Integrating Factor (DP IB Analysis & Approaches (AA)): Revision Note

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Integrating factor

What is an integrating factor?

  • An integrating factor can be used to solve a differential equation that can be written in the standard form fraction numerator d y over denominator d x end fraction plus p left parenthesis x right parenthesis y equals q left parenthesis x right parenthesis

  • For an equation in standard form, the integrating factor is straight e to the power of integral p open parentheses x close parentheses straight d x space end exponent

Examiner Tips and Tricks

Be careful – the ‘functions of xp(x) and q(x) may just be constants!

  • For example in fraction numerator d y over denominator d x end fraction plus 6 y equals straight e to the power of negative 2 x end exponent, space p left parenthesis x right parenthesis equals 6 and q left parenthesis x right parenthesis equals straight e to the power of negative 2 x end exponent

  • While in fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator 2 x end fraction equals 12, space p left parenthesis x right parenthesis equals fraction numerator 1 over denominator 2 x end fraction  and q left parenthesis x right parenthesis equals 12

  • And in fraction numerator d y over denominator d x end fraction plus y equals 1, space p left parenthesis x right parenthesis equals 1  and q left parenthesis x right parenthesis equals 1

All three of those equations can be solved using an integrating factor.

How do I use an integrating factor to solve a differential equation?

  • STEP 1
    If necessary, rearrange the differential equation into standard form
     

  • STEP 2
    Find the integrating factor space straight e to the power of integral p open parentheses x close parentheses straight d x space end exponent

    • Note that you don’t need to include a constant of integration here when you integrate  integral p open parentheses x close parentheses space straight d x

  • STEP 3
    Multiply both sides of the differential equation by the integrating factor

    • This will turn the equation into an exact differential equation of the form 

fraction numerator straight d over denominator straight d x end fraction open parentheses y straight e to the power of integral p open parentheses straight x close parentheses straight d x end exponent close parentheses equals q open parentheses x close parentheses straight e to the power of integral p open parentheses x close parentheses straight d x end exponent

  • STEP 4
    Integrate both sides of the equation with respect to x

    • The left side will automatically integrate to space y straight e to the power of integral p open parentheses x close parentheses d x end exponent

    • For the right side, integrate integral q left parenthesis x right parenthesis straight e to the power of integral p left parenthesis x right parenthesis d x end exponent d x using your usual techniques for integration

    • Don’t forget to include a constant of integration

      • Although there are two integrals, you only need to include one constant of integration

  • STEP 5
    Rearrange your solution to get it in the form y = f(x)

Examiner Tips and Tricks

The standard form for an integrating factor equation, and the form of the integrating factor, are both given in the exam formula booklet.

What else should I know about using an integrating factor to solve differential equations?

  • After finding the general solution using the steps above you may be asked to do other things with the solution

    • For example you may be asked to find the solution corresponding to certain initial or boundary conditions

Worked Example

Consider the differential equation fraction numerator straight d y over denominator straight d x end fraction equals 2 x y plus 5 straight e to the power of x squared end exponent where  y = 7  when  x = 0.

Use an integrating factor to find the solution to the differential equation with the given boundary condition.

5-10-2-ib-aa-hl-integrating-factor-we-solution

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Roger B

Author: Roger B

Expertise: Maths Content Creator

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.