Variable Acceleration in 2D (Edexcel A Level Maths: Mechanics): Exam Questions

Exam code: 9MA0

5 hours44 questions
1a
2 marks

A particle’s position, at time t seconds, is given by the vector

bold r space equals space open parentheses table row cell 2 t cubed space minus space 1 end cell row cell t squared space plus space 4 end cell end table close parentheses space straight m 

(i) Find the coordinates of the initial position of the particle.

(ii) Find the position vector of the particle after 6 seconds.

1b
1 mark

Explain why the particle will never pass through the origin.

2a
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2 marks

[In this question, position vectors are given relative to a fixed origin O.]

At time t seconds, a particle moving in a plane has velocity

bold v space equals space open parentheses open parentheses 2 t cubed space minus space 4 t close parentheses bold i space plus space open parentheses 2 t space minus 3 close parentheses bold j close parentheses space straight m space straight s to the power of negative 1 end exponent

Find an expression for the acceleration of the particle.

2b
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2 marks

Find the displacement of the particle from its initial position.

3a
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2 marks

[In this question, position vectors are given relative to a fixed origin O.]

The acceleration of a particle is modelled using

bold a space equals space open parentheses open parentheses 2 space minus 8 t close parentheses bold i space plus space open parentheses 6 t squared close parentheses bold j close parentheses space straight m space straight s to the power of negative 2 end exponent

where time t is measured in seconds.

Given that the particle is initially at rest, find an expression for the velocity of the particle.

3b
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3 marks

Show that the speed of the particle at time t equals 2 space seconds is 20 m s-1.

4a
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2 marks

The position vector of a particle relative to a fixed origin O, at time t seconds, is given by

bold r space equals space open parentheses open parentheses sin space t close parentheses bold i space plus open parentheses cos space 2 t close parentheses bold j close parentheses space straight m space space space space space space space space space space space space space space space 0 space less or equal than space t space less or equal than space straight pi

Find an expression for the velocity of the particle.

4b
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3 marks

When the velocity in the direction parallel to bold i is 0.5 ms-1, the velocity in the direction parallel to bold j is v subscript y.

Find the exact value of v subscript y.

5
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4 marks

[In this question, position vectors are given relative to a fixed origin O.]

The acceleration of a particle is modelled using the equation

bold a equals space open parentheses table row cell 3 t squared space minus space 1 end cell row cell 5 e to the power of negative t end exponent end cell end table close parentheses space straight m space straight s to the power of negative 2 end exponent

where time t is measured in seconds.

Given that the initial velocity is bold v equals open parentheses table row 4 row 0 end table close parentheses space straight m space straight s to the power of negative 1 end exponent find an expression for the velocity of the particle in terms of t.

6a
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3 marks

[In this question, position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its position vector bold r metres is given by

bold r space equals space open parentheses open parentheses 3 t cubed space minus space t close parentheses bold i space plus space open parentheses 2 t squared space minus space 1 close parentheses bold j close parentheses space straight m

At time t equals 0, P is at the origin O.

Find the acceleration of P at time t equals 3seconds.

6b
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2 marks

Find the magnitude of the acceleration of P at time t equals 3seconds.

7
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4 marks

[In this question, position vectors are given relative to a fixed origin O.]

The velocity bold v of a particle at time t seconds, where t greater or equal than 0, is given by

bold v space equals space open parentheses table row cell 8 t to the power of 1 half end exponent space plus space 2 t end cell row cell 3 t squared space plus space 5 t space minus space 1 end cell end table close parentheses space space straight m space straight s to the power of negative 1 end exponent

Find the magnitude of acceleration of the particle when t equals 4 seconds, giving your answer to three significant figures.

8
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4 marks

[In this question, position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its acceleration bold a space straight m space straight s to the power of negative 2 end exponent is given by

bold a bold space equals space open parentheses open parentheses 6 t space minus 2 close parentheses bold i space plus space open parentheses 4 space minus space 12 t close parentheses bold j close parentheses space straight m space straight s to the power of negative 2 end exponent

At time t equals 0, P is at rest at the origin O.

Find the position vector of P at time t seconds.

