Permutations (DP IB Analysis & Approaches (AA)): Revision Note
Permutations
What are Permutations?
A permutation is the number of possible arrangements of a set of objects when the order of the arrangements matters
A permutation can either be finding the number of ways to arrange n items or finding the number of ways to arrange r out of n items
How many ways can n different objects be arranged?
When considering how many ways you can arrange a number of different objects in a row consider how many of the objects can go in the first position, how many can go in the second and so on
For n = 2 there are two options for the first position and then there will only be one option to go in the second position so:
The first object has two places it could go and the second object has one place
By the fundamental counting principle both objects have 2 × 1 places to go
For example to arrange the letters A and B we have
AB and BA
For n = 3 there are three options for the first position and then there will be two options for the second position and one for the third position so
The first object has three places it could go, the second object has two places and the third object has one place
By the fundamental counting principle the three objects have 3 × 2 × 1 places to go
For example to arrange the letters A, B and C we have
ABC, ACB, BAC, BCA, CAB and CBA
For n objects there are n options for the first position, n - 1 options for the second position and so on until there is only one object left to go in final position
The number of permutations of n different objects is n factorial (n!)
Where
For 5 different items there are
permutations
For 6 different items there are
permutations
It is easy to see how quickly the number of possible permutations of different items can increase
For 10 different items there are 10! = 3 628 800 possible permutations
What are factorials?
Factorials are a type of mathematical operation (just like +, -, ×, ÷)
The symbol for factorial is !
So to take a factorial of any non-negative integer, n, it will be written n! and pronounced ‘n factorial’
The factorial function for any positive integer, n, is
For example, 5 factorial is
The factorial of a negative number is not defined
You cannot arrange a negative number of items
0! = 1
There are no positive integers less than zero, so zero items can only be arranged once
Your GDC will have a mode for calculating factorials, make sure you can put yours into the correct mode
Most normal calculators cannot handle numbers greater than about 70!, experiment with yours to see the greatest value of x such that your calculator can handle x!
What are the key properties of using factorials?
Some important relationships to be aware of are:
Therefore
Therefore
Expressions with factorials in can be simplified by considering which values cancel out in the fraction
Dividing a large factorial by a smaller one allows many values to cancel out
How do we find r permutations of n items?
If we only want to find the number of ways to arrange a few out of n different objects, we should consider how many of the objects can go in the first position, how many can go in the second and so on
If we wanted to arrange 3 out of 5 different objects, then we would have 3 positions to place the objects in, but we would have 5 options for the first position, 4 for the second and 3 for the third
This would be 5 × 4 × 3 ways of permutating 3 out of 5 different objects
This is equivalent to
If we wanted to arrange 4 out of 10 different objects, then we would have 4 positions to place the objects in, but we would have 10 options for the first position, 9 for the second, 8 for the third and 7 for the fourth
This would be 10 × 9 × 8 × 7 ways of permutating 4 out of 10 different objects
This is equivalent to
If we wanted to arrange r out of n different objects, then we would have r positions to place the objects in, but we would have n options for the first position,
for the second,
for the third and so on until we reach
This would be
ways of permutating r out of n different objects
This is equivalent to
The function
can be written as
Make sure you can find and use this button on your calculator
The same function works if we have n spaces into which we want to arrange r objects, consider
for example arranging five people into a row of ten empty chairs
Permutations when two or more items must be together
If two or more items must stay together within an arrangement, it is easiest to think of these items as ‘stuck’ together
These items will become one within the arrangement
Arrange this ‘one’ item with the others as normal
Arrange the items within this ‘one’ item separately
Multiply these two arrangements together
Permutations when two or more items cannot be all together
If two items must be separated …
consider the number of ways these two items would be together
subtract this from the total number of arrangements without restrictions
If more than two items must be separated…
consider whether all of them must be completely separate (none can be next to each other) or whether they cannot all be together (but two could still be next to each other)
If they cannot all be together then we can treat it the same way as separating two items and subtract the number of ways they would all be together from the total number of permutations of the items, the final answer will include all permutations where two items are still together
If the items must all be completely separate then
lay out the rest of the items in a line with a space in between each of them where one of the items which cannot be together could go
remember that this could also include the space before the first and after the last item
You would then be able to fit the items which cannot be together into any of these spaces, using the r permutations of n items rule
You do not need to fill every space
Permutations when two or more items must be in specific places
Most commonly this would be arranging a word where specific letters would go in the first and last place
Or arranging objects where specific items have to be at the ends/in the middle
Imagine these specific items are stuck in place, then you can find the number of ways to arrange the rest of the items around these ‘stuck’ items
Sometimes the items must be grouped
for example all vowels must be before the consonants
Or all the red objects must be on one side and the blue objects must be on the other
Find the number of permutations within each group separately and multiply them together
Be careful to check whether the groups could be in either place
e.g. the vowels on one side and consonants on the other
or if they must be in specific places (the vowels before the consonants)
If the groups could be in either place than your answer would be multiplied by two
If there were n groups that could be in any order then your answer would be multiplied by n!
Examiner Tips and Tricks
The wording is very important in permutations questions, just one word can change how you answer the question
Look out for specific details such as whether three items must all be separated or just cannot be all together (there is a difference)
Pay attention to whether items must be in alternating order (e.g. red and blue items must alternate, either RBRB… or BRBR…) or whether a particular item must come first (red then blue and so on)
If items should be at the ends, look out for whether they can be at either end or whether one must be at the beginning and the other at the end
Worked Example
Find the number of ways nine different tasks can be carried out given that two particular tasks must not be carried out consecutively.

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