Differentiating Inverse Functions (DP IB Analysis & Approaches (AA)): Revision Note
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Differentiating inverse functions
What is meant by an inverse function?
Some functions are easier to handle with
(rather than
) as the subject
i.e. in the form
This can be particularly true when dealing with inverse functions
If
the inverse would be written as
Finding
can be awkward
But a function and its inverse 'cancel' each other
This means
So you can write
instead
This expresses the same relationship between
and
as
does
How do I differentiate inverse functions?
With
it is easier to differentiate “
with respect to
” rather than “
with respect to
”
I.e. to find
rather than
Note that
will be in terms of
STEP 1
For the function, the inverse will be
Rewrite
as
E.g. Find an expression in terms of
for the derivative
of
, where
STEP 2
Fromfind
STEP 3
Findusing
(this will usually be in terms of
)
This can be used to find the gradient of the curve
at a given point
Substitute the
-coordinate of the point into your expression for
If the
-coordinate is not given, you should be able to work it out from the original function and
-coordinate
E.g. for the function used above, find the gradient of
at the point where
You need to know the value of
Substitute
into the expression for
Examiner Tips and Tricks
With 's and
's everywhere this can soon get confusing! Be clear about the key information and steps, and set your working out accordingly:
The original function,
Its inverse,
Rewriting the inverse,
Finding
first, then finding its reciprocal for
Your GDC can help when numerical derivatives (gradients) are required.
Worked Example
a) Let . Find the gradient of the curve
at the point where
.

b) By considering , show that the derivative of
is
.

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