9a
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3 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

An ice skater is modelled as a particle moving on a horizontal plane. At time t seconds, where t greater or equal than 0, the position vector of the skater, bold r metres, is given by

bold r equals left parenthesis 0.2 t squared minus 0.005 t cubed right parenthesis bold i plus left parenthesis 0.5 t plus 2 right parenthesis bold j space

Find the distance of the skater from O when t equals 40.

9b
2 marks

Find an expression for the velocity of the ice skater at time t seconds.

9c
2 marks

Find an expression for the acceleration of the ice skater at time t seconds.

10a
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2 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A stone is modelled as a particle P moving in a vertical plane. At time t seconds after being thrown, where t greater or equal than 0, the velocity of P, bold v space straight m space straight s to the power of negative 1 end exponent, is given by

bold v equals space bold i plus left parenthesis 1.5 minus 0.3 t squared right parenthesis bold j

Find the speed of P at the instant it is thrown.

10b
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3 marks

Find the magnitude of the acceleration of the stone at time t equals 2.5 space seconds.

11a
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1 mark

The velocity of a particle at time t seconds is given by

bold r with bold times on top space equals space open parentheses table row cell 12 t squared space minus space 2 t end cell row cell 9 t squared space minus space 1 end cell end table close parentheses space straight m space straight s to the power of negative 1 end exponent

Find , bold r with bold times bold times on top straight m space straight s to the power of negative 2 end exponent comma at time t seconds.

11b
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2 marks

Find the position vector of the particle at time t seconds, given that its initial position is the origin.

1a
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3 marks

[In this question position vectors are given relative to a fixed origin O]

At time t seconds, where t greater or equal than 0, a particle, P, moves so that its velocity bold v ms-1 is given by

bold v equals 6 t bold i minus 5 t to the power of 3 over 2 end exponent bold j

Find the acceleration of P when t equals 4.

1b
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3 marks

When t equals 0, the position vector of P is open parentheses negative 20 bold i plus 20 bold j close parentheses m.

Find the position vector of P when t equals 4.

2a
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2 marks

[In this question, position vectors are given relative to a fixed origin.]

At time t seconds, where t greater than 0, a particle P has velocity bold v ms–1 where

bold v equals 3 t squared bold i minus 6 t to the power of 1 half end exponent bold j

Find the speed of P at time t equals 2 seconds.

2b
2 marks

Find an expression, in terms of t, bold i and bold j, for the acceleration of P at time t seconds, where t greater than 0.

2c
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4 marks

At time t equals 4 seconds, the position vector of P is open parentheses bold i minus 4 bold j close parentheses m.

Find the position vector of P at time t equals 1 second.

3a
4 marks

[In this question position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its velocity bold v bold space ms to the power of negative 1 end exponent is given by

bold v space equals space open parentheses table row cell e to the power of t space minus space t end cell row cell 0.5 t to the power of 4 end cell end table close parentheses space straight m space straight s to the power of negative 1 end exponent

When t equals 0, the particle P is at the origin O.

Find the position vector of P at time t seconds.

3b
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2 marks

Find the distance of the particle from O at time t equals 1 space straight s, giving your answer to three significant figures.

4a
3 marks

[In this question, position vectors are given relative to a fixed origin O.]

The velocity bold v of a particle at time t seconds, where t greater or equal than 0 is given by

bold v space equals space open parentheses open parentheses 10 t space minus space 3 t squared close parentheses bold i space plus space open parentheses 4 t space minus 5 close parentheses bold j close parentheses space straight m space straight s to the power of negative 1 end exponent

Find the initial acceleration of the particle.

4b
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4 marks

The particle’s initial position is at the point open parentheses 4 bold i plus 5 bold j close parentheses space straight m.

Find the distance of the particle from the origin at time space t space equals space 3 spaceseconds, giving your answer to three significant figures.

5a
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2 marks

[In this question, position vectors are given relative to a fixed origin O.]

The position vector of a boat, sailing on a lake is

 bold r equals left parenthesis 2 sin space t right parenthesis bold i plus left parenthesis 2 minus 2 cos space t right parenthesis bold j space space km 

where time t is measured in hours and t greater or equal than 0.

Show that the boat takes 2 pi hours until it first returns to O.

