Trigonometric Proof (DP IB Analysis & Approaches (AA)): Revision Note

Amber

Written by: Amber

Reviewed by: Dan Finlay

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Trigonometric proof

What identities might I have to use during a proof?

  • You are given the following identities in the SL section of the formula booklet

    • Identity for tan theta

      • tan invisible function application theta equals fraction numerator sin invisible function application theta over denominator cos invisible function application theta end fraction

    • Pythagorean identity

      • cos squared invisible function application theta blank plus sin squared invisible function application theta equals 1

    • Double angle identities

      • sin invisible function application 2 theta equals 2 sin invisible function application theta cos invisible function application theta blank

      • cos invisible function application 2 theta equals cos squared invisible function application theta minus sin squared invisible function application theta equals 2 cos squared invisible function application theta minus 1 equals 1 minus 2 sin squared invisible function application theta blank

  • You are given the following identities in the HL section of the formula booklet

    • Reciprocal trigonometric identities

      • sec invisible function application theta equals fraction numerator 1 over denominator cos invisible function application theta blank end fraction

      • cosec blank theta equals fraction numerator 1 over denominator sin invisible function application theta end fraction

    • Pythagorean identities

      • 1 plus tan squared invisible function application theta blank equals sec squared invisible function application theta blank

      • 1 plus cot squared invisible function application theta blank equals cosec squared invisible function application theta blank

    • Compound angle identities

      • sin invisible function application open parentheses A plus-or-minus B close parentheses equals sin invisible function application A cos invisible function application B blank plus-or-minus cos space A space sin invisible function application B

      • cos invisible function application open parentheses A plus-or-minus B close parentheses equals cos invisible function application A cos invisible function application B blank minus-or-plus sin space A space sin invisible function application B

      • tan invisible function application open parentheses A plus-or-minus B close parentheses equals fraction numerator tan invisible function application A blank plus-or-minus space tan invisible function application B over denominator 1 minus-or-plus tan invisible function application A tan invisible function application B end fraction

    • Double angle identity for tan

      • tan invisible function application 2 theta equals fraction numerator 2 tan invisible function application theta over denominator 1 minus tan squared invisible function application theta end fraction

  • You are not given the following identities and need to remember them

    • Reciprocal trigonometric identity for cot

      • cot invisible function application theta equals fraction numerator 1 over denominator tan invisible function application theta end fraction

    • Identity for cot theta

      • cot invisible function application theta equals fraction numerator cos invisible function application theta over denominator sin invisible function application theta end fraction

How do I prove an identity?

  • To prove an identity:

    • Select one side to start on

      • It is more common to start on the left-hand side

      • However, you can start on the right-hand side

    • Apply relevant identities to turn that expression into the one on the other side

Examiner Tips and Tricks

If you get stuck, try starting on the other side.

What should I look out for when proving trigonometric identities?

  • Check to see if any of the angles are double or half any of the others

    • You can use the double angle identities

      • e.g. you can replace sin invisible function application 6 theta with 2 sin invisible function application 3 theta cos invisible function application 3 theta blank

      • e.g. you can replace cos invisible function application 4 theta blankwith 1 minus 2 sin squared invisible function application 2 theta

      • e.g. you can replace sin theta cos theta with 1 half sin 2 theta

  • Check to see if any of the terms have an even power

    • You can use the Pythagorean identities

      • e.g. you can replace sec to the power of 4 theta with open parentheses 1 plus tan squared theta close parentheses squared

  • Check to see if any terms can cancel

    • e.g. you can replace cos 4 theta with 2 cos squared 2 theta minus 1 to cancel the 1 in the expression1 plus cos 4 theta

  • Combine any fractions

    • e.g. rewrite fraction numerator 1 over denominator cos theta end fraction plus fraction numerator 1 over denominator sin theta end fraction as fraction numerator sin theta plus cos theta over denominator cos theta sin theta end fraction

  • Always keep an eye on the 'target' expression – this can help suggest what identities to use

Examiner Tips and Tricks

Always keep an eye on the 'target' expression! This can help you spot which identities to use.

Don't forget that you can start a proof from either end. Sometimes it might be easier to start from the left-hand side, and sometimes it may be easier to start from the right-hand side.

Worked Example

Prove that 8 cos to the power of 4 invisible function application theta minus 8 cos squared invisible function application theta plus 1 equals cos invisible function application 4 theta.

3-8-1-ib-aa-hl-trig-proof-we-solution-

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Amber

Author: Amber

Expertise: Maths Content Creator

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.