Mass Spectrometry (MS) Fragmentation Patterns (HL) (DP IB Chemistry): Revision Note

Philippa Platt

Written by: Philippa Platt

Reviewed by: Richard Boole

Updated on

Mass spectrometry (MS) fragmentation patterns

  • To analyse a sample in a mass spectrometer:

    • The molecules are vaporised

    • Then bombarded with a beam of high-speed electrons

  • The high speed electrons knock an electron off some of the molecules, creating molecular ions (M+):

molecule rightwards arrow with electron space bombardment on topmolecular ion (Mplus bullet) + e-

  • The detected ions produce a mass spectrum

    • This is a molecular fingerprint used to identify compounds via a spectral database

  • The peak with the highest m/z value is the molecular ion (M+) peak

  • In addition to the molecular ion peak, many compounds show a smaller [M+1] peak due to the presence of the carbon-13 isotope (13C)

The M+1 peak

  • The [M+1] peak is a smaller peak next to the molecular ion peak

Mass spectrum of pent-1-ene

The mass spectrum of pent-1-ene
The peak at m/z = 70 corresponds to the molecular mass of pent-1-ene, with an [M+1] peak at m/z = 71
  • The height of the [M+1] peak depends on the number of carbon atoms in the molecule:

    • More carbon atoms means a higher [M+1] peak

    • For example, hexane (6 carbon atoms) has a larger [M+1] peak than ethane (2 carbon atoms)

Worked Example

Determine whether the following mass spectrum belongs to propanal or butanal.

Mass spectrum of propanal worked example

Answer:

  • The molecular ion of propanal is CH3CH2CHO+

    • Mr = (3 x 12.01) + (6 x 1.01) + 16.00 = 58.09

  • The molecular ion of butanal is CH3CH2CH2CHO+

    • Mr = (4 x 12.01) + (8 x 1.01) + 16.00 = 72.12

  • So, the mass spectrum corresponds to propanal as the molecular ion peak is at m/z = 58

Fragmentation patterns

  • The molecular ion peak gives the molecular mass (Mᵣ) of the compound

  • However, different compounds can have the same molecular mass

  • To confirm the structure, fragmentation analysis is used

Diagram showing different ways that a molecule can split during mass spectroscopy
Fragmentation of the molecular ion produces a range of positively charged fragments. Only ions are detected by the mass spectrometer.
  • Fragments arise due to:

    • The formation of characteristic fragments

      • CH3+ at m/z = 15

      • C2H5+ at m/z = 29

    • The loss of small molecules

      • H2O at m/z = 18

      • CO at m/z = 28

      • CO2 at m/z = 44

  • The IB Chemistry data booklet (Section 22) contains a list of common neutral fragments lost:

Mass lost (Mr)

Possible neutral fragment lost

15

bulletCH3

17

bulletOH

18

H2O

28

CH2=CH2
CO

29

bulletCH2CH3
bulletCHO

31

bulletOCH3

45

bulletCOOH

Alkanes and alkyl cations

  • In alkanes, fragmentation typically occurs by breaking C–C bonds

  • The resulting fragments are alkyl cations with identifiable m/z values:

Mass lost (Mr)

Possible fragment lost

15

CH3+

29

C2H5+

43

C3H7+

57

C4H9+

71

C5H11+

85

C6H13+

Fragmentation in a mass spectrum

Mass spectrum graph displaying peaks at m/e values 43, 56, 57 (C4H9⁺), 71 (C5H11⁺), 113 (C8H17⁺), and 142, showing relative abundance.
Mass spectrum of an alkane showing characteristic alkyl fragment peaks

Halogenoalkanes

  • Halogenoalkanes often show multiple peaks around the molecular ion

    • This is caused by the presence of different isotopes of the halogen

Mass spectrum of a bromine-containing compound

  • Bromine exists as two major isotopes: 79Br and 81Br

    • These are present in roughly equal abundance

  • So compounds containing bromine show two molecular ion peaks of similar height:

    • M (with 79Br)

    • M + 2 (with 81Br)

Mass spectrum graph showing molecular ion peaks at m/z 108 and 110. Texts explain peaks with similar height due to bromine isotopes 79Br and 81Br.
Mass spectrum of a brominated compound showing isotopic molecular ion peaks

Alcohols

  • Alcohols often undergo dehydration

    • This produces a peak 18 units below the molecular ion

  • The CH2OH+ fragment is also commonly observed at m/z = 31

Fragmentation in propan-1-ol

  • The following fragmentation patterns are commonly observed in propan-1-ol:

Mass lost (Mr)

Possible fragment lost

Reason

29

C2H5+

Loss of bulletCH2OH

31

CH2OH+

Characteristic alcohol fragment

42

C3H6+

Loss of H2O

59

C3H7O+

Loss of Hbullet

Mass spectrum for propan-1-ol showing peaks at m/z 29, 31, 42, 59, 60. Annotations indicate fragment ions and processes, including loss of water.
Mass spectrum of propan-1-ol showing characteristic alcohol fragmentation patterns

Worked Example

Alcohol fragmentation

Which alcohol is not likely to have a fragment ion at m/z at 43 in its mass spectrum?

A. (CH3)2CHCH2OH

B. CH3CH(OH)CH2CH2CH3

C. CH3CH2CH2CH2OH

D. CH3CH2CH(OH)CH3

Answer:

The correct answer is option D - CH3CH2CH(OH)CH3 (2-butanol)

  • A fragment at m/z = 43 typically indicates one of the following ions:

    • CH3CH2CH2+

    • (CH3)2CH+

  • D is unlikely to form either of these fragments

    • Therefore, it is not expected to produce a peak at m/z = 43

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Philippa Platt

Author: Philippa Platt

Expertise: Chemistry Content Creator

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener

Richard Boole

Reviewer: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.