Second Order Differential Equations (DP IB Applications & Interpretation (AI)): Revision Note
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Euler's method: second order
What is a second order differential equation?
- A second order differential equation is a differential equation containing one or more second derivatives 
- In this course you consider second order differential equations of the form 
- Some examples include; 
How do I apply Euler’s method to second order differential equations?
- You need to turn the second order differential equation into a pair of coupled first order differential equations 
- Use the substitution - Then 
 
- The pair of equations then becomes the system 
- You can then use Euler's method in the same way 
- Write down the recursion equations using the formulae from the exam formula booklet: - h in those equations is the step size 
- The exam question will usually tell you the correct value of h to use 
 
 
- Use the recursion feature on your GDC to calculate the Euler’s method approximation over the correct number of steps - The values for - , - and - will come from the boundary conditions given in the question 
- Frequently you will be given an initial condition - Look out for terms like ‘initially’ or ‘at the start’ 
- In this case 
 
 
Worked Example
Consider the second order differential equation .
a) Show that the equation above can be rewritten as a system of coupled first order differential equations.

b) Initially  and 
. By applying Euler’s method with a step size of 0.1, find approximations for the values of 
 and 
 when 
 .

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Exact solutions of second order differential equations
How can I find the exact solution for a second order differential equation?
- You might be asked to find exact solutions to second order differential equations of the form - where - and - are constants 
 
- Use the substitution - to turn it into a coupled differential equation 
- This can be written in the form 
- You can then investigate the solutions of the coupled differential equations - The characteristic equation is 
 
- If the eigenvalues - and - are real, distinct, non-zero - The exact solution is of the form - Where - and - are constants 
 
- You can find the value of the constants given initial or boundary conditions - Remember that 
- This helps if you are given the initial value of 
 
 
Examiner Tips and Tricks
In your exam, the eigenvalues will always be real, distinct and non-zero for these questions. The formula  is given in the formula booklet.
- For example, consider - The eigenvalues of - are 1 and 3 
- The general solution is 
 
Worked Example
Consider the second order differential equation . Initially 
 and  
.
a) Show that the equation above can be rewritten as a system of coupled first order differential equations.

b) Given that the matrix  has eigenvalues of 1 and -4 with corresponding eigenvectors 
 and 
, find the exact solution to the second order differential equation.

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