Factor & Remainder Theorem (DP IB Analysis & Approaches (AA)): Revision Note

Lucy Kirkham

Written by: Lucy Kirkham

Reviewed by: Dan Finlay

Updated on

Factor theorem

What is the factor theorem?

  • The factor theorem states that for any polynomial function P left parenthesis x right parenthesis the following is true

    • If open parentheses a x minus b close parentheses is a factor of P open parentheses x close parentheses then P open parentheses b over a close parentheses equals 0

    • If P open parentheses b over a close parentheses equals 0 then open parentheses a x minus b close parentheses is a factor of P open parentheses x close parentheses

  • For example:

    • 2 open parentheses negative 3 close parentheses to the power of 4 plus 5 open parentheses negative 3 close parentheses cubed minus 27 equals 0

      • so open parentheses x plus 3 close parentheses is a factor of 2 x to the power of 4 plus 5 x cubed minus 27 equals 0

    • 2 x to the power of 4 minus x cubed plus 4 x squared minus 8 x plus 3 identical to open parentheses 2 x minus 1 close parentheses open parentheses x cubed plus 2 x minus 3 close parentheses

      • so 2 open parentheses 1 half close parentheses to the power of 4 minus open parentheses 1 half close parentheses cubed plus 4 open parentheses 1 half close parentheses squared minus 8 open parentheses 1 half close parentheses plus 3 equals 0

  • The factor theorem connects the roots of a polynomial equation and the factors of the polynomial function

    • Rearrange the root to make it equal to zero to find the factor

      • e.g. x equals 1 half rightwards double arrow 2 x minus 1 equals 0 so open parentheses 2 x minus 1 close parentheses would be the factor

    • Make the factor equal to zero and solve to find the root

      • e.g. 3 x plus 4 equals 0 rightwards double arrow x equals negative 4 over 3 so x equals negative 4 over 3 would be a root

How do I use the factor theorem to find unknown values?

  • You might be given a polynomial equation with one or two unknown coefficients

    • e.g. 2 x cubed minus x squared plus a x minus 3 equals 0

  • You will be given one or two factors of the polynomial expression

    • e.g. open parentheses 2 x minus 3 close parentheses is a factor

  • To find the value(s) of the unknown(s)

    • Set the factor equal to zero and solve for x

      • e.g. 2 x minus 3 equals 0 rightwards double arrow x equals 3 over 2

    • Substitute the value of x into the polynomial equation and simplify

      • e.g. 2 open parentheses 3 over 2 close parentheses cubed minus open parentheses 3 over 2 close parentheses squared plus a open parentheses 3 over 2 close parentheses minus 3 equals 0 simplifies to 3 over 2 a plus 3 over 2 equals 0

    • Solve the resulting equation(s) to find the unknown value(s)

      • e.g. a equals negative 1

How do I use the factor theorem to fully factorise a polynomial?

  • Find a root of the polynomial equation

    • Test values of the form x equals plus-or-minus p over q into the polynomial where

      • p is a factor of polynomial's constant term

      • q is a factor of the coefficient of the polynomial's leading term

    • e.g. for P open parentheses x close parentheses equals 2 x to the power of 4 plus 5 x cubed minus x squared plus 5 x minus 3 try x equals plus-or-minus 1 comma space plus-or-minus 3 comma space plus-or-minus 1 half comma space plus-or-minus 3 over 2

      • P open parentheses 1 half close parentheses equals 0 and P open parentheses negative 3 close parentheses equals 0

  • Use the factor theorem to identify factors

    • e.g. open parentheses 2 x minus 1 close parentheses and open parentheses x minus 3 close parentheses

  • Divide the polynomial by each factor

    • You can divide by one factor at a time

      • e.g. fraction numerator 2 x to the power of 4 plus 5 x cubed minus x squared plus 5 x minus 3 over denominator 2 x minus 1 end fraction equals x cubed plus 3 x squared plus x plus 3

      • e.g. fraction numerator x cubed plus 3 x squared plus x plus 3 over denominator x plus 3 end fraction equals x squared plus 1

    • Or divide by the expansion of the factors

      • e.g. fraction numerator 2 x to the power of 4 plus 5 x cubed minus x squared plus 5 x minus 3 over denominator 2 x squared plus 5 x minus 3 end fraction equals x squared plus 1

  • Check to see if the new polynomial can be factorised

Examiner Tips and Tricks

Even if you tested all possible roots in the original polynomial, you still need to check if the new polynomial has any roots. It is possible that some of the roots are repeated. For example, the factors might be open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses. Testing the original polynomial will only tell you that open parentheses x plus 1 close parentheses and open parentheses x plus 2 close parentheses are factors, it doesn't tell you how many times they appear.

