Modulus Equations & Inequalities (DP IB Analysis & Approaches (AA)): Revision Note

Lucy Kirkham

Written by: Lucy Kirkham

Reviewed by: Mark Curtis

Updated on

Modulus equations

How do I solve modulus equations graphically?

  • To solve vertical line f open parentheses x close parentheses vertical line equals g open parentheses x close parentheses (or vertical line f open parentheses x close parentheses vertical line equals vertical line g open parentheses x close parentheses vertical line) graphically

    • Draw y equals vertical line f open parentheses x close parentheses vertical line and y equals g open parentheses x close parentheses (or y equals vertical line g open parentheses x close parentheses vertical line) into your GDC

      • Find the x-coordinates of the points of intersection

Three graphs show intersections of modulus functions with linear and quadratic equations, indicating solutions at their points of intersection.

How do I solve modulus equations using algebra?

  • To solve either vertical line f open parentheses x close parentheses vertical line equals g open parentheses x close parentheses or vertical line f open parentheses x close parentheses vertical line equals vertical line g open parentheses x close parentheses vertical line using algebra, the process is the same:

    • split into two equations

      • f open parentheses x close parentheses equals g open parentheses x close parentheses

      • f open parentheses x close parentheses equals negative g open parentheses x close parentheses

    • Solve both equations

    • Check that the solutions work in the original equation

  • e.g. vertical line x minus 2 vertical line equals 2 x minus 3 splits into x minus 2 equals 2 x minus 3 and x minus 2 equals negative open parentheses 2 x minus 3 close parentheses

    • the first equation gives x equals 1

    • but x equals 1 is not a solution to vertical line x minus 2 vertical line equals 2 x minus 3

      • as vertical line left parenthesis 1 right parenthesis minus 2 vertical line equals 1 and 2 left parenthesis 1 right parenthesis minus 3 equals negative 1

    • the second equation gives x equals 5 over 3

      • which does satisfy vertical line x minus 2 vertical line equals 2 x minus 3 so is the solution

  • A sketch can help, even when solving algebraically

Graph solving the equation |2x-4| = |x-1|, with labelled steps showing graph sketch, intersections, and solutions for x=5/3 and x=3.

Worked Example

Solve

(a) stretchy vertical line fraction numerator 2 x plus 3 over denominator 2 minus x end fraction stretchy vertical line equals 5

2-8-3-ib-aa-hl-modulus-equation-a-we-solution

(b) open vertical bar 3 x minus 1 close vertical bar equals 5 x minus 11.

2-8-3-ib-aa-hl-modulus-equation-b-we-solution

Modulus inequalities

How do I solve modulus inequalities?

  • To solve modulus inequalities

    • first solve the modulus equation

      • by replacing the inequality sign with =

    • then use a graphical method to find the intervals of x that satisfy the inequality

  • To solve G subscript 1 less or equal than G subscript 2, G subscript 1 greater or equal than G subscript 2, G subscript 1 less than G subscript 2 or G subscript 1 greater than G subscript 2 where

    • G subscript 1 is graph 1

    • G subscript 2 is graph 2

    • STEP 1
      Sketch G subscript 1 and G subscript 2

    • STEP 2
      Locate the x-coordinates of the points of intersection

      • these would be x-axis intercepts if G subscript 2 equals 0

    • STEP 3
      Determine which part(s) of the graph(s) satisfy the inequality

      • G subscript 1 less or equal than G subscript 2 or G subscript 1 less than G subscript 2are where graph 1 is below than graph 2

      • G subscript 1 greater or equal than G subscript 2 or G subscript 1 greater than G subscript 2 are where graph 1 is above than graph 2

    • STEP 4
      Write the range of values of x for these regions

      • using strict inequalities if G subscript 1 less than G subscript 2 or G subscript 1 greater than G subscript 2

      • or 'equal to' inequalities if G subscript 1 less or equal than G subscript 2 or G subscript 1 greater or equal than G subscript 2

  • An alternative method is to use a sign table

    • e.g. where you substitute a numerical value from each of the possible intervals of x into the original inequality

      • The solutions are the regions for which the original inequality is true

Steps to solve a more complicated modulus equation

Worked Example

Solve the following inequalities.

(a) vertical line 2 x minus 1 vertical line less than 4

2-8-3-ib-aa-hl-modulus-inequality-a-we-solution

(b) open vertical bar x plus 1 close vertical bar less than open vertical bar 2 x plus 3 close vertical bar

K-a4iR1J_2-8-3-ib-aa-hl-modulus-inequality-b-we-solution

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Lucy Kirkham

Author: Lucy Kirkham

Expertise: Head of Content Creation

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.