5b
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4 marks

Find the velocity of the boat at time t equals 2 over 3 straight pi hours.

6a
3 marks

[In this question, position vectors are given relative to a fixed origin O.]

A particle P moves in a plane with velocity, bold v space straight m space straight s to the power of negative 1 end exponent, at time t seconds where t greater or equal than 0. bold v is given by

bold v space equals space open parentheses table row cell 4 t space minus space 3 t squared end cell row cell 6 t squared space minus space 2 end cell end table close parentheses 

Find the acceleration of the particle at time  t equals 3 seconds.

6b
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3 marks

Given that its initial position is at the origin, find the position vector of the particle at time t equals 4 seconds.

7a
3 marks

[In this question bold i and bold j are horizontal unit vectors.]

An aircraft is modelled as a particle P moving in a horizontal plane. At time t seconds, where t greater or equal than 0, the acceleration of P, bold a space straight m space straight s to the power of negative 2 end exponent, is given by

bold a equals left parenthesis 30 minus 2 t right parenthesis bold i plus left parenthesis 4 t minus 3 right parenthesis bold j

When t equals 0, the velocity of P is left parenthesis 200 bold i plus 150 bold j right parenthesis space straight m space straight s to the power of negative 1 end exponent.

Find the velocity of P at time t seconds.

7b
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4 marks

Find the speed of P at time t equals 4 seconds, giving your answer in kilometres per hour to three significant figures.

8a
2 marks

A remote-controlled car is driven around a playground with velocity, bold v space straight m space straight s to the power of negative 1 end exponent, at time t seconds, given by

 bold v equals left parenthesis 0.25 right parenthesis bold i plus left parenthesis 0.5 t minus 9 right parenthesis bold j 

Find an expression for the displacement of the remote-controlled car, bold s metres, measured from its initial position.

8b
1 mark

The remote-controlled car starts from the point open parentheses 2 bold i minus 5 bold j close parentheses space straight m metres.

Find the position vector bold r of the particle from the origin at time t seconds.

8c
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2 marks

Find the distance of the remote-controlled car from the origin after 40 seconds.

9a
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5 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A spider is modelled as a particle P moving on a horizontal floor. At time t seconds, where t greater or equal than 0, the acceleration of P, bold a space straight m space straight s to the power of negative 2 end exponent, is given by

bold a equals left parenthesis 0.1 t right parenthesis bold i plus left parenthesis 0.6 t squared minus 2 t right parenthesis bold j space straight m space straight s to the power of negative 2 end exponent

The velocity of P at time t equals 0 is left parenthesis negative 1.2 bold i plus 1.8 bold j right parenthesis space straight m space straight s to the power of negative 1 end exponent.

Find the speed of P at time t equals 3.

9b
3 marks

Find the position vector of P at time t seconds.

10a
2 marks

[In this question, position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its position vector bold r metres is given by

 bold r bold space equals space left parenthesis 12 e to the power of negative 0.1 t end exponent right parenthesis bold i bold space plus space left parenthesis 24 e to the power of negative 0.2 t end exponent right parenthesis bold j space space straight m

Explain why P never reaches the origin O.

10b
2 marks

Find an expression for the velocity of P at time t seconds.

10c
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5 marks

Find the magnitude of acceleration of P at time t equals 4 seconds, giving your answer to three significant figures.

11a
4 marks

A particle’s velocity is modelled by the equation

 bold r with bold times on top space equals space open parentheses table row cell 3 t squared space minus space 6 t end cell row cell 4 space minus space 8 t cubed end cell end table close parentheses space straight m space straight s to the power of negative 1 end exponent

where t is the time in seconds.

Given that the particle is initially located at the point open parentheses table row 2 row 1 end table close parentheses space straight m, find the position vector of the particle, bold r bold space straight m, at time t seconds.

11b
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3 marks

Find the time at which the particle has zero acceleration in the horizontal direction.

12a
2 marks

[In this question, position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its position vector bold r metres is given by

bold r equals open parentheses t cubed minus 11 t squared minus 16 t plus 2 close parentheses bold i space plus open parentheses t cubed plus 2 t minus 1 close parentheses bold j

Find the velocity of P at time t seconds.

12b
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3 marks

Find the value of t at the instant when P is moving in a direction parallel to bold j.

