Exponential (Euler's) Form (DP IB Analysis & Approaches (AA)): Revision Note

Exponential (Euler's) form

What is exponential (Euler) form?

  • The exponential (Euler) form of a complex number z is

    • z equals r straight e to the power of straight i theta end exponent

    • where

      • r equals vertical line z vertical line

      • theta equals arg space z

Examiner Tips and Tricks

The exponential (Euler) form of a complex number is given in the formula booklet.

  • e.g. z equals 1 plus square root of 3 straight i has a modulus of 2 and an argument of pi over 3

    • so z equals 2 straight e to the power of fraction numerator straight i pi over denominator 3 end fraction end exponent

  • To convert back to Cartesian form

    • go via the modulus-argument (polar) form

    • e.g. z equals 4 straight e to the power of fraction numerator straight i pi over denominator 4 end fraction end exponent equals 4 open parentheses cos pi over 4 plus isin pi over 4 close parentheses is 4 open parentheses fraction numerator square root of 2 over denominator 2 end fraction plus fraction numerator square root of 2 over denominator 2 end fraction close parentheses equals 2 square root of 2 plus 2 square root of 2 space straight i

Examiner Tips and Tricks

You can put the straight i at the beginning or the end of the power (e.g. 2 straight e to the power of fraction numerator straight i pi over denominator 3 end fraction end exponent, 2 straight e to the power of fraction numerator pi straight i over denominator 3 end fraction end exponent and 2 straight e to the power of pi over 3 straight i end exponent are all the same).

How do I multiply and divide complex numbers in exponential (Euler) form?

  • If z subscript 1 equals r subscript 1 straight e to the power of straight i theta subscript 1 end exponent spaceand z subscript 2 equals r subscript 2 straight e to the power of straight i theta subscript 2 end exponent then 

    • z subscript 1 z subscript 2 equals r subscript 1 r subscript 2 straight e to the power of straight i open parentheses theta subscript 1 plus theta subscript 2 close parentheses end exponent

      • Multiply the moduli and add the arguments

    • z subscript 1 over z subscript 2 equals r subscript 1 over r subscript 2 straight e to the power of straight i open parentheses theta subscript 1 minus theta subscript 2 close parentheses end exponent

      • Divide the moduli and subtract the arguments

  • These rules makes multiplying and dividing easier in exponential (Euler) form than in Cartesian form!

  • Powers of complex numbers are also easier in exponential (Euler) form

    • You can use index laws

      • e.g. z equals r straight e to the power of straight i theta end exponent,  z squared equals r squared straight e to the power of 2 straight i theta end exponent  and  z to the power of n equals r to the power of n straight e to the power of ni theta end exponent

Examiner Tips and Tricks

It is common for questions to use the range 0 less or equal than theta less than 2 pi for arguments in exponential (Euler) form.

What numbers do I need to know in exponential (Euler) form?

  • You should know the following numbers in exponential (Euler) form

  • straight e to the power of 2 pi straight i end exponent equals 1

    • as cos space left parenthesis 2 pi right parenthesis equals 1 and sin space left parenthesis 2 pi right parenthesis equals 0

    • similarly 1 equals straight e to the power of 0 equals straight e to the power of 2 pi straight i end exponent equals straight e to the power of 4 pi straight i end exponent equals straight e to the power of 6 pi straight i end exponent equals straight e to the power of 2 k pi straight i end exponent

      • for all even multiples of pi

  • straight e to the power of pi straight i end exponent equals negative 1

    • as cos invisible function application open parentheses pi close parentheses equals negative 1 and sin invisible function application left parenthesis pi right parenthesis equals 0 

    • straight e to the power of pi straight i end exponent equals negative 1 can be rearranged to straight e to the power of straight i pi end exponent plus 1 equals 0

      • known as Euler's identity

      • often considered the most elegant relationship in Mathematics!

  • straight e to the power of pi over 2 straight i end exponent equals straight i

    • as cos invisible function application open parentheses pi over 2 close parentheses equals 0 and sin invisible function application open parentheses pi over 2 close parentheses equals 1 

Worked Example

Consider the complex number z equals 2 straight e to the power of pi over 3 straight i end exponent.

Calculate z squared, giving your answer in the form r straight e to the power of straight i theta end exponent where r greater than 0 and 0 less or equal than theta less than 2 pi.

1-9-2-ib-aa-hl-forms-of-cn-we-solution-2-eulers

You've read 0 of your 5 free revision notes this week

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.