  • Repeat the steps until you get a linear expression or a polynomial that cannot be factorised

  • The factorised form is the product of all the factors you found

    • e.g. 2 x to the power of 4 plus 5 x cubed minus x squared plus 5 x minus 3 equals open parentheses 2 x minus 1 close parentheses open parentheses x plus 3 close parentheses open parentheses x squared plus 1 close parentheses try

Worked Example

Determine whether left parenthesis x minus 2 right parenthesis is a factor of the following polynomials:

a) space f left parenthesis x right parenthesis equals x cubed minus 2 x squared minus x plus 2.

page1

b) space g left parenthesis x right parenthesis equals 2 x cubed plus 3 x squared minus x plus 5.

2-7-1-ib-aa-hl-factor-theorem-b-we-solution

It is given that left parenthesis 2 x minus 3 right parenthesis is a factor of space h left parenthesis x right parenthesis equals 2 x cubed minus b x squared plus 7 x minus 6.

c) Find the value of b.

mZEjMdDm_2-7-1-ib-aa-hl-factor-theorem-c-we-solution

Remainder theorem

What is the remainder theorem? 

  • The remainder theorem states that for any polynomial function P left parenthesis x right parenthesis the following is true

    • The remainder when P open parentheses x close parentheses is divided by open parentheses a x minus b close parentheses is equal to P open parentheses b over a close parentheses

  • The remainder theorem is used to find the remainder when you divide a polynomial function by a linear function

    • fraction numerator P open parentheses x close parentheses over denominator a x minus b end fraction equals Q open parentheses x close parentheses plus fraction numerator r over denominator a x minus b end fraction where

      • Q open parentheses x close parentheses is the quotient polynomial

      • r is the remainder

    • This means P open parentheses x close parentheses equals open parentheses a x minus b close parentheses Q open parentheses x close parentheses plus r

      • So P open parentheses b over a close parentheses equals 0 cross times Q open parentheses b over a close parentheses plus r equals r

  • For example:

    • 8 open parentheses 5 over 2 close parentheses cubed minus 2 open parentheses 5 over 2 close parentheses minus 15 equals 105

      • so the remainder when you divide open parentheses 8 x cubed minus 2 x minus 15 close parentheses by open parentheses 2 x minus 5 close parentheses is 105

  • The factor theorem is a special case of the remainder theorem when the remainder is zero

How do I use the remainder theorem?

  • A question will involve a polynomial being divided by a linear expression

  • You will be asked to find one of the following:

    • an unknown coefficient of the polynomial

    • an unknown coefficient of the linear expression

    • the remainder

  • Follow these steps for all the cases:

    • Set the linear expression equal to zero and solve for x

      • e.g. 3 x plus 2 equals 0 rightwards double arrow x equals negative 2 over 3

    • Substitute the value of x into the polynomial equation

      • e.g. 9 open parentheses negative 2 over 3 close parentheses cubed plus a open parentheses negative 2 over 3 close parentheses plus 5 simplifies to 7 over 3 minus 2 over 3 a

    • This is equal to the remainder

      • 7 over 3 minus 2 over 3 a equals 1

    • Solve to find any unknowns

      • a equals 2

Worked Example

Let space f left parenthesis x right parenthesis equals 2 x to the power of 4 minus 2 x cubed minus x squared minus 3 x plus 1, find the remainder R when space f left parenthesis x right parenthesis is divided by:

a) x minus 3.

2-7-1-ib-aa-hl-remainder-theorem-a-we-solution

b) x plus 2.

2-7-1-ib-aa-hl-remainder-theorem-b-we-solution

The remainder when space f left parenthesis x right parenthesis is divided by left parenthesis 2 x plus k right parenthesis is 893 over 8.

c) Given that k greater than 0, find the value of k.

2-7-1-ib-aa-hl-remainder-theorem-c-we-solution

You've read 0 of your 5 free revision notes this week

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Lucy Kirkham

Author: Lucy Kirkham

Expertise: Head of Content Creation

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Maths Subject Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.