Integration by Substitution (DP IB Analysis & Approaches (AA)): Revision Note

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Substitution: Reverse Chain Rule

What is integration by substitution?

  • When reverse chain rule is difficult to spot or awkward to use then integration by substitution can be used instead

    • Substitution simplifies the integral by defining an alternative variable (usuallyspace u) in terms of the original variable (usuallyspace x)

    • Everything (including “straight d x” and limits for definite integrals) is then substituted which makes the integration much easier

How do I integrate using substitution?

  • STEP 1
    Identify the substitution to be used – it will be the secondary function in the composite function

    • So if you are integrating something likespace f left parenthesis g left parenthesis x right parenthesis right parenthesis, use the substitution space u equals g left parenthesis x right parenthesis

    • E.g. integral 2 x cos open parentheses x squared close parentheses space straight d x

      • Use the substitution u equals x squared

  • STEP 2
    Differentiate the substitution and rearrange

    fraction numerator straight d u over denominator straight d x end fractioncan be treated like a fraction (i.e. “multiply byspace straight d x to get rid of fractions)

    • E.g. space u equals x squared space space rightwards double arrow space space fraction numerator straight d u over denominator straight d x end fraction equals 2 x space space rightwards double arrow space space straight d u equals 2 x straight d x

  • STEP 3

    Replace all parts of the integral

    Allspace x terms should be replaced with equivalentspace u terms, includingspace straight d x

    (If finding a definite integral change the limits fromspace x-values tospace u-values too)

    • E.g. space integral 2 x cos open parentheses x squared close parentheses space straight d x equals integral cos open parentheses x squared close parentheses space open parentheses 2 x straight d x close parentheses equals integral cos u space straight d u

  • STEP 4

    Integrate and either substitutespace x back in (indefinite integral) or evaluate using thespace u limits (definite integral)

    • E.g. space integral cos u space straight d u equals sin u plus c equals sin open parentheses x squared close parentheses plus c

  • STEP 5

    Findspace c, the constant of integration, if needed
     

  • For definite integrals, a GDC should be able to process the integral without the need for a substitution

    • Be clear about whether or not working is required in a question

Examiner Tips and Tricks

If you have your GDC with you in the exam, you can always use it to check the value of a definite integral, even in cases where working needs to be shown.

Worked Example

a) Find the integral

space integral fraction numerator 6 x plus 5 over denominator left parenthesis 3 x squared plus 5 x minus 1 right parenthesis cubed end fraction space straight d x

5-4-2-ib-sl-aa-only-we3-soltn-a

b) Evaluate the integral

           space integral subscript 1 superscript 2 fraction numerator 6 x plus 5 over denominator left parenthesis 3 x squared plus 5 x minus 1 right parenthesis cubed end fraction space straight d x

giving your answer as an exact fraction in its simplest terms.

5-4-2-ib-sl-aa-only-we3-soltn-b

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