Integration by Substitution (DP IB Analysis & Approaches (AA)): Revision Note

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Integration by Substitution

What is integration by substitution?

  • Integration by substitution is used when an integrand where reverse chain rule is either not obvious or is not spotted

    • in the latter case it is like a “back-up” method for reverse chain rule

How do I use integration by substitution?

  • For instances where the substitution is not obvious it will be given in a question

    • e.g.  Find integral subscript blank superscript blank cot space x space d x using the substitution u equals sin space x

  • Substitutions are usually of the form u equals g left parenthesis x right parenthesis

    • in some cases u squared equals g left parenthesis x right parenthesis and other variations are more convenient

      • as these would not be obvious, they would be given in a question

    • if need be, this can be rearranged to find x in terms of u

  • Integration by substitution then involves rewriting the integral, including “straight d x” in terms of u
    STEP 1
    Name the integral to save rewriting it later
    Identify the given substitution u equals g left parenthesis x right parenthesis

    STEP 2
    Find fraction numerator straight d u over denominator straight d x end fraction and rearrange into the form f left parenthesis u right parenthesis space straight d u equals g left parenthesis x right parenthesis space straight d x such that (some of) the integral can be rewritten in terms of u

    STEP 3
    If limits are involved, use u equals g left parenthesis x right parenthesis to change them from x values to u values 

    STEP 4
    Rewrite the integral so everything is in terms of u rather than x
    This is the step when it may become apparent that x is needed in terms of u

    STEP 5
    Integrate with respect to u and either rewrite in terms of x or apply the limits using their u values

  • For quotients the substitution usually involves the denominator

  • It may be necessary to use ‘adjust and compensate’ to deal with any coefficients in the integrand

  • Although fraction numerator straight d u over denominator straight d x end fraction can be treated like a fraction it should be appreciated that this is a ‘shortcut’ and the maths behind it is beyond the scope of the IB course

Examiner Tips and Tricks

  • If a substitution is not given in a question, it is usually because it is obvious

    • If you can't see anything obvious, or you find that your choice of substitution doesn't reduce the integrand to something easy to integrate, consider that it may not be a substitution question

Worked Example

Use the substitution u equals open parentheses 1 plus 2 x close parentheses to evaluate integral subscript 0 superscript 1 x open parentheses 1 plus 2 x close parentheses to the power of 7 space end exponent d x.

5-9-2-ib-hl-aa-only-we1-soltn

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