12c
1 mark

Show that P never moves in a direction perpendicular to bold j.

13a
2 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P is moving in a horizontal plane with velocity bold v space straight m space straight s to the power of negative 1 end exponent given by

bold v equals left parenthesis 0.1 t cubed minus 3 t squared right parenthesis bold i plus left parenthesis 2 t plus 1 right parenthesis bold j

Find the acceleration of P at time t seconds.

13b
1 mark

Explain why the acceleration of P in the direction of bold j is constant.

13c
2 marks

Find the value of t, other than t equals 0, for which the acceleration of P in the direction of bold i is zero.

13d
3 marks

When t equals 0, P is at the point with position vector left parenthesis negative 3 bold i plus 5 bold j right parenthesis space straight m.

Find the position vector of P at time t seconds.

14a
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4 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

An ice skater is modelled as a particle P moving across a straight section of a frozen river. At time t seconds, where t greater or equal than 0, the position vector of P, bold r metres, is given by

bold r equals open parentheses 1 third t squared plus 1 fifth t close parentheses bold i plus open parentheses 2 t squared plus 7 t close parentheses bold j

Find the speed of P at time t equals 0, giving your answer to 3 significant figures.

14b
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4 marks

Show that the acceleration of P is constant and find the magnitude of this acceleration, giving your answer to 3 significant figures.

1
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6 marks

At time t seconds, where t greater or equal than 0, a particle P moves in the x-y plane in such a way that its velocity vms−1 is given by

bold v equals t to the power of negative 1 half end exponent bold i minus 4 t bold j

When t equals 1, P is at the point A and when t equals 4, P is at the point B.

Find the exact distance A B.

2a
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3 marks

At time t seconds, where t greater or equal than 0, a particle P moves so that its acceleration bold a ms−2 is given by

bold a equals open parentheses 1 minus 4 t close parentheses bold i plus open parentheses 3 minus t squared close parentheses bold j

At the instant when t equals 0, the velocity of P is 36 bold i ms-1.

Find the velocity of P when t equals 4.

2b
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3 marks

Find the value of t at the instant when P is moving in a direction perpendicular to bold i.

2c
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6 marks

At time t seconds, where t greater or equal than 0 , a particle Q moves so that its position vector bold r metres, relative to a fixed origin O, is given by

bold r equals open parentheses t squared minus t close parentheses bold i plus 3 t bold j

Find the value of t at the instant when the speed of Q is 5 ms−1.

3a
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3 marks

At time t seconds, where t greater or equal than 0, a particle P has velocity bold v ms–1 where

bold v equals open parentheses t squared minus 3 t plus 7 close parentheses bold i plus open parentheses 2 t squared minus 3 close parentheses bold j

Find the speed of P at time t equals 0.

3b
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2 marks

Find the value of t when P is moving parallel to open parentheses bold i plus bold j close parentheses.

3c
2 marks

Find the acceleration of P at time t seconds.

3d
2 marks

Find the value of t when the direction of the acceleration of P is perpendicular to bold i.

4a
2 marks

At time t seconds, a particle P has velocity bold v ms−1, where

bold v equals 3 t to the power of 1 half end exponent bold i minus 2 t bold j space space space space space t greater than 0

Find the acceleration of P at time t seconds, where t greater than 0.

4b
3 marks

Find the value of t at the instant when P is moving in the direction of bold i minus bold j.

4c
3 marks

At time t seconds, where t greater than 0, the position vector of P, relative to a fixed origin O, is bold r metres.

When t equals 1, bold r equals negative bold j.

Find an expression for bold r in terms of t.

4d
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6 marks

Find the exact distance of P from O at the instant when P is moving with speed 10 ms−1.

5a
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2 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A boat is modelled as a particle B moving on a lake. At time t seconds, where t greater or equal than 0, the position vector of B, bold r metres, is given by

bold r equals left parenthesis negative 20 space sin space left parenthesis t over 360 right parenthesis right parenthesis bold i plus left parenthesis 20 minus 20 space cos space left parenthesis t over 360 right parenthesis right parenthesis bold j space straight m

Show that the distance of B from O when Error converting from MathML to accessible text. is 20 square root of 2 space straight m.

