Ionisation Energy Trends Across a Period (HL) (DP IB Chemistry): Revision Note
Ionisation energy trends across a period
The trends in ionisation energy across a period and down a group have been discussed in our revision note on Periodicity
Trends in ionisation energy across a period provide evidence for the existence of energy sublevels
Graph showing ionisation energies From H to Ne

The ionisation energy across a period increases due to the following factors:
Across a period the nuclear charge increases
The distance between the nucleus and outer electron remains reasonably constant
The shielding by inner shell electrons remains the same
There is a rapid decrease in ionisation energy between the last element in one period and the first element in the next period caused by:
The increased distance between the nucleus and the outer electrons
The increased shielding by inner electrons
These two factors outweigh the increased nuclear charge
Exceptions to the general trend in ionisation energy
There are two key exceptions to the general trend across Period 2:
Beryllium and boron
Nitrogen and oxygen
Both exceptions provide evidence for the existence of energy sublevels
Beryllium and boron
Beryllium has:
A first ionisation energy value of 900 kJ mol-1
An electron configuration of 1s2 2s2
Boron has:
A first ionisation energy value of 801 kJ mol-1
An electron configuration of 1s2 2s2 2p1
There is a slight decrease in 1st I.E. between beryllium and boron, because:
The electron removed from boron is in a 2p orbital
2p orbitals are higher in energy than 2s orbitals
The 2p electron experiences slightly more shielding than the 2s electron in beryllium
This means that the outer electron of boron:
Is further from the nucleus
Experiences a weaker attraction to the nucleus
Requires less energy to remove
The increased nuclear charge is not enough to outweigh these factors
Nitrogen and oxygen
Nitrogen has:
A first ionisation energy of 1402 kJ mol-1
An electron configuration of 1s2 2s2 2p3
Oxygen has:
A first ionisation energy of 1314 kJ mol-1
An electron configuration of 1s2 2s2 2p4
There is a slight decrease in 1st I.E. between nitrogen and oxygen, because:
In nitrogen, all three 2p electrons occupy separate orbitals
There is no electron pairing
In oxygen, the fourth electron is in a 2p orbital that contains a pair of electrons
The electron pairing in oxygen increases electron–electron repulsion
This means that the outer 2p electron of oxygen:
Is slightly higher in energy
Requires less energy to remove
The increased nuclear charge is not enough to outweigh the electron–electron repulsion
Summary of ionisation energy trends
Across a period
Nuclear charge increases
So, there is a stronger attraction between the nucleus and the outer electrons
Number of electron shells is constant
So, the outer electrons are approximately the same distance from the nucleus
Shielding remains reasonably constant
Atomic radius decreases
This is due to the increased nuclear charge pulling electrons closer
The outer electron is held more tightly and requires more energy to remove
Down a group
Nuclear charge increases
But, this effect is outweighed by other factors
Number of electron shells increases
So, the outer electrons are further from the nucleus
Shielding increases
There are more inner shells repelling the outermost electron
Atomic radius increases
The outer electron is held more loosely and requires less energy to remove
You've read 0 of your 5 free revision notes this week
Unlock more, it's free!
Did this page help you?