Factorising Quadratics (DP IB Analysis & Approaches (AA): HL): Revision Note

Factorising quadratics

Why is factorising quadratics useful?

  • Factorising gives roots (zeroes or solutions) of a quadratic

  • It gives the x-intercepts of the graph of the quadratic

How do I factorise a monic quadratic of the form x2+bx+c?

  • A monic quadratic is a quadratic where the coefficient of the x2 term is 1

  • You might be able to spot the factors by inspection

    • Especially if c is a prime number

  • Otherwise, start by finding two numbers m and n which have,

    • A sum equal to b

      • p+q=b

    • A product equal to c

      • pq=c

  • Rewrite the middle term of the quadratic, bx, as mx+nx

  • Use this to factorise x2+mx+nx+c

  • A shortcut is to write down (x+p)(x+q) as soon as you have found p and q

Worked Example

Factorise x27x+12 fully.

Answer:

2-2-2-ib-aa-sl-factorise-a-we-solution

How do I factorise a non-monic quadratic of the form ax2+bx+c?

  • A non-monic quadratic is a quadratic where the coefficient of the x2 term is not equal to 1

  • If a, b and c have a common factor then first factorise that out to leave a quadratic with coefficients that have no common factors

    • E.g. 3x2+6x45 can be rewritten as 3(x2+2x15)

  • You might be able to spot the factors by inspection

    • Especially if a and/or c are prime numbers

  • Otherwise, start by finding two numbers m and n which have,

    • A sum equal to b

      • m+n=b

    • A product equal to ac

      • mn=ac

  • Rewrite the middle term, bx, as mx+nx

  • Use this to factorise ax2+mx+nx+c

  • A shortcut is to write

    • (ax+m)(ax+n)a

    • Then factorise common factors from numerator to cancel with the a on the denominator

Worked Example

Factorise 4x2+4x15 fully.

Answer:

2-2-2-ib-aa-sl-factorise-b-we-solution

How do I use the difference of two squares to factorise a quadratic of the form a2x2-c2?

  • The difference of two squares can be used when

    • There is no linear x term and

    • The constant term is a negative

    • E.g. 9x216

  • First, square-root the two terms a2x2 and c2

  • The two factors of the quadratic are the sum of the square roots and the difference of the square roots

    • i.e. (ax+c)(axc)

    • 9x216=(3x+4)(3x4)

Worked Example

Factorise 1850x2 fully.

Answer:

2-2-2-ib-aa-sl-factorise-c-we-solution

Examiner Tips and Tricks

You can deduce the factors of a quadratic function by using your GDC to find the solutions of a quadratic equation.

Using your GDC, the quadratic equation  6x2+x2=0  has solutions  x=23  and  x=12.

Therefore the factors would be  (3x+2)  and  (2x1).

i.e.  6x2+x2=(3x+2)(2x1).

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