5b
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5 marks

Show that the speed of B at the instant it first returns to O is 1 over 18 space straight m space straight s to the power of negative 1 end exponent.

6a
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4 marks

[In this question bold i and bold j are horizontal unit vectors.]

An aircraft is modelled as a particle P moving in a horizontal plane. Once P reaches its cruising height, at time t hours where t greater or equal than 0, the acceleration of P, bold a space km space straight h to the power of negative 2 end exponent, is given by

 bold a equals open parentheses 4 t cubed minus 6 t squared close parentheses bold i plus open parentheses 0.9 t squared minus 1 close parentheses bold j

The velocity of P at time t equals 5 is left parenthesis 400 bold i plus 40 bold j right parenthesis space km space straight h to the power of negative 1 end exponent.

Find the velocity of P at time t hours.

6b
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2 marks

Find the speed of P when t equals 0.

7a
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6 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A remote-controlled car is modelled as a particle C moving in a horizontal plane. At time t seconds, where t greater or equal than 0, the velocity of C, bold v subscript C space straight m space straight s to the power of negative 1 end exponent, is given by

bold v subscript c equals open parentheses 0.45 straight t squared plus 2 straight t minus 16 close parentheses bold i plus open parentheses 0.75 straight t squared minus 1 close parentheses bold j

When t equals 0, the position vector of C is left parenthesis negative 6 bold i plus 15 bold j right parenthesis space straight m.

(i) Find the position vector of C at time t seconds.

(ii) Find the distance of C from O at the instant when t equals 15.

7b
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3 marks

At the same time as the car starts moving, a remote-controlled truck, modelled as a particle T, is set in motion. The position vector of T, bold r subscript T​ metres, at time t seconds is given by

bold r subscript T equals left parenthesis 0.15 t cubed minus 6 right parenthesis bold i plus left parenthesis 0.25 t cubed minus 1 right parenthesis bold j

Determine the time at which the car and the truck collide.

8a
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4 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A spider is modelled as a particle P moving on a horizontal floor. At time t seconds after emerging from under a skirting board, where t greater or equal than 0, the acceleration of P, bold a space straight m space straight s to the power of negative 2 end exponent, is given by

bold a equals open parentheses 1.2 t close parentheses bold i plus 0.5 bold j

When t equals 3, the velocity of P is left parenthesis 5.4 bold i plus 1.7 bold j right parenthesis space straight m space straight s to the power of negative 1 end exponent.

Find the velocity of P at time t seconds.

8b
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4 marks

When t equals 3, the position vector of P is left parenthesis 10.4 bold i plus 5.15 bold j right parenthesis space straight m.

Find the distance of P from O at the instant it emerges from under the skirting board.

9a
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4 marks

[In this question bold i is a horizontal unit vector and bold j is a vertical unit vector directed upwards. Position vectors are given relative to a fixed origin O.]

A stone is modelled as a particle P thrown from a point O on the edge of a deep hole. At time t seconds after being thrown, where t greater or equal than 0, the velocity of P, bold v space straight m space straight s to the power of negative 1 end exponent, is given by

bold v equals open parentheses 0.2 t close parentheses bold i plus open parentheses 4 minus 0.75 straight t squared close parentheses bold j

Find the position vector of P at time t equals 4 and give an interpretation of the bold j component of this position vector.

9b
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5 marks

The hole has a depth of 384 m.

Find the magnitude of the acceleration of P at the instant it hits the bottom of the hole.

10a
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5 marks

A particle’s velocity is modelled by the equation

bold r with bold times on top space equals space open parentheses table row cell 0.75 e to the power of 1.5 t end exponent space plus space 2 t end cell row cell 5 t space minus space open parentheses t space plus 1 close parentheses to the power of negative 1 end exponent end cell end table close parentheses space straight m space straight s to the power of negative 1 end exponent space space space space space space space space space space t space greater or equal than space 0

where t is the time in seconds.

The particle’s initial displacement is open parentheses table row 0 row 0 end table close parentheses space straight m.

Find an expression for bold r, at time t seconds. State appropriate units with your answer.

10b
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4 marks

Find open vertical bar bold r with bold times bold times on top close vertical bar when t equals 1 space straight s. State appropriate units with your answer.

