfur atom has been expanded to hold 10 electrons
Triiodide ion, l3-
The total number of valence electrons in I3-,is:
(3 x I) + 1 electron = (3 x 7) + 1 = 22
There are two iodine atoms bonded to a central iodine atom
So, there are 2 bonding pairs
The bonding pairs account for 4 electrons
This leaves 22 - 4 = 18 electrons
The remaining 18 electrons exist as 9 lone pairs
Each outer iodine accommodates 3 lone pairs
This accounts for 12 electrons
This leaves 3 lone pairs on the central iodine atom
The central iodine atom has expanded its octet, since it has 5 pairs of electrons
The Lewis formula for I3- is:

The octet of the central iodine atom has been expanded to hold 10 electrons
Worked Example
Draw the Lewis formula for chlorine trifluoride, ClF3.
Answer:
The total number of valence electrons in ClF3,is:
Cl + (3 x F) = 7 + (3 x 7) = 28
3 fluorine atoms bonded to a central chlorine atom = 3 bonding pairs
This leaves 22 electrons, existing as 11 lone pairs
Each fluorine accommodates 3 lone pairs, accounting for 18 electrons
This leaves 2 lone pairs on the chlorine
The Lewis formula for ClF3 is:

Expansion to six electron pairs
Molecules with six electron domains around the central atom adopt an octahedral electron domain geometry
Examples of chemicals where an octet is expanded to six electron pairs include:
Sulfur hexafluoride, SF6
Bromine pentafluoride, BrF5
Xenon tetrafluoride, XeF4
Sulfur hexafluoride, SF6
The total number of valence electrons in SF6,is:
S + (6 x F) = 6 + (6 x 7) = 48
There are 6 fluorine atoms bonded to a central sulfur atom
So, there are 6 bonding pairs
The bonding pairs account for 12 electrons
This leaves 48 - 12 = 36 electrons
The remaining 36 electrons exist as 18 lone pairs
This means that each fluorine atom has 3 lone pairs
Sulfur has expanded its octet, since it has 6 pairs of electrons
The Lewis formula for SF6 is:

The octet of the central sulfur atom has been expanded to hold 12 electrons
Bromine pentafluoride, BrF5
The total number of valence electrons in BrF5,is:
Br + (5 x F) = 7 + (5 x 7) = 42
There are 5 fluorine atoms bonded to a central bromine atom
So, there are 5 bonding pairs
The bonding pairs account for 10 electrons
This leaves 42 - 10 = 32 electrons
The remaining 32 electrons exist as 16 lone pairs
Fluorine cannot expand the octet
So, each fluorine would accommodate 3 lone pairs
This accounts for 30 electrons
This leaves 1 lone pair on the bromine
Bromine has expanded its octet, since it has 6 pairs of electrons
The Lewis formula for BrF5 is:

The octet of the central bromine atom has been expanded to hold 12 electrons
Worked Example
Draw the Lewis formula for xenon tetrafluoride, XeF4.
Answer:
The total number of valence electrons in XeF4,is:
Xe + (4 x F) = 8 + (4 x 7) = 36
4 fluorine atoms bonded to a central xenon atom = 4 bonding pairs
This leaves 28 electrons, existing as 14 lone pairs
Each fluorine accommodates 3 lone pairs, accounting for 24 electrons
This leaves 2 lone pairs on the xenon
The Lewis formula for XeF4 is:

Revisiting Valence Shell Electron Pair Repulsion Theory (VSEPR)
The shapes and bond angles of molecules can be predicted using VSEPR theory
This theory is based on three core rules:
All bonding and lone pairs arrange themselves to be as far apart as possible
Lone pairs repel more strongly than bonding pairs
Multiple bonds behave like a single bonding region when predicting shape
These principles apply to molecules with both expanded and unexpanded octets
Molecular geometry versus electron domain geometry
In exam questions, it’s important to distinguish between:
Electron domain geometry
This is the arrangement of all electron pairs (bonding and lone) around the central atom
Molecular geometry
This is the arrangement of the atoms in space
Electron domain geometry and molecular geometry can be the same
However, if lone pairs are present the geometries often differ
Electron domain and molecular geometry of water
The Lewis formula for H2O shows two bonding pairs and two lone pairs around the oxygen atom
So, there are four electron pairs
This makes the electron domain geometry tetrahedral
Only the bonded atoms count for molecular shape
The molecular geometry is bent (also called angular, bent linear or V-shaped)
The bond angle is approximately 104.5°

Molecular geometry with five electron domains
The molecular geometry of species with five electron domains depends on the number of lone and bonding pairs
5 bonding pairs, 0 lone pairs:
Electron domain geometry = trigonal bipyramidal
Molecular geometry = trigonal bipyramidal
Example = PCl5
PCl5 is a symmetrical molecule
This makes it nonpolar as any dipoles cancel out

4 bonding pairs, 1 lone pair
Electron domain geometry = trigonal bipyramidal
Molecular geometry = seesaw
Example = SF4
SF4 is an asymmetrical molecule
It has one lone pair on one side of the central axis making the overall molecule polar

3 bonding pairs, 2 lone pairs
Electron domain geometry = trigonal bipyramidal
Molecular geometry = T-shaped
Example = ClF3
ClF3 is an asymmetrical molecule
It has two lone pairs on one side of the central axis making the overall molecule polar

2 bonding pairs, 3 lone pairs
Electron domain geometry = trigonal bipyramidal
Molecular geometry = linear
Example = I3-

Molecular geometry with six electron domains
The molecular geometry of species with six electron domains depends on the number of lone and bonding pairs
6 bonding pairs, 0 lone pairs:
Electron domain geometry = octahedral
Molecular geometry = octahedral
Example = SF6
SF6 is a symmetrical molecule
This makes it nonpolar as any dipoles cancel out

5 bonding pairs, 1 lone pair
Electron domain geometry = octahedral
Molecular geometry = square pyramidal
Example = BrF5
BrF5 is an asymmetrical molecule
It has one lone pair at the base making the overall molecule polar

4 bonding pairs, 2 lone pairs
Electron domain geometry = octahedral
Molecular geometry = square planar
Example = XeF4
XeF4 is non-polar despite having two lone pairs
The bonding pairs are at 90o to the plane
The lone pairs are at 180o
The lone pairs are arranged above and below the square plane
This results in an even distribution of electron cloud charge

Worked Example
What is the electron domain geometry, molecular geometry and F-Xe-F bond angle of xenon difluoride, XeF2?
Answer
Count the valence electrons = Xe + 2F = 8 + (2 x 7) = 22
2 bonding pairs = 4 electrons
This leaves 18 electrons
Each fluorine gets 3 lone pairs
This accounts for 6 pairs or 12 electrons
This leaves 3 lone pairs on the central xenon atom
XeF2 has 2 bonding pairs and 3 lone pairs
This means that:
Electron domain geometry = trigonal bipyramid
Molecular geometry = linear
F-Xe-F bond angle = 180o
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