Quotient Rule (DP IB Analysis & Approaches (AA): HL): Revision Note

Quotient rule

What is the quotient rule?

  • The quotient rule states that if  y is a quotient of functions of x

    • i.e. if  y=uv where u=u(x) and v=v(x)

    • then

      dydx=vdudxudvdxv2 

      • This is given in the formula booklet

  • In function notation this could be written

 y=f(x)g(x)

 dydx=g(x)f'(x)f(x)g'(x)[g(x)]2

  • As with product rule, ‘dash notation’ may be used

y=uv

y'=vu'uv'v2

Examiner Tips and Tricks

In an exam, your final answers should match the notation used by the question.

How do I know when to use the quotient rule?

  • The quotient rule is used when trying to differentiate a fraction where both the numerator and denominator are functions of x

    • If the numerator is a constant, negative powers can be used

      • E.g. 2(3x7)2=2(3x7)2

        • That can be differentiated using the chain rule

    • If the denominator is a constant, treat it as a factor of the expression

      • E.g. (3x7)22=12(3x7)2

        • That can be differentiated using the chain rule or by expanding the brackets

Examiner Tips and Tricks

The quotient rule will still work if the numerator or denominator is a constant. It is just usually quicker to use another method.

How do I use the quotient rule?

  • STEP 1

    Identify the two functions, u and v

    Differentiate both u and v with respect to x to find u' and v'
     

  • STEP 2

    Obtain dydx by applying the quotient rule formula dydx=vdudxudvdxv2

    Simplify the answer if straightforward or if the question requires a particular form

Examiner Tips and Tricks

Use u, v, u' and v' for the elements of quotient rule

  • Make it clear what u, v, u' and v' are

  • Lay them out in a 'square' (imagine a 2x2 grid)

  • Those that are paired together are then on opposite diagonals (v and u',  u and v')

  • Be careful using the formula – because of the minus sign in the numerator, the order of the functions is important

For trickier functions, the chain rule may be required inside the quotient rule

  • I.e.  the chain rule may be needed to differentiate u and/or v

Examiner Tips and Tricks

Look out for functions of the form  y=f(x)(g(x))1.

These can be differentiated using a combination of chain rule and product rule (it would be good practice to try!).

But they can also be seen as a quotient rule question in disguise 

  • f(x)(g(x)1)=f(x)g(x)

...and vice versa!

  • A quotient could be seen as a product by rewriting the denominator as (g(x))1

Worked Example

Differentiate  f(x)=cos 2x3x+2  with respect to  x.

Answer:

5-2-2-ib-sl-aa-only-quotient-we-soltn

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