11a
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6 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

At time t seconds, where t greater or equal than 0, a particle P moves so that its acceleration, bold a space straight m space straight s to the power of negative 2 end exponent, is given by

bold a equals left parenthesis 4 straight t minus 3 right parenthesis bold i plus left parenthesis 4 straight t plus 5 right parenthesis bold j

When t equals 0, the velocity of P is negative 5 bold j space straight m space straight s to the power of negative 1 end exponent and P is at the origin O.

Find the distance of P from O when t equals 6.

11b
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4 marks

Find the value of t at the instant when P is moving in the direction of left parenthesis bold i plus 2 bold j right parenthesis.

12a
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2 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O on one bank of a straight river.]

An ice skater is modelled as a particle P moving across the river. The banks of the river are parallel to the vector bold i. At time t seconds, where 0 less or equal than t less or equal than 225, the position vector of P, bold r metres, is given by

bold r equals left parenthesis 2 t to the power of 1 half end exponent ​ plus t right parenthesis bold i plus t to the power of 1 half end exponent bold j

Find the distance of P from O when t equals 25.

12b
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1 mark

Given that the skater reaches the opposite bank of the river when t equals 225, find the width of the river.

12c
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4 marks

Show that the magnitude of the acceleration of P at time t seconds is given by open vertical bar bold a close vertical bar equals 0.25 square root of 5 t to the power of negative 3 end exponent end root ​ straight m space straight s to the power of negative 2 end exponent.

13a
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5 marks

[In this question bold i is a horizontal unit vector and bold j is a vertical unit vector directed upwards. Position vectors are given relative to a fixed origin O at the edge of the hole.]

A stone is modelled as a particle P projected from O. At time t seconds after projection, where t greater or equal than 0, the velocity of P, bold v space straight m space straight s to the power of negative 1 end exponent, is given by

bold v equals left parenthesis 0.4 t right parenthesis bold i plus left parenthesis 2 minus 0.3 t squared right parenthesis bold j

Find the position vector of P at the instant it returns to the level of O.

13b
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3 marks

Find the maximum height of P above O.

13c
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4 marks

The deepest known cave in the world, the Veryovkina Cave in Georgia, has a depth of 2212 m. The model predicts that the stone would take approximately 28 seconds to reach this depth.

Calculate the average vertical speed and the magnitude of the acceleration of P at t equals 28 and use these values to comment on the validity of the model.

14a
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4 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A particle P moves in a horizontal plane. At time t seconds, where t greater or equal than 0, the velocity of P, bold r with bold times on top space straight m space straight s to the power of negative 1 end exponent, is given by

bold r with bold times on top equals left parenthesis t to the power of 1 half end exponent ​ minus t right parenthesis bold i plus left parenthesis 4 left parenthesis t plus 1 right parenthesis to the power of negative 1 end exponent plus 5 t to the power of 3 over 2 end exponent ​ right parenthesis bold j space

When t equals 0, the position vector of P is left parenthesis 3 bold i plus 5 bold j right parenthesis space straight m.

Find bold r at time t seconds.

14b
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3 marks

Find the value of t at the instant when the acceleration of P is parallel to bold j.

1a
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5 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A boat is modelled as a particle B moving on a lake. At time t seconds, the displacement of B, bold s metres, relative to a fixed mooring point M is given by

bold s equals open parentheses negative 40 space sin open parentheses fraction numerator pi t over denominator 900 end fraction close parentheses close parentheses space bold i plus open parentheses 30 minus 30 space cos open parentheses fraction numerator pi t over denominator 900 end fraction close parentheses close parentheses space bold j

The position vector of M relative to O is 10 bold i space straight m.

(i) Write down an expression for the position vector of B relative to O at time t seconds.

(ii) Find the difference between the distance of B from M and the distance of B from O at the instant when t equals 225.

1b
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6 marks

(i) Find the velocity of B at time t seconds.

(ii) Given that one trip around the lake takes 30 minutes, find the values of t in the interval 0 less than t less than 1800 for which B is moving parallel to one of the coordinate axes.

2
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7 marks

[In this question bold i and bold j are horizontal unit vectors.]

An aircraft is modelled as a particle P moving in a horizontal plane. Once P reaches its cruising height, at time t hours where t greater or equal than 0, the acceleration of P, bold a space km space straight h to the power of negative 2 end exponent, is given by

bold a equals left parenthesis 3 t squared minus 1 right parenthesis bold i plus left parenthesis 8 t plus 1 right parenthesis bold j

When t equals 2, the velocity of P is bold v space km space straight h to the power of negative 1 end exponent.

Given that:

• the bold i component of bold v is positive and is double the bold j component of bold v,

• and the speed of P is 22 square root of 5 space km space straight h to the power of negative 1 end exponent,

find the velocity of P at time t seconds.

3a
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7 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

Two remote-controlled cars, coloured red and blue, are modelled as particles R and B moving on a horizontal playground. At time t seconds, where t greater or equal than 0, the velocity of R, bold v subscript R space straight m space straight s to the power of negative 1 end exponent, and the velocity of B, bold v subscript B space straight m space straight s to the power of negative 1 end exponent, are given by

bold v subscript R equals left parenthesis 0.2 t minus 1 right parenthesis bold i plus left parenthesis t minus 5 right parenthesis bold j

bold v subscript B equals left parenthesis 0.2 t right parenthesis bold i plus left parenthesis t minus 7 right parenthesis bold j

When t equals 0, the position vector of R is left parenthesis negative 2.4 bold i plus 8 bold j right parenthesis space straight m and the position vector of B is left parenthesis negative 2.4 bold i minus 4 bold j right parenthesis space straight m.

Find the value of t, where t greater or equal than 5, when R and B are equidistant from O and find the distance of the cars from O at this instant.

3b
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2 marks

Hence show that R and B do not collide at this instant.

4a
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4 marks

[In this question bold i and bold j are horizontal unit vectors and position vectors are given relative to a fixed origin O.]

A spider is modelled as a particle P moving on a horizontal floor. The floor is represented by the rectangle R, shown below, defined by 0 less or equal than x less or equal than 12 and 0 less or equal than y less or equal than 8, where the units are metres and the origin O is a corner of the room.

Rectangular room diagram, 12m horizontally by 8m vertically. A spider is at the bottom-left corner with horizontal 'i' and vertical 'j' vectors shown.

At time t seconds after P emerges from O, where t greater or equal than 0, the acceleration of P, bold a space straight m space straight s to the power of negative 2 end exponent, is given by

bold a equals left parenthesis 0.2 t right parenthesis bold i plus left parenthesis 0.4 t right parenthesis bold j

The velocity of P at time t seconds is bold v space straight m space straight s to the power of negative 1 end exponent.

Given that:

  • the bold i component of bold v when t equals 3 is twice the bold i component of bold v when t equals 2,

  • and the bold j component of bold v when t equals 3 is three times the bold j component of bold v when t equals 1.

Find an expression for bold v in terms of t.

4b
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4 marks

Determine whether P is within the region R when t equals 6.

5a
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3 marks

The position vectors in the x-y plane of two particles, A and B, at time t, left parenthesis t space greater or equal than space 0 right parenthesis are given by

 bold r subscript bold A equals left parenthesis 3 e to the power of negative 0.15 t end exponent right parenthesis bold i plus left parenthesis 4 e to the power of 0.1 t end exponent right parenthesis bold j

bold r subscript bold B equals left parenthesis negative 3 e to the power of negative 0.15 t end exponent right parenthesis bold i plus left parenthesis 4 e to the power of 0.1 t end exponent right parenthesis bold j

(i) Write down the initial position of both particles.

(ii) Briefly explain what happens to the position of both particles for very high values of t.

5b
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2 marks

(i) Find the velocity of particle A in terms of t.

(ii) Hence write down the velocity of particle B in terms of t.

5c
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4 marks

(i) On the same diagram sketch the graphs of y against x for both rA and  rB.

(ii) Using your graph, and without doing any calculations explain why for all values of t,

open vertical bar bold r subscript bold A close vertical bar space equals space open vertical bar bold r subscript bold B close vertical bar space space and space space open vertical bar bold v subscript bold A close vertical bar space equals space open vertical bar bold v subscript bold B close vertical bar